Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Try

=ROUND((A1*100000)/25,0)*25/100000


"chartasap" wrote in message
...
Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) --
take
last two digits '38' compared to .00025. If it's less than .00025 then
those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Barb,

It works great however, when i used the function below for values such as
1.52866, 1.52821, 1.52775, 1.52730 etc. the result is not correct. Any idea
why it won't work on these?

"Barb Reinhardt" wrote:

Try

=ROUND((A1*100000)/25,0)*25/100000


"chartasap" wrote in message
...
Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) --
take
last two digits '38' compared to .00025. If it's less than .00025 then
those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Because it is rounding to the nearest .00025, not as per your actual criteria.

HTH,
Bernie
MS Excel MVP


It works great however, when i used the function below for values such as
1.52866, 1.52821, 1.52775, 1.52730 etc. the result is not correct. Any idea
why it won't work on these?

For a value in cell A1:

=IF(A1*1000-INT(A1*1000)=0.25,INT(A1*1000)/1000+0.0005,INT(A1*1000)/1000)

You didn't say what to do it it were equal to 25, so I chose =, but you can change that.

HTH,
Bernie
MS Excel MVP


"chartasap" wrote in message
...
Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Thank you Bernie...i tried this formula and it works wonderfully. Thank you
for your time.

"Bernie Deitrick" wrote:

For a value in cell A1:

=IF(A1*1000-INT(A1*1000)=0.25,INT(A1*1000)/1000+0.0005,INT(A1*1000)/1000)

You didn't say what to do it it were equal to 25, so I chose =, but you can change that.

HTH,
Bernie
MS Excel MVP


"chartasap" wrote in message
...
Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

One more alternative

=TRUNC(A1,3)+0.0005*(MID(A1,SEARCH(".",A1)+4,2)25 )

"chartasap" wrote:

Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Thank you Duke...this is definitely another way i can go.

"Duke Carey" wrote:

One more alternative

=TRUNC(A1,3)+0.0005*(MID(A1,SEARCH(".",A1)+4,2)25 )

"chartasap" wrote:

Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!

Oops - make that

=TRUNC(A1,3)+0.0005*(VALUE(MID(A1,SEARCH(".",A1)+4 ,2))25)

"chartasap" wrote:

Hello,

would someone be able to help me build a function that would take the last
two digits in a value compare it then return a '0' or '5'. For example,

Column A
1.53138 (this value is the result of a formula =sum(c6/5873.05-c3) -- take
last two digits '38' compared to .00025. If it's less than .00025 then those
two last digits should become a 0 if greater than .00025 then it should be
'5'.
RESULT
1.5315
---------
1.53047 -- 1.5305
1.53002 -- 1.5300
1.52957 -- 1.5295

Thank you!