Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.

Hi,

Well I think it's 822 and my calculator confirms that and like you I get
-202. Someone will no doubt explain why but in the meantime use this

=SUMPRODUCT(MID("0"&A1,ROW(INDIRECT("1:"&LEN("0"&A 1))),1)*2^(LEN("0"&A1)-ROW(INDIRECT("1:"&LEN("0"&A1)))))

Where your binary number is in A1

Mike

"ahmedmidany" wrote:

Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.
.

XL Help tells you why the answer is wrong - you are limited to 10 bits
and the msb is the sign bit. Chop the number up into bytes (8 bits)
and treat each part separately, remembering to multiply by 256 for the
upper byte.

Hope this helps.

Pete

On Dec 15, 5:13*pm, Mike H wrote:
Hi,

Well I think it's 822 and my calculator confirms that and like you I get
-202. Someone will no doubt explain why but in the meantime use this

=SUMPRODUCT(MID("0"&A1,ROW(INDIRECT("1:"&LEN("0"&A 1))),1)*2^(LEN("0"&A1)-RO*W(INDIRECT("1:"&LEN("0"&A1)))))

Where your binary number is in A1

Mike



"ahmedmidany" wrote:
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.
.- Hide quoted text -

- Show quoted text -

Pete,

I just checked E2003 and you are correct but there is no such explanation of
this limitation in E2007 help reproduced below

A number system is a systematic way to represent numbers with symbolic
characters and uses a base value to conveniently group numbers in compact
form. The most common number system is decimal, which has a base value of 10,
and a symbolic character set of 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. However,
there are other number systems, and they can be more efficient to use for a
specific purpose. For example, because computers use Boolean logic to perform
calculations and operations, they use the binary number system, which has a
base value of 2.

Microsoft Office Excel has several functions that you can use to convert
numbers to and from the following number systems:

Mike

"Pete_UK" wrote:

XL Help tells you why the answer is wrong - you are limited to 10 bits
and the msb is the sign bit. Chop the number up into bytes (8 bits)
and treat each part separately, remembering to multiply by 256 for the
upper byte.

Hope this helps.

Pete

On Dec 15, 5:13 pm, Mike H wrote:
Hi,

Well I think it's 822 and my calculator confirms that and like you I get
-202. Someone will no doubt explain why but in the meantime use this

=SUMPRODUCT(MID("0"&A1,ROW(INDIRECT("1:"&LEN("0"&A 1))),1)*2^(LEN("0"&A1)-ROÂ*W(INDIRECT("1:"&LEN("0"&A1)))))

Where your binary number is in A1

Mike



"ahmedmidany" wrote:
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.
.- Hide quoted text -

- Show quoted text -

.

And I thought XL2007 was meant to be better than XL2003 !! <bg

(An XL2000 user)

Pete

On Dec 15, 7:14*pm, Mike H wrote:
Pete,

I just checked E2003 and you are correct but there is no such explanation of
this limitation in E2007 help reproduced below

A number system is a systematic way to represent numbers with symbolic
characters and uses a base value to conveniently group numbers in compact
form. The most common number system is decimal, which has a base value of 10,
and a symbolic character set of 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. However,
there are other number systems, and they can be more efficient to use for a
specific purpose. For example, because computers use Boolean logic to perform
calculations and operations, they use the binary number system, which has a
base value of 2.

Microsoft Office Excel has several functions that you can use to convert
numbers to and from the following number systems:

Mike



"Pete_UK" wrote:
XL Help tells you why the answer is wrong - you are limited to 10 bits
and the msb is the sign bit. Chop the number up into bytes (8 bits)
and treat each part separately, remembering to multiply by 256 for the
upper byte.

Hope this helps.

