Unexpected result
 

Hi Folks!

Can someone explain the result I'm getting:

A1 = 11
A2 = 12
A3 = 13
A4 = 14
A5 = 15

A10 = empty

I want the formula to extract the values in A1:A5 IF A10 = X

Formula: (array entered)

=INDEX(A$1:A$5,SMALL(IF(A$10="X",ROW($1:$5)),ROW(1 :1)))

Copied down 5 cells returns:

11
#NUM!
#NUM!
#NUM!
#NUM!

I should get #NUM! in every cell.

Here's where I don't understand the result of the first cell return of
11....

Evaluating the formula and stepping through:

SMALL(FALSE,{1}) evaluates to SMALL(0,1) = 0

So, =INDEX(A$1:A$5,0)

Returns the value in the first position in the array A1:A5, 11.

=INDEX(A$1:A$5,1) also returns the value in the first position in the array
A1:A5, 11.

I would think that there is no zero position in the array and the formula
should error.

I know that the above #NUM! errors are being generated by the SMALL function
but shouldn't INDEX also generate an error based on position zero?

I'm confiussed on this!

Thanks

Biff

Hi Biff,

Try entering the following in a cell
=INDEX(A1:A5,0)

Case 1: as an array formula, and
Case 2: as a simple formula

In the first case, it returns 11 (and if you drag down, the subsequent
numbers). In the second case, it returns #VALUE and the same for
dragging down.

In you main formula, the above part is treated as an array formula and
so you get 11 in the first case, whereas in the subsequent cases
instead of 0 you get #NUM as the second argument for the index function
and so you get #NUM

Mangesh


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Hi Biff,

your question and the solution aaray did not match. Why don't you
simply use:
=IF($A$10="X",A1,"") and copy down
or
=IF($A$10="X",A1:A5,"") as an array formula by selecting all the five
cells in the column.

Mangesh


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=INDEX(A1:A5,0)

which is identical to the full version:

=INDEX(A1:A5,0,1)

means all of the rows of A1:A5.

The formula cell will house the result given your sample:

={11;12;13;14;15}

with the topleft cell displaying.

The foregoing also holds for:

=INDEX(A1:A5,{0})

Intermezzo: Invoke =INDEX($A$1:$A$5,0) in a cell in the same worksheet
you want to data validate as Source. That cell will show you all of the
values from A1:A5.

BTW, ROW(1:1) in

=INDEX(A$1:A$5,SMALL(IF(A$10="X",ROW($1:$5)),ROW(1 :1)))

makes the formula non-robust (therefore incorrect) against row
insertions before the formula row.

Biff wrote:
Hi Folks!

Can someone explain the result I'm getting:

A1 = 11
A2 = 12
A3 = 13
A4 = 14
A5 = 15

A10 = empty

I want the formula to extract the values in A1:A5 IF A10 = X

Formula: (array entered)

=INDEX(A$1:A$5,SMALL(IF(A$10="X",ROW($1:$5)),ROW(1 :1)))

Copied down 5 cells returns:

11
#NUM!
#NUM!
#NUM!
#NUM!

I should get #NUM! in every cell.

Here's where I don't understand the result of the first cell return of
11....

Evaluating the formula and stepping through:

SMALL(FALSE,{1}) evaluates to SMALL(0,1) = 0

So, =INDEX(A$1:A$5,0)

Returns the value in the first position in the array A1:A5, 11.

=INDEX(A$1:A$5,1) also returns the value in the first position in the array
A1:A5, 11.

I would think that there is no zero position in the array and the formula
should error.

I know that the above #NUM! errors are being generated by the SMALL function
but shouldn't INDEX also generate an error based on position zero?

I'm confiussed on this!

Thanks

Biff

Thanks for your input.

Actually, I was just "playing" around with some stuff and couldn't quite
figure out what I was seeing.

Biff

"mangesh_yadav"
wrote in message
news:mangesh_yadav.1pzm2e_1117695909.6097@excelfor um-nospam.com...

Hi Biff,

your question and the solution aaray did not match. Why don't you
simply use:
=IF($A$10="X",A1,"") and copy down
or
=IF($A$10="X",A1:A5,"") as an array formula by selecting all the five
cells in the column.

Mangesh


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mangesh_yadav
------------------------------------------------------------------------
mangesh_yadav's Profile:
http://www.excelforum.com/member.php...o&userid=10470
View this thread: http://www.excelforum.com/showthread...hreadid=375888

Ok, that makes sense!

Biff

"Aladin Akyurek" wrote in message
...
=INDEX(A1:A5,0)

which is identical to the full version:

=INDEX(A1:A5,0,1)

means all of the rows of A1:A5.

The formula cell will house the result given your sample:

={11;12;13;14;15}

with the topleft cell displaying.

The foregoing also holds for:

=INDEX(A1:A5,{0})

Intermezzo: Invoke =INDEX($A$1:$A$5,0) in a cell in the same worksheet you
want to data validate as Source. That cell will show you all of the values
from A1:A5.

BTW, ROW(1:1) in

=INDEX(A$1:A$5,SMALL(IF(A$10="X",ROW($1:$5)),ROW(1 :1)))

makes the formula non-robust (therefore incorrect) against row insertions
before the formula row.

Biff wrote:
Hi Folks!

Can someone explain the result I'm getting:

A1 = 11
A2 = 12
A3 = 13
A4 = 14
A5 = 15

A10 = empty

I want the formula to extract the values in A1:A5 IF A10 = X

Formula: (array entered)

=INDEX(A$1:A$5,SMALL(IF(A$10="X",ROW($1:$5)),ROW(1 :1)))

Copied down 5 cells returns:

11
#NUM!
#NUM!
#NUM!
#NUM!

I should get #NUM! in every cell.

Here's where I don't understand the result of the first cell return of
11....

Evaluating the formula and stepping through:

SMALL(FALSE,{1}) evaluates to SMALL(0,1) = 0

So, =INDEX(A$1:A$5,0)

Returns the value in the first position in the array A1:A5, 11.

=INDEX(A$1:A$5,1) also returns the value in the first position in the
array A1:A5, 11.

I would think that there is no zero position in the array and the formula
should error.

I know that the above #NUM! errors are being generated by the SMALL
function but shouldn't INDEX also generate an error based on position
zero?

I'm confiussed on this!

Thanks

Biff