FIND 2nd character in a string
 

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

You can select the column..Data Text to Columns and separate the pieces to
columns....If you are looking for a formula below is one way..

=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("/",A1,FIND("/",A1)+1)+1,LEN(A1)),"/",REPT(CHAR(32),LEN(A1))),LEN(A1)))

If this post helps click Yes
---------------
Jacob Skaria


"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

On Mon, 31 Aug 2009 02:31:01 -0700, Fuzzy
wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

=TRIM(RIGHT(SUBSTITUTE(LEFT(A1,FIND(CHAR(1),
SUBSTITUTE(A1,"/",CHAR(1),3))-1),"/",REPT(" ",99)),99))

or, you could use the Data/Text-to-columns wizard with "/" as the delimiter,
and use the third column.
--ron

FIND 2nd character in a string
 

Hi,

Suppose the string you are looking for 78445945 is always 8 characters, then

=MID(A1,FIND("/",A1,FIND("/",A1)+1)+1,8)

--
If this helps, please click the Yes button.

Cheers,
Shane Devenshire


"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

Hi Fuzzy,

The Substitute function allows you to specify an instance # so that you can
identify where the 2nd instance of "/" is:

SUBSTITUTE(text,old_text,new_text,instance_num)

Substitute("\",a1,"unique character of your choice",2)

Then you can use Find:

Find("unique character of your choice",(substitute("\",a1,"unique character
of your choice",2),1)

Hope this helps.

Peggy

"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

Peggy - Thanks a ton!!!! Was simple and worked!!
Btw, the syntax for substitute was slightly wrong... :)
Correct - Substitute(a1,'/',"unique character of your choice",2)



"pshepard" wrote:

Hi Fuzzy,

The Substitute function allows you to specify an instance # so that you can
identify where the 2nd instance of "/" is:

SUBSTITUTE(text,old_text,new_text,instance_num)

Substitute("\",a1,"unique character of your choice",2)

Then you can use Find:

Find("unique character of your choice",(substitute("\",a1,"unique character
of your choice",2),1)

Hope this helps.

Peggy

"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

Perfect!!!
It worked!! Thank you....

Was wondering how to get the second "/" in that mid formula....
Coz i had used the mid as well as the find formula... just dint know how to
get the 2nd "/"

God Bless!

"Shane Devenshire" wrote:

Hi,

Suppose the string you are looking for 78445945 is always 8 characters, then

=MID(A1,FIND("/",A1,FIND("/",A1)+1)+1,8)

--
If this helps, please click the Yes button.

Cheers,
Shane Devenshire


"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

FIND 2nd character in a string
 

The formula was complicated! but it worked!

Thank you very much.

"Jacob Skaria" wrote:

You can select the column..Data Text to Columns and separate the pieces to
columns....If you are looking for a formula below is one way..

=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("/",A1,FIND("/",A1)+1)+1,LEN(A1)),"/",REPT(CHAR(32),LEN(A1))),LEN(A1)))

If this post helps click Yes
---------------
Jacob Skaria


"Fuzzy" wrote:

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945