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Convert variable #'s in a gen. format to a # that can be used w/ma
I have this data that is pasted to my worksheet:
Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve |
Convert variable #'s in a gen. format to a # that can be usedw/ma
Steve wrote:
I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) |
Convert variable #'s in a gen. format to a # that can be used w/ma
One way...
Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve |
Convert variable #'s in a gen. format to a # that can be used
I'm getting a #value!
A1 is where my general format data is, correct ? "Glenn" wrote: Steve wrote: I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) . |
Convert variable #'s in a gen. format to a # that can be used
I do believe the "Days" will always be present, and your formula works to
produce either the single #, tens, or hundreds, but when I use that result as a divisor, it still produces a #value! E.g. Formula result is 6(in J3).... e19/j3 = #value! "T. Valko" wrote: One way... Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve . |
Convert variable #'s in a gen. format to a # that can be used
E.g. Formula result is 6(in J3).... e19/j3 = #value!
What's in E19? When a formula like that resturns a #VALUE! error it usually means one (or possibly both) cells referenced contain TEXT. Since we know that J3 contains numeric 6 then the problem has to be with cell E19. -- Biff Microsoft Excel MVP "Steve" wrote in message ... I do believe the "Days" will always be present, and your formula works to produce either the single #, tens, or hundreds, but when I use that result as a divisor, it still produces a #value! E.g. Formula result is 6(in J3).... e19/j3 = #value! "T. Valko" wrote: One way... Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve . |
Convert variable #'s in a gen. format to a # that can be used
Yes, A1 should have "Period: 01/23/2010 to 01/29/2010 - Days: 6". You
probably have trailing spaces in your data, which could cause the #Value! error. Try this instead: B1 =--RIGHT(SUBSTITUTE(TRIM(A1)," ",REPT(" ",3)),3) Steve wrote: I'm getting a #value! A1 is where my general format data is, correct ? "Glenn" wrote: Steve wrote: I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) . |
Convert variable #'s in a gen. format to a # that can be used
This produced :6
I changed the 3's to 2's and got the 6, but I don't think my fix will account for 2 or 3 digit numbers, will it ? Same as other, taking a number in cell E19, and dividing by the resulting 6, still produces a #value! "Glenn" wrote: Yes, A1 should have "Period: 01/23/2010 to 01/29/2010 - Days: 6". You probably have trailing spaces in your data, which could cause the #Value! error. Try this instead: B1 =--RIGHT(SUBSTITUTE(TRIM(A1)," ",REPT(" ",3)),3) Steve wrote: I'm getting a #value! A1 is where my general format data is, correct ? "Glenn" wrote: Steve wrote: I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) . . |
Convert variable #'s in a gen. format to a # that can be used
E19 has a number in it. Formatted as a number.
Also, in playing around, I may have changed the formatting of J3. It is currently formatted as a number. Thanks, Steve "T. Valko" wrote: E.g. Formula result is 6(in J3).... e19/j3 = #value! What's in E19? When a formula like that resturns a #VALUE! error it usually means one (or possibly both) cells referenced contain TEXT. Since we know that J3 contains numeric 6 then the problem has to be with cell E19. -- Biff Microsoft Excel MVP "Steve" wrote in message ... I do believe the "Days" will always be present, and your formula works to produce either the single #, tens, or hundreds, but when I use that result as a divisor, it still produces a #value! E.g. Formula result is 6(in J3).... e19/j3 = #value! "T. Valko" wrote: One way... Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve . . |
Convert variable #'s in a gen. format to a # that can be used
What EXACTLY is in A1 (or whatever cell it is that you are looking at)?
