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Copying formulas with mixed references
I want to fill down a formula like this
=(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
Change your first formula to
=(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
Can you explain the 1+(a3)/100 so I can use this in other formulas? I'm not
sure what the a3 is. Thanks! "Duke Carey" wrote: Change your first formula to =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
A3 is refering to cell a3
row(a3) = 3 as row a3 is in row 3 Therefore 1+a3/100 = 1.03 HTH Andi "TMcMillin" wrote in message ... Can you explain the 1+(a3)/100 so I can use this in other formulas? I'm not sure what the a3 is. Thanks! "Duke Carey" wrote: Change your first formula to =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
It's actually 1+ROW(A3)/100
ROW(A3) returns the #3, and dividing it by 100 & adding it to the #1 gives you the 1.03 referenced in your original formula. Since ROW(A3) uses a relative reference, as you copy it down the column you increment the 1.03 to 1.04, 1.05, 1.06, etc. "TMcMillin" wrote: Can you explain the 1+(a3)/100 so I can use this in other formulas? I'm not sure what the a3 is. Thanks! "Duke Carey" wrote: Change your first formula to =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
OK so it doesn't matter if there is anything in A3, A4, A5 etc.?
"Duke Carey" wrote: It's actually 1+ROW(A3)/100 ROW(A3) returns the #3, and dividing it by 100 & adding it to the #1 gives you the 1.03 referenced in your original formula. Since ROW(A3) uses a relative reference, as you copy it down the column you increment the 1.03 to 1.04, 1.05, 1.06, etc. "TMcMillin" wrote: Can you explain the 1+(a3)/100 so I can use this in other formulas? I'm not sure what the a3 is. Thanks! "Duke Carey" wrote: Change your first formula to =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
Correct. Its contents (or lack of contents) are totally irrelevant.
"TMcMillin" wrote: OK so it doesn't matter if there is anything in A3, A4, A5 etc.? "Duke Carey" wrote: It's actually 1+ROW(A3)/100 ROW(A3) returns the #3, and dividing it by 100 & adding it to the #1 gives you the 1.03 referenced in your original formula. Since ROW(A3) uses a relative reference, as you copy it down the column you increment the 1.03 to 1.04, 1.05, 1.06, etc. "TMcMillin" wrote: Can you explain the 1+(a3)/100 so I can use this in other formulas? I'm not sure what the a3 is. Thanks! "Duke Carey" wrote: Change your first formula to =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*(1+ro w(a3)/100)) and copy that down "TMcMillin" wrote: I want to fill down a formula like this =(($C$73*$G$81)+(($C$76*0.89)*$F$81))*($C$87*1.03) where b=with the absolute cell references, but have the 1.03 change incrementally (1.03, 1.04, 1.05 etc.). I can't find anything in the help on this - does anyone know how to do this? Thanks |
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