Pete

On Dec 15, 5:13 pm, Mike H wrote:
Hi,

Well I think it's 822 and my calculator confirms that and like you I get
-202. Someone will no doubt explain why but in the meantime use this

=SUMPRODUCT(MID("0"&A1,ROW(INDIRECT("1:"&LEN("0"&A 1))),1)*2^(LEN("0"&A1)-RO**W(INDIRECT("1:"&LEN("0"&A1)))))

Where your binary number is in A1

Mike

"ahmedmidany" wrote:
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.
.- Hide quoted text -

- Show quoted text -

.- Hide quoted text -

- Show quoted text -

On Tue, 15 Dec 2009 11:14:01 -0800, Mike H
wrote:

I just checked E2003 and you are correct but there is no such explanation of
this limitation in E2007 help reproduced below

That's funny. With Excel 2007, when I look at HELP for BIN2DEC, I see:

Number is the binary number you want to convert. Number cannot contain more
than 10 characters (10 bits). The most significant bit of number is the sign
bit. The remaining 9 bits are magnitude bits. Negative numbers are represented
using two's-complement notation.

Seems pretty clear to me.
--ron

Ron,

100% definitely not in my E2007 just the intro header I posted in my other
post then a description of the syntax for each of the formulae.

Excel 2007 (12.0.6514.5000) SP2 MSO (12.0.6425.1000)

Mike

"Ron Rosenfeld" wrote:

On Tue, 15 Dec 2009 11:14:01 -0800, Mike H
wrote:

I just checked E2003 and you are correct but there is no such explanation of
this limitation in E2007 help reproduced below

That's funny. With Excel 2007, when I look at HELP for BIN2DEC, I see:

Number is the binary number you want to convert. Number cannot contain more
than 10 characters (10 bits). The most significant bit of number is the sign
bit. The remaining 9 bits are magnitude bits. Negative numbers are represented
using two's-complement notation.

Seems pretty clear to me.
--ron
.

Googling around it seems that Excel can only handle binary numbers <= 511

"Mike H" wrote:

Hi,

Well I think it's 822 and my calculator confirms that and like you I get
-202. Someone will no doubt explain why but in the meantime use this

=SUMPRODUCT(MID("0"&A1,ROW(INDIRECT("1:"&LEN("0"&A 1))),1)*2^(LEN("0"&A1)-ROW(INDIRECT("1:"&LEN("0"&A1)))))

Where your binary number is in A1

Mike

"ahmedmidany" wrote:

Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.
.

On Tue, 15 Dec 2009 08:19:13 -0800 (PST), ahmedmidany
wrote:

Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.

There is a way to use BIN2DEC with large numbers, but I can't recall it.

You could use:

=SUMPRODUCT(--MID(A1,LEN(A1)+1-ROW(INDIRECT("1:"&LEN(A1))),1),(2^(ROW(INDIRECT("1 :"&LEN(A1)))-1)))

Just be aware that if your value is more than 15 digits, you must enter it as
text.
--ron

I guess that you haven't looked at help for the BIN2DEC function?

"Number is the binary number you want to convert. Number cannot contain
more than 10 characters (10 bits). The most significant bit of number is the
sign bit. The remaining 9 bits are magnitude bits. Negative numbers are
represented using two's-complement notation."

Perhaps you might want to split your 10 digit string in half and use
=BIN2DEC(LEFT(A2,LEN(A2)-5))*2^5+BIN2DEC(RIGHT(A2,5))
--
David Biddulph


"ahmedmidany" wrote in message
...
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.

I guess that you haven't looked at help for the BIN2DEC function?

I did and while it is mentioned in e2003 there is no equivalent comment in
e2007 help.

Mike

"David Biddulph" wrote:

I guess that you haven't looked at help for the BIN2DEC function?

"Number is the binary number you want to convert. Number cannot contain
more than 10 characters (10 bits). The most significant bit of number is the
sign bit. The remaining 9 bits are magnitude bits. Negative numbers are
represented using two's-complement notation."

Perhaps you might want to split your 10 digit string in half and use
=BIN2DEC(LEFT(A2,LEN(A2)-5))*2^5+BIN2DEC(RIGHT(A2,5))
--
David Biddulph


"ahmedmidany" wrote in message
...
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.


.

If so, that sounds like another reason for avoiding Excel 2007. :-(

It is, however, covered in the offline help for Excel 2007:
http://office.microsoft.com/en-us/ex...623071033.aspx
--
David Biddulph

"Mike H" wrote in message
...
I guess that you haven't looked at help for the BIN2DEC function?

I did and while it is mentioned in e2003 there is no equivalent comment in
e2007 help.