Maybe try this, which assumes you are just subtracting the first date from the second date to get "Days": =MID(A1,FIND(" to ",A1)+4,11)-MID(A1,FIND(" to ",A1)-10,11) As for your other problem, put this in a blank cell and tell us what the result is: =ISNUMBER(E19) Steve wrote: This produced :6 I changed the 3's to 2's and got the 6, but I don't think my fix will account for 2 or 3 digit numbers, will it ? Same as other, taking a number in cell E19, and dividing by the resulting 6, still produces a #value! "Glenn" wrote: Yes, A1 should have "Period: 01/23/2010 to 01/29/2010 - Days: 6". You probably have trailing spaces in your data, which could cause the #Value! error. Try this instead: B1 =--RIGHT(SUBSTITUTE(TRIM(A1)," ",REPT(" ",3)),3) Steve wrote: I'm getting a #value! A1 is where my general format data is, correct ? "Glenn" wrote: Steve wrote: I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) . . |
Convert variable #'s in a gen. format to a # that can be used
Glenn wrote:
Maybe try this, which assumes you are just subtracting the first date from the second date to get "Days": =MID(A1,FIND(" to ",A1)+4,11)-MID(A1,FIND(" to ",A1)-10,11) Actually, both 11's should be 10's. |
Convert variable #'s in a gen. format to a # that can be used
This in the cell
Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. "Glenn" wrote: What EXACTLY is in A1 (or whatever cell it is that you are looking at)? Maybe try this, which assumes you are just subtracting the first date from the second date to get "Days": =MID(A1,FIND(" to ",A1)+4,11)-MID(A1,FIND(" to ",A1)-10,11) As for your other problem, put this in a blank cell and tell us what the result is: =ISNUMBER(E19) Steve wrote: This produced :6 I changed the 3's to 2's and got the 6, but I don't think my fix will account for 2 or 3 digit numbers, will it ? Same as other, taking a number in cell E19, and dividing by the resulting 6, still produces a #value! "Glenn" wrote: Yes, A1 should have "Period: 01/23/2010 to 01/29/2010 - Days: 6". You probably have trailing spaces in your data, which could cause the #Value! error. Try this instead: B1 =--RIGHT(SUBSTITUTE(TRIM(A1)," ",REPT(" ",3)),3) Steve wrote: I'm getting a #value! A1 is where my general format data is, correct ? "Glenn" wrote: Steve wrote: I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve One way: =--TRIM(RIGHT(SUBSTITUTE(A1," ",REPT(" ",10)),10)) . . . |
Convert variable #'s in a gen. format to a # that can be used
If this string is in cell A1:
Period: 01/23/2010 to 01/29/2010 - Days: 6 What result do you get from this formula: =CODE(RIGHT(A1)) That formula should return 54. That's the character code value for the number 6. If you get a result other than 54 then that means there is some unseen whitespace character(s) at the end of the string in cell A1. -- Biff Microsoft Excel MVP "Steve" wrote in message ... E19 has a number in it. Formatted as a number. Also, in playing around, I may have changed the formatting of J3. It is currently formatted as a number. Thanks, Steve "T. Valko" wrote: E.g. Formula result is 6(in J3).... e19/j3 = #value! What's in E19? When a formula like that resturns a #VALUE! error it usually means one (or possibly both) cells referenced contain TEXT. Since we know that J3 contains numeric 6 then the problem has to be with cell E19. -- Biff Microsoft Excel MVP "Steve" wrote in message ... I do believe the "Days" will always be present, and your formula works to produce either the single #, tens, or hundreds, but when I use that result as a divisor, it still produces a #value! E.g. Formula result is 6(in J3).... e19/j3 = #value! "T. Valko" wrote: One way... Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve . . |
Convert variable #'s in a gen. format to a # that can be used
When I copy your text directly from this post to cell A3 in a blank worksheet
and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. |
Convert variable #'s in a gen. format to a # that can be used
Are you copying the text from your worksheet to the post, or re-typing it?
Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. |
Convert variable #'s in a gen. format to a # that can be used
I am getting the 54.
