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More than one variable for Countif
Hi -
Really stumped on this one. I have tried many different formula's using SUMPRODUCT, And, IF in conjunction with Countif but still can't seem to get it to work. I have a worksheet with dates listed down column B called "Schedule". I need to look in another worksheet, find two separate colunms true; if they are both true then count. I continue to get the #NUM! error no matter which way I approach this. Any help would surely be appreciated. Example of the "SUMPRODUCT" approach below [B163 is equal to a date of 06/09/2009 and K2 is equal to a team number of L01 on the worksheet "Schedule"] =SUMPRODUCT('Team Worksheet'!J:J=Schedule!B163,'Team Worksheet'!N:N=Schedule! K2) Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
You can't use whole columns like J:J, try using a range like J1;J5000
Regards, Alan. "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:9596092e4be14@uwe... Hi - Really stumped on this one. I have tried many different formula's using SUMPRODUCT, And, IF in conjunction with Countif but still can't seem to get it to work. I have a worksheet with dates listed down column B called "Schedule". I need to look in another worksheet, find two separate colunms true; if they are both true then count. I continue to get the #NUM! error no matter which way I approach this. Any help would surely be appreciated. Example of the "SUMPRODUCT" approach below [B163 is equal to a date of 06/09/2009 and K2 is equal to a team number of L01 on the worksheet "Schedule"] =SUMPRODUCT('Team Worksheet'!J:J=Schedule!B163,'Team Worksheet'!N:N=Schedule! K2) Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Hi
=SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule!K2)) The above formula will only work in XL2007. In previous versions, you can not use a range like J:J, but something like J1:J1000. Hopes this helps. Per "Carrie_Loos via OfficeKB.com" <u34134@uwe skrev i meddelelsen news:9596092e4be14@uwe... Hi - Really stumped on this one. I have tried many different formula's using SUMPRODUCT, And, IF in conjunction with Countif but still can't seem to get it to work. I have a worksheet with dates listed down column B called "Schedule". I need to look in another worksheet, find two separate colunms true; if they are both true then count. I continue to get the #NUM! error no matter which way I approach this. Any help would surely be appreciated. Example of the "SUMPRODUCT" approach below [B163 is equal to a date of 06/09/2009 and K2 is equal to a team number of L01 on the worksheet "Schedule"] =SUMPRODUCT('Team Worksheet'!J:J=Schedule!B163,'Team Worksheet'!N:N=Schedule! K2) Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Hi, and don't forget that the ranges should have same length (fi J1:J5000 and N1:N5000) HTH Alan;332752 Wrote: You can't use whole columns like J:J, try using a range like J1;J5000 Regards, Alan. "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:9596092e4be14@uwe... Hi - Really stumped on this one. I have tried many different formula's using SUMPRODUCT, And, IF in conjunction with Countif but still can't seem to get it to work. I have a worksheet with dates listed down column B called "Schedule". I need to look in another worksheet, find two separate colunms true; if they are both true then count. I continue to get the #NUM! error no matter which way I approach this. Any help would surely be appreciated. Example of the "SUMPRODUCT" approach below [B163 is equal to a date of 06/09/2009 and K2 is equal to a team number of L01 on the worksheet "Schedule"] =SUMPRODUCT('Team Worksheet'!J:J=Schedule!B163,'Team Worksheet'!N:N=Schedule! K2) Thanks for any help -- Message posted via OfficeKB.com 'Excel - using Excel worksheet functions' (http://www.officekb.com/Uwe/Forums.a...tions/200905/1) HOW TO GET FURTHER HELP WITH A WORKBOOK For further help with it why not join our forums (shown in the link below) it's completely free, if you do join you will have the opportunity to add attachmnets to your posts so you can add workbooks to better illustrate your problems and get help directly with them. Also if you do join please post in this thread (link found below) so that people who have been following or helping with this query can continue to do so. :) -- Pecoflyer Cheers - ------------------------------------------------------------------------ Pecoflyer's Profile: http://www.thecodecage.com/forumz/member.php?userid=14 View this thread: http://www.thecodecage.com/forumz/sh...ad.php?t=92988 |
More than one variable for Countif
Thanks - It did finally remove the #NUM! error but now I am only getting 0's
where I know there should be a count. I need to make sure the values match and then see..........? Alan wrote: You can't use whole columns like J:J, try using a range like J1;J5000 Regards, Alan. Hi - [quoted text clipped - 18 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Carrie_Loos via OfficeKB.com;332825 Wrote: Thanks - It did finally remove the #NUM! error but now I am only getting 0's where I know there should be a count. I need to make sure the values match and then see..........? Alan wrote: You can't use whole columns like J:J, try using a range like J1;J5000 Regards, Alan. Hi - d text clipped - 18 lines Wrote: Thanks for any help -- Message posted via OfficeKB.com 'Excel - using Excel worksheet functions' (http://www.officekb.com/Uwe/Forums.aspx/excel-functions/200905/1) Hi, you can post a sample of your data on our forum if you fel like it -- Pecoflyer Cheers - ------------------------------------------------------------------------ Pecoflyer's Profile: http://www.thecodecage.com/forumz/member.php?userid=14 View this thread: http://www.thecodecage.com/forumz/sh...ad.php?t=92988 |
More than one variable for Countif
You can reference whole columns but only in Excel 2007. Otherwise change the