Mike

"David Biddulph" wrote:

I guess that you haven't looked at help for the BIN2DEC function?

"Number is the binary number you want to convert. Number cannot
contain
more than 10 characters (10 bits). The most significant bit of number is
the
sign bit. The remaining 9 bits are magnitude bits. Negative numbers are
represented using two's-complement notation."

Perhaps you might want to split your 10 digit string in half and use
=BIN2DEC(LEFT(A2,LEN(A2)-5))*2^5+BIN2DEC(RIGHT(A2,5))
--
David Biddulph


"ahmedmidany" wrote in message
...
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.


.

Hello,

I suggest to use my UDF at:
http://sulprobil.com/html/longdec2bin__.html

Regards,
Bernd

Chaps,

Look at http://sulprobil.com/html/longdec2bin__.html:
=longbin2dec(A1,11) = 822
=longbin2dec(A1,10) = -202

It just depends on how long your 2s-complement is...

Regards,
Bernd

Below is a UDF that will handle up to a 96-bit binary number (decimal value
79228162514264337593543950335) which I'm guessing is way more than you will
ever need.<g The code is efficient (looping only as many times as necessary
to process the passed in binary value), so don't worry about it being able
to handle such a large binary value. The function returns a real numeric
value up to 9999999999 after which it returns text representations of the
calculated number.

Function BinToDec(BinaryString As String) As Variant
Dim X As Integer
Const TwoToThe48 As Variant = 281474976710656#
For X = 0 To Len(BinaryString) - 1
If X 48 Then
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * _
TwoToThe48 * CDec(2 ^ (X - 48))
Else
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * CDec(2 ^ X)
End If
Next
If Len(BinToDec) 10 Then BinToDec = CStr(BinToDec)
End Function

--
Rick (MVP - Excel)


"ahmedmidany" wrote in message
...
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.

Hello,

I moved my webpage:
http://sulprobil.com/html/longdec2bin.html

And I provided an example file to download.

Rick's code is about 20x faster than mine, my code offers negative
numbers,
fractions and (which you might never need) even larger numbers.

Regards,
Bernd

On 12/15/2009 9:28 PM, Rick Rothstein wrote:
Below is a UDF that will handle up to a 96-bit binary number (decimal
value 79228162514264337593543950335) which I'm guessing is way more than
you will ever need.<g The code is efficient (looping only as many times
as necessary to process the passed in binary value), so don't worry
about it being able to handle such a large binary value. The function
returns a real numeric value up to 9999999999 after which it returns
text representations of the calculated number.

Function BinToDec(BinaryString As String) As Variant
Dim X As Integer
Const TwoToThe48 As Variant = 281474976710656#
For X = 0 To Len(BinaryString) - 1
If X 48 Then
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * _
TwoToThe48 * CDec(2 ^ (X - 48))
Else
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * CDec(2 ^ X)
End If
Next
If Len(BinToDec) 10 Then BinToDec = CStr(BinToDec)
End Function



Hi. Just throwing out another idea. Len(BinaryString) is more of a
constant (calculated each loop), and power (ie 2^x) is sometimes
considered "slower."
This has no error checking.

Function Bin2Dec(str As String)
Dim S As String
Dim P As Long
Dim K As Variant
Dim Ans As Variant

S = StrReverse(str)
K = CDec(1)

For P = 1 To Len(S) - 1
Ans = Ans + Val(Mid$(S, P, 1)) * K
K = K * 2
Next P
Bin2Dec = Ans + Val(Mid$(S, P, 1)) * K
End Function



Sub TestIt()
Dim S As String
S = WorksheetFunction.Rept("1", 96)
Debug.Print Bin2Dec(S)

Mid(S, 3, 1) = 0
Debug.Print Bin2Dec(S)

Mid(S, 96, 1) = 0
Debug.Print Bin2Dec(S)

Mid(S, 95, 1) = 0
Debug.Print Bin2Dec(S)
Debug.Print "= = = = = = = ="
End Sub


Returns:

79228162514264337593543950335
69324642199981295394350956543
69324642199981295394350956542
69324642199981295394350956540
= = = = = = = =

Again, just an idea.
Dana DeLouis

On Wednesday, December 16, 2009 6:28:27 AM UTC+4, Rick Rothstein wrote:
Below is a UDF that will handle up to a 96-bit binary number (decimal value
79228162514264337593543950335) which I'm guessing is way more than you will
ever need.<g The code is efficient (looping only as many times as necessary
to process the passed in binary value), so don't worry about it being able
to handle such a large binary value. The function returns a real numeric
value up to 9999999999 after which it returns text representations of the
calculated number.