Actually this is the actual wording in the cell. I inadvertently left out the word Analyis originally. Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 "T. Valko" wrote: If this string is in cell A1: Period: 01/23/2010 to 01/29/2010 - Days: 6 What result do you get from this formula: =CODE(RIGHT(A1)) That formula should return 54. That's the character code value for the number 6. If you get a result other than 54 then that means there is some unseen whitespace character(s) at the end of the string in cell A1. -- Biff Microsoft Excel MVP "Steve" wrote in message ... E19 has a number in it. Formatted as a number. Also, in playing around, I may have changed the formatting of J3. It is currently formatted as a number. Thanks, Steve "T. Valko" wrote: E.g. Formula result is 6(in J3).... e19/j3 = #value! What's in E19? When a formula like that resturns a #VALUE! error it usually means one (or possibly both) cells referenced contain TEXT. Since we know that J3 contains numeric 6 then the problem has to be with cell E19. -- Biff Microsoft Excel MVP "Steve" wrote in message ... I do believe the "Days" will always be present, and your formula works to produce either the single #, tens, or hundreds, but when I use that result as a divisor, it still produces a #value! E.g. Formula result is 6(in J3).... e19/j3 = #value! "T. Valko" wrote: One way... Assuming the word "Days:" is *always* present. =--MID(A1,SEARCH("Days:",A1)+5,5) -- Biff Microsoft Excel MVP "Steve" wrote in message ... I have this data that is pasted to my worksheet: Period: 01/23/2010 to 01/29/2010 - Days: 6 It is in general format. The day numbers will always be in the last, last 2 , or last 3 positions. Depending on the period, the days may be any # up to the 365. I need to use that day #, be it 6, or 25, or 147, whatever, as a divisor of another number. E.g. if 6, then 1234 / 6 = 206 if 25, then 5678 / 25 = 227, etc/ The variable #'s will be in the same cell, so I basically want: E29/6 or E29/25, or E29/147, etc. Basically, those general formatted #'s converted to a usable/divisable #. Thanks, Steve . . . |
Convert variable #'s in a gen. format to a # that can be used
Whoa !! This was sooo weird, but I think I solved the mystery thanks to you
guiding me with your questions, though I still need the formula adjusted. Both your MidTrimFind and the MidFind worked when I copied the data. And by pasting that into the original cell, it worked. But both were identical, or so I thought. They were in different fonts, so when I put the original below what I typed and then made them both in the same font, I discovered that the original had extra spaces around the dashes, and before the number. See below: Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days:73 typed Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days: 73 original Anyway, if you could adjust your formula to account for these extra spaces, I would be very grateful. And again, Thanks for all your patience. It is much appreciated. Steve "Glenn" wrote: Are you copying the text from your worksheet to the post, or re-typing it? Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. . |
Convert variable #'s in a gen. format to a # that can be used
OK, now I'm confused. There are 90 days between 10/31/2009 and 1/29/2010, but
the answer you want is 73? Let's go back to grabbing the last number in the cell: =--TRIM(RIGHT(SUBSTITUTE(TRIM(A1),":",REPT(" ",10)),10)) That should account for any extra spaces, anywhere within the text or after the number at the end. Steve wrote: Whoa !! This was sooo weird, but I think I solved the mystery thanks to you guiding me with your questions, though I still need the formula adjusted. Both your MidTrimFind and the MidFind worked when I copied the data. And by pasting that into the original cell, it worked. But both were identical, or so I thought. They were in different fonts, so when I put the original below what I typed and then made them both in the same font, I discovered that the original had extra spaces around the dashes, and before the number. See below: Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days:73 typed Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days: 73 original Anyway, if you could adjust your formula to account for these extra spaces, I would be very grateful. And again, Thanks for all your patience. It is much appreciated. Steve "Glenn" wrote: Are you copying the text from your worksheet to the post, or re-typing it? Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. . |
Convert variable #'s in a gen. format to a # that can be used
Mee too.
I don't know how they got their days, but you're right, I should go with their ending #'s. This formula only worked if I removed the begining dashes after the = . =TRIM(RIGHT etc., but it did work that way. The number came up, but by dividing the other number into it, it came up as #value! The # I'm using isnumber TRUE The formula cell isnnumber FALSE Even formatting that cell as a number from general, it's still FALSE "Glenn" wrote: OK, now I'm confused. There are 90 days between 10/31/2009 and 1/29/2010, but the answer you want is 73? Let's go back to grabbing the last number in the cell: =--TRIM(RIGHT(SUBSTITUTE(TRIM(A1),":",REPT(" ",10)),10)) That should account for any extra spaces, anywhere within the text or after the number at the end. Steve wrote: Whoa !! This was sooo weird, but I think I solved the mystery thanks to you guiding me with your questions, though I still need the formula adjusted. Both your MidTrimFind and the MidFind worked when I copied the data. And by pasting that into the original cell, it worked. But both were identical, or so I thought. They were in different fonts, so when I put the original below what I typed and then made them both in the same font, I discovered that the original had extra spaces around the dashes, and before the number. See below: Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days:73 typed Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days: 73 original Anyway, if you could adjust your formula to account for these extra spaces, I would be very grateful. And again, Thanks for all your patience. It is much appreciated. Steve "Glenn" wrote: Are you copying the text from your worksheet to the post, or re-typing it? Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. . . |
