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"Shane Devenshire" wrote:
Or after some thought how about just =SUMPRODUCT(MIN(2*(A1:A8=0)+A1:A8)) Perhaps you should do less "thought" and more testing. Try A1:A8 equal to {0,3,3,3,3,3,3,0}. Klunk! Anyway, I think the horse is dead. ----- original message ----- "Shane Devenshire" wrote in message ... Hi, Or after some thought how about just =SUMPRODUCT(MIN(2*(A1:A8=0)+A1:A8)) -- If this helps, please click the Yes button. Cheers, Shane Devenshire "JoeU2004" wrote: "Shane Devenshire" wrote: =SUMPRODUCT(MIN(9^9*(A1:A8=0)+A1:A8)) Why 9^9? Why not something more straight-forward like 10^10? That can written as the constant 1E10? And why is this any better than Biff's (T.Valko's) formulation that uses MIN(INDEX(...))? I presume you saw his, since you posted your follow-up more than 4 hours later to the same news server, I believe. In any case, as I noted regarding Biff's formula, expressions of this ilk limit MAX(A1:A8) to whatever factor you use, be it 9^9, 1E10 or 1E100. So it would behoove you to use a larger factor like 1E10 or even 1E100. And to that end, I think it would be better to replace any constant factor (e.g. 9^9) with 2*max(A1:A8). That limits MAX(A1:A8) to 2^1023, about half the biggest value allowed. I also noted that we can extend the range of values for MAX(A1:A8) by replacing the factor 2 with a smaller factor larger than 1; the smallest constant factor is 1.00000000000001. But none of this seems to be worth the trouble just to avoid the straight-forward array formula solution, as much as I don't like array formulas myself. ----- original message ----- "Shane Devenshire" wrote in message ... Well that's pretty interesting, unfortunately I cleared my test range and can't duplicate the original results. Alternative: =SUMPRODUCT(MIN(9^9*(A1:A8=0)+A1:A8)) hopefully this is a little better. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Shane Devenshire" wrote: Hi, If you don't want an array formula try this =SUMPRODUCT((A1:A7<0)*(MIN(A1:A7)=A1:A7)*A1:A7) -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Opus" wrote: I need to find the minimum non-zero number in a range of cells that contains some zeroes. So that I can divide by the minimum number. Any ideas? If I just use the MIN function, it returns a value of 0, then when my formula divides by that I get the divide by zero error. |
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