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Return Consecutive Values
Hi All,
I am using the formula below to return one specific value referenced in an input cell B1: =IF((COUNTIF(INDEX(Stock,ROW()-ROW(Stock)+1,0),B$1))=1,B$1,"") How might a more suitable formula or the above formula be expanded to find pairs of consecutive values in ascending order in a Dynamic Defined Range “Stock” ( 7 Columns B-H and many Rows), and return the two consecutive values on the same Row in separate columns (side by side) on a new sheet. Sample Data – Defined Dynamic Range “Stock”: COL B C D E F G H ROW19 70 72 87 88 89 92 95 ROW20 73 74 78 80 81 83 84 In case data is misaligned: Row 19, Column B, C, D, E, F, G, and H houses 70, 72, 87, 88, 89, 92 and 95 respectively. Row 20, Column C, D, E, F, G, and H houses 73 74, 78, 80, 81, 83 and 84 respectively. New Worksheet (for Expected Results) ROW1 Input cells: B$1, C$1, D$1, E$1, F$1, G$1, H$1, I$1, J$1, K$1 80 81 82 83 84 85 86 87 88 89 In case data is misaligned: cell B1, C1, D1, E1, F1, G1, H1, I1, J1 and K1 house 80, 81, 82, 83, 84, 85, 86, 87, 88 and 89 Expected Results: COL B C D E F G H I J K ROW19 88 89 ROW20 83 84 Row19 – 88 and 89 returned in columns J and K Row20 – 83 and 84 returned in columns E and F Kind Regards, Sam -- Message posted via http://www.officekb.com |
I haven't fully tested it, but see if this will do...
Assuming that Sheet1 contains your source data, and Sheet2 contains your expected results... 1) If there will always be at least one set of consecutive pairs... Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1 )))=B$1,SUM(B$1,A19),IF(COUNTIF($A19:A19,"0")=1,S UM(A19,1),"")) ....confirmed with CONTROL+SHIFT+ENTER. 2) If there may not be at least one consecutive pair... Sheet2!B19, copied across and down: =IF(1-ISNA(MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1))),IF(INDEX(She et1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1)))=B$1,SUM(B $1,A19),IF(COUNTIF($A19:A19,"0")=1,SUM(A19,1),"") ),"") ....confirmed with CONTROL+SHIFT+ENTER. Hope this helps! In article , "Sam via OfficeKB.com" wrote: Hi All, I am using the formula below to return one specific value referenced in an input cell B1: =IF((COUNTIF(INDEX(Stock,ROW()-ROW(Stock)+1,0),B$1))=1,B$1,"") How might a more suitable formula or the above formula be expanded to find pairs of consecutive values in ascending order in a Dynamic Defined Range “Stock” ( 7 Columns B-H and many Rows), and return the two consecutive values on the same Row in separate columns (side by side) on a new sheet. Sample Data – Defined Dynamic Range “Stock”: COL B C D E F G H ROW19 70 72 87 88 89 92 95 ROW20 73 74 78 80 81 83 84 In case data is misaligned: Row 19, Column B, C, D, E, F, G, and H houses 70, 72, 87, 88, 89, 92 and 95 respectively. Row 20, Column C, D, E, F, G, and H houses 73 74, 78, 80, 81, 83 and 84 respectively. New Worksheet (for Expected Results) ROW1 Input cells: B$1, C$1, D$1, E$1, F$1, G$1, H$1, I$1, J$1, K$1 80 81 82 83 84 85 86 87 88 89 In case data is misaligned: cell B1, C1, D1, E1, F1, G1, H1, I1, J1 and K1 house 80, 81, 82, 83, 84, 85, 86, 87, 88 and 89 Expected Results: COL B C D E F G H I J K ROW19 88 89 ROW20 83 84 Row19 – 88 and 89 returned in columns J and K Row20 – 83 and 84 returned in columns E and F Kind Regards, Sam |
I forgot to mention that this will only work if Column A on Sheet2