Convert variable #'s in a gen. format to a # that can be used
The "beginning dashes" were intentional, they force Excel to evaluate the result
of the text manipulation (trim, right, substitute) as a number. What do you get with them in the formula? Steve wrote: Mee too. I don't know how they got their days, but you're right, I should go with their ending #'s. This formula only worked if I removed the begining dashes after the = . =TRIM(RIGHT etc., but it did work that way. The number came up, but by dividing the other number into it, it came up as #value! The # I'm using isnumber TRUE The formula cell isnnumber FALSE Even formatting that cell as a number from general, it's still FALSE "Glenn" wrote: OK, now I'm confused. There are 90 days between 10/31/2009 and 1/29/2010, but the answer you want is 73? Let's go back to grabbing the last number in the cell: =--TRIM(RIGHT(SUBSTITUTE(TRIM(A1),":",REPT(" ",10)),10)) That should account for any extra spaces, anywhere within the text or after the number at the end. Steve wrote: Whoa !! This was sooo weird, but I think I solved the mystery thanks to you guiding me with your questions, though I still need the formula adjusted. Both your MidTrimFind and the MidFind worked when I copied the data. And by pasting that into the original cell, it worked. But both were identical, or so I thought. They were in different fonts, so when I put the original below what I typed and then made them both in the same font, I discovered that the original had extra spaces around the dashes, and before the number. See below: Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days:73 typed Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days: 73 original Anyway, if you could adjust your formula to account for these extra spaces, I would be very grateful. And again, Thanks for all your patience. It is much appreciated. Steve "Glenn" wrote: Are you copying the text from your worksheet to the post, or re-typing it? Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. . . |
Convert variable #'s in a gen. format to a # that can be used
This
=--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve Gives me a "Glenn" wrote: The "beginning dashes" were intentional, they force Excel to evaluate the result of the text manipulation (trim, right, substitute) as a number. What do you get with them in the formula? Steve wrote: Mee too. I don't know how they got their days, but you're right, I should go with their ending #'s. This formula only worked if I removed the begining dashes after the = . =TRIM(RIGHT etc., but it did work that way. The number came up, but by dividing the other number into it, it came up as #value! The # I'm using isnumber TRUE The formula cell isnnumber FALSE Even formatting that cell as a number from general, it's still FALSE "Glenn" wrote: OK, now I'm confused. There are 90 days between 10/31/2009 and 1/29/2010, but the answer you want is 73? Let's go back to grabbing the last number in the cell: =--TRIM(RIGHT(SUBSTITUTE(TRIM(A1),":",REPT(" ",10)),10)) That should account for any extra spaces, anywhere within the text or after the number at the end. Steve wrote: Whoa !! This was sooo weird, but I think I solved the mystery thanks to you guiding me with your questions, though I still need the formula adjusted. Both your MidTrimFind and the MidFind worked when I copied the data. And by pasting that into the original cell, it worked. But both were identical, or so I thought. They were in different fonts, so when I put the original below what I typed and then made them both in the same font, I discovered that the original had extra spaces around the dashes, and before the number. See below: Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days:73 typed Analysis Period: 10/31/2009 to 01/29/2010 - Processing Days: 73 original Anyway, if you could adjust your formula to account for these extra spaces, I would be very grateful. And again, Thanks for all your patience. It is much appreciated. Steve "Glenn" wrote: Are you copying the text from your worksheet to the post, or re-typing it? Try this: =MID(TRIM(A3),FIND(" to ",TRIM(A3))+4,10)- MID(TRIM(A3),FIND(" to ",TRIM(A3))-10,10) Glenn wrote: When I copy your text directly from this post to cell A3 in a blank worksheet and then copy my formula to any other cell, I get the number result 6. Can you reproduce that result? Steve wrote: This in the cell Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6 the subtraction would work, as that's really all I need, the days, but this =MID(A3,FIND(" to ",A3)+4,10)-MID(A3,FIND(" to ",A3)-10,10) still produced a #value! Also =isnumber(e19) produced a TRUE Thanks for your patience. . . . |
Convert variable #'s in a gen. format to a # that can be used
Copy the value from A3 (the one that results in #Value!) directly into a
response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve |
Convert variable #'s in a gen. format to a # that can be used
Analysis Period: 01/23/2010 to 01/29/2010 - Processing Days: 6
"Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . |
Convert variable #'s in a gen. format to a # that can be used
#VALUE! -
=--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . |
Convert variable #'s in a gen. format to a # that can be used
Can not reproduce the error with information you are providing. If you like,
email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . |
Convert variable #'s in a gen. format to a # that can be used
Thank you very much.
