Find the lowest number in a given column
 

Colin Hayes wrote:
In article , smartin
writes
Colin Hayes wrote:

Hi

I need a small macro to find the lowest number in a given column , and
then replace it with a number input through a popup.


Can anyone help?


Grateful for any assistance.


Try this:

Sub ReplaceIt()
Dim TheMin As Variant
Dim TheOffset As Long
Dim TheCell As String
Dim TheNewValue As Variant

TheMin = Application.WorksheetFunction. _
Min(Range("A:A"))
TheOffset = Application.WorksheetFunction. _
Match(TheMin, Range("A1:A9999"), 0)
TheCell = Range("A1").Offset(TheOffset - 1).Address

TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
Range(TheCell).Value = TheNewValue
End Sub

Hi

OK thanks very much for helping.

It works fine , but only changes one value , rather than all the
matching ones.

For example , it found the lowest to be 1.95 and I asked it to change
this to 1.25. It did it , but only to the first occurrence of a cell
with 1.95 and left all the others intact. Could it be tweaked to change
all cells with the lowest value?

Also , because the column I need it to work on could vary would it be
possible to enter the column to be selected via a popup and for it to
work on the whole column down to the last row wherever that is?

Grateful again for you advice.



Best Wishes

Hi Colin, sorry for the late reply.
Without creating a user form, the approach I would take would be:

- Sub1 with input box to query user for the column, call and pass result
to Sub2.

- Sub2 with input box to query user for min value, then leverage
Application.WorksheetFunction.Replace and the column reference obtained
above to do the heavy lifting.

Sorry I don't feel like coding just now, post back if you get stuck!

Find the lowest number in a given column
 

In article , smartin
writes
Hi Colin, sorry for the late reply.
Without creating a user form, the approach I would take would be:

- Sub1 with input box to query user for the column, call and pass result to Sub2.

- Sub2 with input box to query user for min value, then leverage Application.Worksh
eetFunction.Rep
lace and the column reference obtained above to do the heavy lifting.

Sorry I don't feel like coding just now, post back if you get stuck!

Hi

OK I understand the feeling!

I see the logic in your outline above , but I'm afraid I don't have the
technical skills to code this. Maybe when you have more time available
you could assist. I'd be grateful for that.

Thanks again



Best Wishes


Colin

Find the lowest number in a given column
 

Colin Hayes wrote:
In article , smartin
writes
Hi Colin, sorry for the late reply.
Without creating a user form, the approach I would take would be:

- Sub1 with input box to query user for the column, call and pass
result to Sub2.

- Sub2 with input box to query user for min value, then leverage
Application.Worksh
eetFunction.Rep
lace and the column reference obtained above to do the heavy lifting.

Sorry I don't feel like coding just now, post back if you get stuck!

Hi

OK I understand the feeling!

I see the logic in your outline above , but I'm afraid I don't have the
technical skills to code this. Maybe when you have more time available
you could assist. I'd be grateful for that.

Thanks again



Best Wishes


Colin

Here's a more thorough version for you.


Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub

Find the lowest number in a given column
 

In article , smartin
writes
Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub


Hi

OK thanks - this worked perfectly first time and precisely fits the
bill. I'm impressed.

I did find that on the second popup (Minimum value found was ..Enter
value to replace..) that if I click 'cancel' then all of the selected
values from the first popup are wiped form the worksheet , leaving blank
cells. I imagined it would just exit the routine with no further action
or impact.

Anyway , thanks again.

Best Wishes


Colin

Find the lowest number in a given column
 

Colin Hayes wrote:
In article , smartin
writes
[snipped for clarity]


Hi

OK thanks - this worked perfectly first time and precisely fits the
bill. I'm impressed.

I did find that on the second popup (Minimum value found was ..Enter
value to replace..) that if I click 'cancel' then all of the selected
values from the first popup are wiped form the worksheet , leaving blank
cells. I imagined it would just exit the routine with no further action
or impact.

Anyway , thanks again.

Best Wishes


Colin

My bad! That would be the one thing I did not test. Not very good
programming, is it? (^: Try this replacement:


Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
If TheNewValue < "" Then
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False
Else
MsgBox "No input, operation canceled."
End If

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub

Find the lowest number in a given column
 

In article , smartin
writes
My bad! That would be the one thing I did not test. Not very good programming, is
it? (^: Try this
replacement:


Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
If TheNewValue < "" Then
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False
Else
MsgBox "No input, operation canceled."
End If

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub

HI

OK , that's got it. Perfect now.


Thanks again. I'm grateful for your time and expertise.



Best Wishes


Colin

Find the lowest number in a given column
 

In article , Colin Hayes
writes
In article , smartin
writes
My bad! That would be the one thing I did not test. Not very good programming, is
it? (^: Try this
replacement:


Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
If TheNewValue < "" Then
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False
Else
MsgBox "No input, operation canceled."
End If

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub


HI

BTW Would it be an easy amendment for the routine to operate directly on
the column where the cursor is , rather than ask for an input letter at
the beginning? It would be useful in some circumstances if it just
assumed that the column where the cursor is is the one to be worked on.

That's all , I promise.


Best Wishes


Colin

Find the lowest number in a given column
 

Colin Hayes wrote:
In article , Colin Hayes
writes
In article , smartin
writes
My bad! That would be the one thing I did not test. Not very good
programming, is
it? (^: Try this
replacement:


Sub ReplaceIt2()
Dim TheColumn As Variant
Dim TheRange As String
Dim TheMin As Variant
Dim TheNewValue As Variant
Dim OriginalRange As String
Dim OriginalCell As String

On Error GoTo Quitter

Application.ScreenUpdating = False
OriginalRange = Selection.Address
OriginalCell = ActiveCell.Address

TheColumn = InputBox("Which column?")
If TheColumn < "" Then
TheRange = TheColumn & ":" & TheColumn
TheMin = Application.WorksheetFunction. _
Min(Range(TheRange))
TheNewValue = InputBox("Minimum value found was " & _
TheMin & ". Enter value to replace.")
If TheNewValue < "" Then
Range(TheRange).Select
Selection.Replace What:=TheMin, _
Replacement:=TheNewValue, _
LookAt:=xlWhole, _
SearchOrder:=xlByRows, _
MatchCase:=False, _
SearchFormat:=False, _
ReplaceFormat:=False
Else
MsgBox "No input, operation canceled."
End If

Range(OriginalRange).Select
Range(OriginalCell).Activate
Else
MsgBox "No input, quitting."
End If
Quitter:
Application.ScreenUpdating = True
End Sub


HI

BTW Would it be an easy amendment for the routine to operate directly on
the column where the cursor is , rather than ask for an input letter at
the beginning? It would be useful in some circumstances if it just
assumed that the column where the cursor is is the one to be worked on.

That's all , I promise.


Best Wishes


Colin

Replace this:
TheColumn = InputBox("Which column?")

With this:
TheColumn = Left(OriginalCell, _
InStr(2, OriginalCell, "$") - 1)

Find the lowest number in a given column
 

In article , smartin
writes
HI

BTW Would it be an easy amendment for the routine to operate directly on
the column where the cursor is , rather than ask for an input letter at
the beginning? It would be useful in some circumstances if it just
assumed that the column where the cursor is is the one to be worked on.

That's all , I promise.


Best Wishes


Colin

Replace this:
TheColumn = InputBox("Which column?")

With this:
TheColumn = Left(OriginalCell, _
InStr(2, OriginalCell, "$") - 1)


Hi

OK that's perfect - working great.

Thanks again.

^_^

Best Wishes


Colin