references to equally fixed ranges. ie J1:J900 & N1:N900 Try this: =SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule! K2)) "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:9596092e4be14@uwe... Hi - Really stumped on this one. I have tried many different formula's using SUMPRODUCT, And, IF in conjunction with Countif but still can't seem to get it to work. I have a worksheet with dates listed down column B called "Schedule". I need to look in another worksheet, find two separate colunms true; if they are both true then count. I continue to get the #NUM! error no matter which way I approach this. Any help would surely be appreciated. Example of the "SUMPRODUCT" approach below [B163 is equal to a date of 06/09/2009 and K2 is equal to a team number of L01 on the worksheet "Schedule"] =SUMPRODUCT('Team Worksheet'!J:J=Schedule!B163,'Team Worksheet'!N:N=Schedule! K2) Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Well - Still can't get it to work, double checked to make sure variable
matched formats ect... The new formula is =SUMPRODUCT('Team Worksheet'!$J$1: $J$5000=Schedule!$B163,'Team Worksheet'!$N$1:$N$5000=Schedule!K$2) but brings back a value of zero. I check and there is at least one that should be counted. Set it up on another worksheet for test, still got zeros???? Per Jessen wrote: Hi =SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule!K2)) The above formula will only work in XL2007. In previous versions, you can not use a range like J:J, but something like J1:J1000. Hopes this helps. Per Hi - [quoted text clipped - 18 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Use the formula supplied by Bassman, it will work,
=SUMPRODUCT(--('Team Worksheet'!J1:J1000=Schedule!B163),--('TeamWorksheet'!N1:N1000=Schedule!K2)) "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:959714f1c0c20@uwe... Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team Worksheet'!$J$1: $J$5000=Schedule!$B163,'Team Worksheet'!$N$1:$N$5000=Schedule!K$2) but brings back a value of zero. I check and there is at least one that should be counted. Set it up on another worksheet for test, still got zeros???? Per Jessen wrote: Hi =SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule!K2)) The above formula will only work in XL2007. In previous versions, you can not use a range like J:J, but something like J1:J1000. Hopes this helps. Per Hi - [quoted text clipped - 18 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Take another look at the formula that Per provided. The double unary
operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:959714f1c0c20@uwe... Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team Worksheet'!$J$1: $J$5000=Schedule!$B163,'Team Worksheet'!$N$1:$N$5000=Schedule!K$2) but brings back a value of zero. I check and there is at least one that should be counted. Set it up on another worksheet for test, still got zeros???? Per Jessen wrote: Hi =SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule!K2)) The above formula will only work in XL2007. In previous versions, you can not use a range like J:J, but something like J1:J1000. Hopes this helps. Per Hi - [quoted text clipped - 18 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Oh, thanks for the insight, I did not know that - I will give it a try
Bassman62 wrote: Take another look at the formula that Per provided. The double unary operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team [quoted text clipped - 23 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Worked beautifully, Thanks
Bassman62 wrote: Take another look at the formula that Per provided. The double unary operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team [quoted text clipped - 23 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Worked beautifully, Thanks
Bassman62 wrote: Take another look at the formula that Per provided. The double unary operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team [quoted text clipped - 23 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Worked beautifully, Thanks
Bassman62 wrote: Take another look at the formula that Per provided. The double unary operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team [quoted text clipped - 23 lines] Thanks for any help -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...tions/200905/1 |
More than one variable for Countif
Have a look at this site http://www.xldynamic.com/source/xld....T.html#classic for a detailed explanation of the sumproduct syntax HTH Bassman62;333015 Wrote: Take another look at the formula that Per provided. The double unary operator "--" coerces the logical "TRUE & FALSE" results of your arrarys into numeric 1 & 0 which is required for the operation. "Carrie_Loos via OfficeKB.com" <u34134@uwe wrote in message news:959714f1c0c20@uwe... Well - Still can't get it to work, double checked to make sure variable matched formats ect... The new formula is =SUMPRODUCT('Team Worksheet'!$J$1: $J$5000=Schedule!$B163,'Team Worksheet'!$N$1:$N$5000=Schedule!K$2) but brings back a value of zero. I check and there is at least one that should be counted. Set it up on another worksheet for test, still got zeros???? Per Jessen wrote: Hi =SUMPRODUCT(--('Team Worksheet'!J:J=Schedule!B163),--('Team Worksheet'!N:N=Schedule!K2)) The above formula will only work in XL2007. In previous versions, you can not use a range like J:J, but something like J1:J1000. Hopes this helps. Per Hi - d text clipped - 18 lines Wrote: Thanks for any help -- Message posted via OfficeKB.com 'Excel - using Excel worksheet functions' (http://www.officekb.com/Uwe/Forums.a...tions/200905/1) -- Pecoflyer Cheers - ------------------------------------------------------------------------ Pecoflyer's Profile: http://www.thecodecage.com/forumz/member.php?userid=14 View this thread: http://www.thecodecage.com/forumz/sh...ad.php?t=92988 |
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