Finding a value
 

I have this formula:

=OFFSET(INDIRECT(ADDRESS(MATCH(MAX(B1:B26),B1:B26, 0),2)),0,-1)

It looks up the value one cell left of the largest value in B1:B26,
and it works OK, but

1) Can it be done in an easier way?
2) It only works if the column starts in row 1. as Match find the row
within the array and Address demands the row in the sheet.

Jan

Finding a value
 

Try =INDEX(A1:A26,MATCH(MAX(B1:B26),B1:B26,0))
best wishes
--
Bernard Liengme
Microsoft Excel MVP
http://people.stfx.ca/bliengme

"jkrons" wrote in message
...
I have this formula:

=OFFSET(INDIRECT(ADDRESS(MATCH(MAX(B1:B26),B1:B26, 0),2)),0,-1)

It looks up the value one cell left of the largest value in B1:B26,
and it works OK, but

1) Can it be done in an easier way?
2) It only works if the column starts in row 1. as Match find the row
within the array and Address demands the row in the sheet.

Jan

Finding a value
 

Hi,

here's another way with an ARRAY formula

=INDEX(A2:A20,MATCH(MAX(B2:B20),B2:B20,0))

This is an array formula which must be entered by pressing CTRL+Shift+Enter
'and not just Enter. If you do it correctly then Excel will put curly brackets
'around the formula {}. You can't type these yourself. If you edit the formula
'you must enter it again with CTRL+Shift+Enter.

--
Mike

When competing hypotheses are otherwise equal, adopt the hypothesis that
introduces the fewest assumptions while still sufficiently answering the
question.


"jkrons" wrote:

I have this formula:

=OFFSET(INDIRECT(ADDRESS(MATCH(MAX(B1:B26),B1:B26, 0),2)),0,-1)

It looks up the value one cell left of the largest value in B1:B26,
and it works OK, but

1) Can it be done in an easier way?
2) It only works if the column starts in row 1. as Match find the row
within the array and Address demands the row in the sheet.

Jan
.

Finding a value
 

I hate to be pedantic, Mike, but the formulas we each suggested do NOT need
to be array entered.
Bernard

"Mike H" wrote in message
...
Hi,

here's another way with an ARRAY formula

=INDEX(A2:A20,MATCH(MAX(B2:B20),B2:B20,0))

This is an array formula which must be entered by pressing
CTRL+Shift+Enter
'and not just Enter. If you do it correctly then Excel will put curly
brackets
'around the formula {}. You can't type these yourself. If you edit the
formula
'you must enter it again with CTRL+Shift+Enter.

--
Mike

When competing hypotheses are otherwise equal, adopt the hypothesis that
introduces the fewest assumptions while still sufficiently answering the
question.


"jkrons" wrote:

I have this formula:

=OFFSET(INDIRECT(ADDRESS(MATCH(MAX(B1:B26),B1:B26, 0),2)),0,-1)

It looks up the value one cell left of the largest value in B1:B26,
and it works OK, but

1) Can it be done in an easier way?
2) It only works if the column starts in row 1. as Match find the row
within the array and Address demands the row in the sheet.

Jan
.

Finding a value
 

Great. Thank you both.

Jan

Bernard Liengme wrote:
I hate to be pedantic, Mike, but the formulas we each suggested do
NOT need to be array entered.
Bernard

"Mike H" wrote in message
...
Hi,

here's another way with an ARRAY formula

=INDEX(A2:A20,MATCH(MAX(B2:B20),B2:B20,0))

This is an array formula which must be entered by pressing
CTRL+Shift+Enter
'and not just Enter. If you do it correctly then Excel will put curly
brackets
'around the formula {}. You can't type these yourself. If you edit
the formula
'you must enter it again with CTRL+Shift+Enter.

--
Mike

When competing hypotheses are otherwise equal, adopt the hypothesis
that introduces the fewest assumptions while still sufficiently
answering the question.


"jkrons" wrote:

I have this formula:

=OFFSET(INDIRECT(ADDRESS(MATCH(MAX(B1:B26),B1:B26, 0),2)),0,-1)

It looks up the value one cell left of the largest value in B1:B26,
and it works OK, but

1) Can it be done in an easier way?
2) It only works if the column starts in row 1. as Match find the
row within the array and Address demands the row in the sheet.

Jan
.