Function BinToDec(BinaryString As String) As Variant
Dim X As Integer
Const TwoToThe48 As Variant = 281474976710656#
For X = 0 To Len(BinaryString) - 1
If X 48 Then
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * _
TwoToThe48 * CDec(2 ^ (X - 48))
Else
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * CDec(2 ^ X)
End If
Next
If Len(BinToDec) 10 Then BinToDec = CStr(BinToDec)
End Function

--
Rick (MVP - Excel)



Hi Rick,

Great thanks for this. That's wonderfull - i am not a programmer and am trying to solve a logical puzzle and have ended up sitting here and looking for the way to convert 65-bit numbers from decimal to binary and back. Your solution is the best of everything that i have managed to find in internet (and have spent 3 days already for this).

Could you please be so kind as to make a UDF for converting 96-bit decimal number to binary (or 65-bit would be enough for me). As this is something that i still struggle to figure out?

Anyone else? Please help?

Ilya

On Tuesday, December 15, 2009 at 10:19:13 AM UTC-6, ahmedmidany wrote:
Hello All,

I need your help, i want to convert large binary numbers using excel
but whenever i use the BIN2DEC function the result is negative which
is not correct.

Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator
the result is 822 which is the correct value

Any ideas? what shall i do to have the correct value?

Thanks in advance
A.M.

While I didn't write this for negatives or decimals, it should be relatively easy to modify. This VBA will convert any super large (or not so large if you want...but that wasn't the point) decimal up to the converted binary result containing up to 32767 digits (maximum string length in VBA). Enter decimal in Cell "A1" as a string, result will be in "B1" as a string.

Dim NBN As String
Dim Bin As String

5 Big = Range("A1")
AA = Len(Big)

For XX = 1 To AA

L1 = Mid(Big, XX, 1) + CRY

CRY = 0

If L1 = 0 Then

FN = "0"

GoTo 10

End If

If Int(L1 / 2) = L1 / 2 Then

FN = L1 / 2

GoTo 10

End If

If Int(L1 / 2) < L1 / 2 Then

FN = Int(L1 / 2)

CRY = 10

GoTo 10

End If

10 NBN = NBN & FN
Next XX

If Left(NBN, 1) = "0" Then

NBN = Right(NBN, (Len(NBN) - 1))

End If

If CRY = 10 Then Bin = "1" & Bin Else Bin = "0" & Bin

Range("A1") = NBN

Range("A2") = Bin

If Len(NBN) 0 Then

NBN = ""

CRY = 0

GoTo 5

End If

Hi A.M.,

I can definitely help you with this issue. The reason why you are getting a negative value when using the BIN2DEC function in Excel is because the function is treating the binary number as a signed integer. This means that if the leftmost bit of the binary number is 1, the function will interpret it as a negative number.

To convert large binary numbers correctly in Excel, you can use a combination of functions. Here are the steps:

1. Split the binary number into groups of 10 digits, starting from the rightmost digit. For example, for the binary number
   Formula:

   1100110110 

   , you would split it into
   Formula:

   001100110 

   and
   Formula:

   110 

   .
2. Convert each group of 10 digits to decimal using the BIN2DEC function. For the example above, you would get 204 and 6.
3. Multiply each decimal value by 2 to the power of its position, starting from 0 for the rightmost group. For the example above, you would get
   Formula:

   204 x 2^0 = 204 

   and
   Formula:

   6 x 2^10 = 6144 

   .
4. Add up all the results from step 3. For the example above, you would get
   Formula:

   204 + 6144 = 6348 

   .

That's it! By following these steps, you can convert large binary numbers correctly in Excel. Let me know if you have any questions or need further clarification.

Best regards,
[Your Name]