(starting at A19 onwards) is either blank or contains text values. Hope this helps! In article , Domenic wrote: I haven't fully tested it, but see if this will do... Assuming that Sheet1 contains your source data, and Sheet2 contains your expected results... 1) If there will always be at least one set of consecutive pairs... Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1 )))=B$1,SUM(B$1,A19),IF(COUNTIF($A19:A19,"0")=1,S UM(A19,1),"")) ...confirmed with CONTROL+SHIFT+ENTER. 2) If there may not be at least one consecutive pair... Sheet2!B19, copied across and down: =IF(1-ISNA(MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1))),IF(INDEX(She et1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1)))=B$1,SUM(B $1,A19),IF(COUNTIF($A19:A19,"0")=1,SUM(A19,1),"") ),"") ...confirmed with CONTROL+SHIFT+ENTER. Hope this helps! In article , "Sam via OfficeKB.com" wrote: Hi All, I am using the formula below to return one specific value referenced in an input cell B1: =IF((COUNTIF(INDEX(Stock,ROW()-ROW(Stock)+1,0),B$1))=1,B$1,"") How might a more suitable formula or the above formula be expanded to find pairs of consecutive values in ascending order in a Dynamic Defined Range “Stock” ( 7 Columns B-H and many Rows), and return the two consecutive values on the same Row in separate columns (side by side) on a new sheet. Sample Data – Defined Dynamic Range “Stock”: COL B C D E F G H ROW19 70 72 87 88 89 92 95 ROW20 73 74 78 80 81 83 84 In case data is misaligned: Row 19, Column B, C, D, E, F, G, and H houses 70, 72, 87, 88, 89, 92 and 95 respectively. Row 20, Column C, D, E, F, G, and H houses 73 74, 78, 80, 81, 83 and 84 respectively. New Worksheet (for Expected Results) ROW1 Input cells: B$1, C$1, D$1, E$1, F$1, G$1, H$1, I$1, J$1, K$1 80 81 82 83 84 85 86 87 88 89 In case data is misaligned: cell B1, C1, D1, E1, F1, G1, H1, I1, J1 and K1 house 80, 81, 82, 83, 84, 85, 86, 87, 88 and 89 Expected Results: COL B C D E F G H I J K ROW19 88 89 ROW20 83 84 Row19 – 88 and 89 returned in columns J and K Row20 – 83 and 84 returned in columns E and F Kind Regards, Sam |
Hi Domenic!
Change the values in Sheet1 row 19 to: 85:91 Sheet2 row 19 = "" This is a real challenge! Biff "Domenic" wrote in message ... I haven't fully tested it, but see if this will do... Assuming that Sheet1 contains your source data, and Sheet2 contains your expected results... 1) If there will always be at least one set of consecutive pairs... Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1 )))=B$1,SUM(B$1,A19),IF(COUNTIF($A19:A19,"0")=1,S UM(A19,1),"")) ...confirmed with CONTROL+SHIFT+ENTER. 2) If there may not be at least one consecutive pair... Sheet2!B19, copied across and down: =IF(1-ISNA(MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1))),IF(INDEX(She et1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1)))=B$1,SUM(B $1,A19),IF(COUNTIF($A19:A19,"0")=1,SUM(A19,1),"") ),"") ...confirmed with CONTROL+SHIFT+ENTER. Hope this helps! In article , "Sam via OfficeKB.com" wrote: Hi All, I am using the formula below to return one specific value referenced in an input cell B1: =IF((COUNTIF(INDEX(Stock,ROW()-ROW(Stock)+1,0),B$1))=1,B$1,"") How might a more suitable formula or the above formula be expanded to find pairs of consecutive values in ascending order in a Dynamic Defined Range "Stock" ( 7 Columns B-H and many Rows), and return the two consecutive values on the same Row in separate columns (side by side) on a new sheet. Sample Data - Defined Dynamic Range "Stock": COL B C D E F G H ROW19 70 72 87 88 89 92 95 ROW20 73 74 78 80 81 83 84 In case data is misaligned: Row 19, Column B, C, D, E, F, G, and H houses 70, 72, 87, 88, 89, 92 and 95 respectively. Row 20, Column C, D, E, F, G, and H houses 73 74, 78, 80, 81, 83 and 84 respectively. New Worksheet (for Expected Results) ROW1 Input cells: B$1, C$1, D$1, E$1, F$1, G$1, H$1, I$1, J$1, K$1 80 81 82 83 84 85 86 87 88 89 In case data is misaligned: cell B1, C1, D1, E1, F1, G1, H1, I1, J1 and K1 house 80, 81, 82, 83, 84, 85, 86, 87, 88 and 89 Expected Results: COL B C D E F G H I J K ROW19 88 89 ROW20 83 84 Row19 - 88 and 89 returned in columns J and K Row20 - 83 and 84 returned in columns E and F Kind Regards, Sam |
Hi Biff!
