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Difficult Time equation
This is my first post so hello everyone and thankyou in advance for any assistance you can provide. The diffuclty I am having is as follows: I have a spreadsheet with two times 8:45 9:45 I need to find the difference in the two times as a decimal but as a fraction of an hour.. for thesee times the answer I need is 0.25 not 0.15. Can anyone help? -- bcbjork ------------------------------------------------------------------------ bcbjork's Profile: http://www.excelforum.com/member.php...o&userid=26665 View this thread: http://www.excelforum.com/showthread...hreadid=399403 |
(A1-B1)*24
format as general Mangesh "bcbjork" wrote in message ... This is my first post so hello everyone and thankyou in advance for any assistance you can provide. The diffuclty I am having is as follows: I have a spreadsheet with two times 8:45 9:45 I need to find the difference in the two times as a decimal but as a fraction of an hour.. for thesee times the answer I need is 0.25 not 0.15. Can anyone help? -- bcbjork ------------------------------------------------------------------------ bcbjork's Profile: http://www.excelforum.com/member.php...o&userid=26665 View this thread: http://www.excelforum.com/showthread...hreadid=399403 |
Time is stored as a fraction of a day, so just multiply by 24 to get decimal
time. In your case =(B1-A1)*24 although I get 1, not .25 -- HTH RP (remove nothere from the email address if mailing direct) "bcbjork" wrote in message ... This is my first post so hello everyone and thankyou in advance for any assistance you can provide. The diffuclty I am having is as follows: I have a spreadsheet with two times 8:45 9:45 I need to find the difference in the two times as a decimal but as a fraction of an hour.. for thesee times the answer I need is 0.25 not 0.15. Can anyone help? -- bcbjork ------------------------------------------------------------------------ bcbjork's Profile: http://www.excelforum.com/member.php...o&userid=26665 View this thread: http://www.excelforum.com/showthread...hreadid=399403 |
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