It's on it's way. Steve "Glenn" wrote: Can not reproduce the error with information you are providing. If you like, email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . . |
Convert variable #'s in a gen. format to a # that can be used
The character after the colon is not a "normal" space. I copied the text from
A3 into A1 of a new worksheet, then entered the following two formulas: B1 = MID($A$1,ROW(),1) C1 = CODE(MID($A$1,ROW(),1)) I copied B1 and C1 down the columns until the entire string was evaluated. The spaces between words ("Analysis" and "Period", "Processing" and "Days") is CHAR(32), all other spaces are CHAR(160). Try this: =--TRIM(RIGHT(SUBSTITUTE(A3,CHAR(160),REPT(" ",10)),10)) Steve wrote: Thank you very much. It's on it's way. Steve "Glenn" wrote: Can not reproduce the error with information you are providing. If you like, email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . . |
Convert variable #'s in a gen. format to a # that can be used
Thank you so very, very much. I really appreciate all your patience.
I don't think I even want to begin to know what a non-normal space is, but the final formula works great. Thank you again, Steve "Glenn" wrote: The character after the colon is not a "normal" space. I copied the text from A3 into A1 of a new worksheet, then entered the following two formulas: B1 = MID($A$1,ROW(),1) C1 = CODE(MID($A$1,ROW(),1)) I copied B1 and C1 down the columns until the entire string was evaluated. The spaces between words ("Analysis" and "Period", "Processing" and "Days") is CHAR(32), all other spaces are CHAR(160). Try this: =--TRIM(RIGHT(SUBSTITUTE(A3,CHAR(160),REPT(" ",10)),10)) Steve wrote: Thank you very much. It's on it's way. Steve "Glenn" wrote: Can not reproduce the error with information you are providing. If you like, email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . . . |
Convert variable #'s in a gen. format to a # that can be used
You are welcome. Glad we could finally get it working.
Steve wrote: Thank you so very, very much. I really appreciate all your patience. I don't think I even want to begin to know what a non-normal space is, but the final formula works great. Thank you again, Steve "Glenn" wrote: The character after the colon is not a "normal" space. I copied the text from A3 into A1 of a new worksheet, then entered the following two formulas: B1 = MID($A$1,ROW(),1) C1 = CODE(MID($A$1,ROW(),1)) I copied B1 and C1 down the columns until the entire string was evaluated. The spaces between words ("Analysis" and "Period", "Processing" and "Days") is CHAR(32), all other spaces are CHAR(160). Try this: =--TRIM(RIGHT(SUBSTITUTE(A3,CHAR(160),REPT(" ",10)),10)) Steve wrote: Thank you very much. It's on it's way. Steve "Glenn" wrote: Can not reproduce the error with information you are providing. If you like, email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . . . |
Convert variable #'s in a gen. format to a # that can be used
I've been offline for a few days thanks to the big snow storm!
I kind of had a feeling there were some whitespace characters causing this problem. To the OP... If this data is copied/pasted/imported from a website or from another application, char(160) problems are very common. I copy/paste/import from the web just about every day. To eliminate the char(160) problem I use this macro by David McRitchie: http://www.mvps.org/dmcritchie/excel/join.htm#trimall Saves a ton of time and aggravation! -- Biff Microsoft Excel MVP "Glenn" wrote in message ... You are welcome. Glad we could finally get it working. Steve wrote: Thank you so very, very much. I really appreciate all your patience. I don't think I even want to begin to know what a non-normal space is, but the final formula works great. Thank you again, Steve "Glenn" wrote: The character after the colon is not a "normal" space. I copied the text from A3 into A1 of a new worksheet, then entered the following two formulas: B1 = MID($A$1,ROW(),1) C1 = CODE(MID($A$1,ROW(),1)) I copied B1 and C1 down the columns until the entire string was evaluated. The spaces between words ("Analysis" and "Period", "Processing" and "Days") is CHAR(32), all other spaces are CHAR(160). Try this: =--TRIM(RIGHT(SUBSTITUTE(A3,CHAR(160),REPT(" ",10)),10)) Steve wrote: Thank you very much. It's on it's way. Steve "Glenn" wrote: Can not reproduce the error with information you are providing. If you like, email me a *SMALL* sample worksheet with the error and I'll take a look at it. Send to glennschwandt at yahoo dot com. Steve wrote: #VALUE! - =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) The above is the data in the #Value! cell via the formula bar. "Glenn" wrote: Copy the value from A3 (the one that results in #Value!) directly into a response to this post. Do not re-type or edit in any way. Steve wrote: This =--TRIM(RIGHT(SUBSTITUTE(TRIM(A3),":",REPT(" ",10)),10)) Gives me a #Value! Also isnumber for that cell is false. Thanks, Steve . . . |
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