In article , "Biff" wrote: Change the values in Sheet1 row 19 to: 85:91 Sheet2 row 19 = "" Thanks for catching it! Much appreciated! This is a real challenge! Most definitely! And I do like a challenge! :) Here's my second attempt at a solution. This time I hope I've covered all the bases. I guess we'll see... :) Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/((Sheet1!$C19:$H19-Sheet1!$B19:$G19= 1)*(Sheet1!$B19:$G19=80)*(Sheet1!$C19:$H19<=89))) )=B$1,SUM(B$1,A19),IF(C OUNTIF($A19:A19,"0")=1,SUM(A19,1),"")) ....confirmed with CONTROL+SHIFT+ENTER. Note that the same caution applies here. Column A, starting at A19, must either be blank or contain text values. Hope this helps! |
Hi Domenic,
Thank you for assistance and ongoing help. I'm using your suggested 2nd option below - the formula did not return all the instances of expected consecutive values. I've just picked up on Biff's posting and your amended version - so I'll post back shortly. Thanks Sam ------------------------------------------------------------------------- 2) If there may not be at least one consecutive pair... Sheet2!B19, copied across and down: =IF(1-ISNA(MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1))),IF(INDEX(She et1!$B19:$G19,MATCH(2,1/(Sheet1!$C19:$H19-Sheet1!$B19:$G19=1)))=B$1,SUM(B $1,A19),IF(COUNTIF($A19:A19,"0")=1,SUM(A19,1),"") ),"") ....confirmed with CONTROL+SHIFT+ENTER. -- Message posted via http://www.officekb.com |
Hi Domenic & Biff,
I've implemented the formula below across the first two columns ("B" and "C") in Sheet2 but it produces the N/A error on some rows and unfortunately, still only returns the same 4 consecutive values that the previous formula returned. I should see 9 values in columns "B" and "C" that are consecutive. Column "A" is empty and remembered to enter with CONTROL+SHIFT+ENTER. Any further ideas and help much appreciated. Thanks Sam ----------------------------------------------------------------------- Here's my second attempt at a solution. This time I hope I've covered all the bases. I guess we'll see... :) Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/((Sheet1!$C19:$H19-Sheet1!$B19:$G19= 1)*(Sheet1!$B19:$G19=80)*(Sheet1!$C19:$H19<=89))) )=B$1,SUM(B$1,A19),IF(C OUNTIF($A19:A19,"0")=1,SUM(A19,1),"")) ....confirmed with CONTROL+SHIFT+ENTER. Note that the same caution applies here. Column A, starting at A19, must either be blank or contain text values. -- Message posted via http://www.officekb.com |
Hi Sam!
Maybe I've misunderstood what it is you're looking for. Let's take a look at the following example... Sheet1!B19:H24 contains... 88 89 90 91 92 93 94 75 76 77 78 79 80 81 70 78 79 84 85 90 92 75 80 81 85 87 88 92 74 75 76 77 78 79 80 89 90 91 92 93 94 95 Sheet2!B1:K1 contains.. 80 81 82 83 84 85 86 87 88 89 Sheet2!B19:K24 would contain the following results... 0 0 0 0 0 0 0 0 88 89 80 81 0 0 0 0 0 0 0 0 0 0 0 0 84 85 0 0 0 0 0 0 0 0 0 0 0 87 88 0 #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A #N/A Note that the 0's are only there to help differentiate the columns, and the #N/A values can be dealt with by either hiding them using Conditional Formatting or modifying the formula to eliminate them. The #N/A values are returned when there are no consecutive pairs or, if they exist, don't fall within the range specified by the input cells. Now, are these the results your looking for? If not, can you supply the correct results? In article , "Sam via OfficeKB.com" wrote: Hi Domenic & Biff, I've implemented the formula below across the first two columns ("B" and "C") in Sheet2 but it produces the N/A error on some rows and unfortunately, still only returns the same 4 consecutive values that the previous formula returned. I should see 9 values in columns "B" and "C" that are consecutive. Column "A" is empty and remembered to enter with CONTROL+SHIFT+ENTER. Any further ideas and help much appreciated. Thanks Sam ----------------------------------------------------------------------- Here's my second attempt at a solution. This time I hope I've covered all the bases. I guess we'll see... :) Sheet2!B19, copied across and down: =IF(INDEX(Sheet1!$B19:$G19,MATCH(2,1/((Sheet1!$C19:$H19-Sheet1!$B19:$G19= 1)*(Sheet1!$B19:$G19=80)*(Sheet1!$C19:$H19<=89))) )=B$1,SUM(B$1,A19),IF(C OUNTIF($A19:A19,"0")=1,SUM(A19,1),"")) ...confirmed with CONTROL+SHIFT+ENTER. Note that the same caution applies here. Column A, starting at A19, must either be blank or contain text values. |
Hi Domenic,
Yes, those are the results I'm looking for. However, I'm not sure why it is not returning all the consecutive values on the 2nd Sheet for the first two columns. I should see 9 values in columns "B" and "C" that are consecutive. Also as suggested, would appreciate it if you could eliminate the N/A values by modyfying the formula. Thanks Sam -- Message posted via http://www.officekb.com |
In article ,
"Sam via OfficeKB.com" wrote: However, I'm not sure why it is not returning all the consecutive values on the 2nd Sheet for the first two columns. I should see 9 values in columns "B" and "C" that are consecutive. Would you like me to take a look at a sample of your file and see if I can pinpoint the problem? If so, you can email me at . Otherwise, I can email you a sample file. |
Hi Domenic,
I would appreciate having a look at your sample file. Email sam_518 AT hotmail DOT co DOT uk Thanks Sam -- Message posted via http://www.officekb.com |
Hi Sam,
I've just emailed you my sample file. Let me know how it works out. Cheers! In article , "Sam via OfficeKB.com" wrote: Hi Domenic, I would appreciate having a look at your sample file. Email sam_518 AT hotmail DOT co DOT uk Thanks Sam |
Hi Domenic,
Thank you very much for sample file. Your interpretation of what I said is perfect and the file does what I requested. However, as usual, I did not fully understand what I actually wanted to see visually on the new worksheet - Sheet2. I still require the consecutive values to be returned to Sheet2 by using the input values on Row 1 of Sheet2 but I need all consecutive values returned by individual pairs and not by individual numbers. Using the current formula I would get 82-83-84-85-86-87-88. There are instances where a Row may contain all consecutive values as below, and what I actually wish to see is all instances for example of 82-83, 83-84, 84-85, 85-86, 86-87 and 87-88. I'm not sure whether having two columns for each input value would help. Is there a way to achieve the above? Sheet1!B19:H19 contains... 82 83 84 85 86 87 88 Sheet2!B1:K1 contains.. 80 81 82 83 84 85 86 87 88 89 Thanks Sam -- Message posted via http://www.officekb.com |
Assumptions:
1) Each row in the source table (Sheet1) contains unique values. 2) Each row in the source table contains values in ascending order. Formula: B19, copied down and across to J19: =IF(ISNUMBER(MATCH(B$1,Sheet1!$B19:$H19,0)),IF(MAT CH(B$1,Sheet1!$B19:$H19 ,0)<7,IF(INDEX(Sheet1!$B19:$H19,MATCH(B$1,Sheet1!$ B19:$H19,0)+1)=B$1+1,B$ 1&"-"&B$1+1,""),""),"") Hope this helps! In article , "Sam via OfficeKB.com" wrote: Hi Domenic, Thank you very much for sample file. Your interpretation of what I said is perfect and the file does what I requested. However, as usual, I did not fully understand what I actually wanted to see visually on the new worksheet - Sheet2. I still require the consecutive values to be returned to Sheet2 by using the input values on Row 1 of Sheet2 but I need all consecutive values returned by individual pairs and not by individual numbers. Using the current formula I would get 82-83-84-85-86-87-88. There are instances where a Row may contain all consecutive values as below, and what I actually wish to see is all instances for example of 82-83, 83-84, 84-85, 85-86, 86-87 and 87-88. I'm not sure whether having two columns for each input value would help. Is there a way to achieve the above? Sheet1!B19:H19 contains... 82 83 84 85 86 87 88 Sheet2!B1:K1 contains.. 80 81 82 83 84 85 86 87 88 89 Thanks Sam |
Hi Domenic,
Thank you very much for all your help. The formula works great - brilliant! Thanks Sam -- Message posted via http://www.officekb.com |
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