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Mercantile Plumbing calcs
Cell B5 will contain the total Occupant load which is an input I have to
provide because it will vary from job to job. Cell C9 is a value of 500 and will not change. It is the Plumbing Codes ratio of 1-WC plumbing fixture for every 500-people. Cell C13 is the answer from B5 divided by C9 where the numerical value is ROUNDEDUP to the next whole number but with some additional input as addressed below. This cell will be the plumbing fixture count or requirements. Here is the catch for C13 (Note: the same formula will be used in C15); I want C13 to provide several answers as follows: 1. When the total Occupant load in B5 is 50 or less C13 is to read €śUni-sex€ť 2. When the total Occupant load in B5 is 51 or more C13s numerical answer will be derived from (B5C9) x 50%. The answer would be the required number of fixtures to be provided for each sex. If 51 people are the occupant load, then by Code I will be required to have separate sex restrooms. I can divide the total fixture count by half between the sexes once the occupant load is 51 or more. I will have a cell for Men (C13) and Women (C15) with the same formulas. Do not forget that the numerical answer if it contains decimals is to be ROUNDED UP to the next whole number. (ex: 0.01 must be rounded up to 1) Now to another Cell B18; =IF((C13+C15)<6,"N/A","REQUIRED") is the current formula and it will have to be modified to provide three answers as follows. 1. If the occupant load in B5 is 50 or under then B18 should read €śALLOWED€ť and 2. if the occupant load in B5 is 51 or more then B18 should read €śN/A€ť and (See NOTE) 3. if C13+C15 totals 6 or more then B18 should read €śREQUIRED€ť. (See NOTE) NOTE: there maybe a conflict of #1 or #2 with #3 because #3 is totaling fixtures required for Men and Women and #1 or #2 is based on total occupant loads. As the occupant load increases over 51 each sex restroom will have an increase in fixtures base on half of the fixture count used for each sex. Since the numerical value is rounded up then a total occupant load of 2001 will push the aggregate total of Men and Women fixtures to 6 and will invoke the Uni-sex €śREQUIRED€ť. A total occupant load of 2000 will not require uni-sex. I am using this cell to flag when another type of Uni-sex restroom is required. If the total fixture count in Men (C13) + Women (C15) is 6 or more then the Code requires a Uni-sex (Family room) in addition to the separate sex restrooms. I do not need the quotation marks to read. This is different from the Assembly occupancies I receive help on earlier this week. |
Mercantile Plumbing calcs
C13 & C15's formulas:
=IF(B5<=50,"Uni-sex",ROUNDUP(0.5*B5/C9,0)) B18 formula: =IF(B5<=50,"Allowed",IF(SUM(C13,C15)=6,"Required" ,"N/A")) -- Best Regards, Luke M *Remember to click "yes" if this post helped you!* "Codeman" wrote: Cell B5 will contain the total Occupant load which is an input I have to provide because it will vary from job to job. Cell C9 is a value of 500 and will not change. It is the Plumbing Codes ratio of 1-WC plumbing fixture for every 500-people. Cell C13 is the answer from B5 divided by C9 where the numerical value is ROUNDEDUP to the next whole number but with some additional input as addressed below. This cell will be the plumbing fixture count or requirements. Here is the catch for C13 (Note: the same formula will be used in C15); I want C13 to provide several answers as follows: 1. When the total Occupant load in B5 is 50 or less C13 is to read €śUni-sex€ť 2. When the total Occupant load in B5 is 51 or more C13s numerical answer will be derived from (B5C9) x 50%. The answer would be the required number of fixtures to be provided for each sex. If 51 people are the occupant load, then by Code I will be required to have separate sex restrooms. I can divide the total fixture count by half between the sexes once the occupant load is 51 or more. I will have a cell for Men (C13) and Women (C15) with the same formulas. Do not forget that the numerical answer if it contains decimals is to be ROUNDED UP to the next whole number. (ex: 0.01 must be rounded up to 1) Now to another Cell B18; =IF((C13+C15)<6,"N/A","REQUIRED") is the current formula and it will have to be modified to provide three answers as follows. 1. If the occupant load in B5 is 50 or under then B18 should read €śALLOWED€ť and 2. if the occupant load in B5 is 51 or more then B18 should read €śN/A€ť and (See NOTE) 3. if C13+C15 totals 6 or more then B18 should read €śREQUIRED€ť. (See NOTE) NOTE: there maybe a conflict of #1 or #2 with #3 because #3 is totaling fixtures required for Men and Women and #1 or #2 is based on total occupant loads. As the occupant load increases over 51 each sex restroom will have an increase in fixtures base on half of the fixture count used for each sex. Since the numerical value is rounded up then a total occupant load of 2001 will push the aggregate total of Men and Women fixtures to 6 and will invoke the Uni-sex €śREQUIRED€ť. A total occupant load of 2000 will not require uni-sex. I am using this cell to flag when another type of Uni-sex restroom is required. If the total fixture count in Men (C13) + Women (C15) is 6 or more then the Code requires a Uni-sex (Family room) in addition to the separate sex restrooms. I do not need the quotation marks to read. This is different from the Assembly occupancies I receive help on earlier this week. |
Mercantile Plumbing calcs
Those all worked thanks.
However, two other Cells (B19 & D19) that are linked to results occurring in C13 & 15 changed. I did not think it would be affected but it did. =IF((C13)<6,"N/A","REQUIRED") is the formula in Cell B19 What changed is when C13 provides the answer €śUni-sex€ť B19 listed €śREQUIRED€ť. It should list €śN/A€ť. After testing some numbers in B5 it is related to the 50 or less. When the occupant load is 50 or less in B5 then B19 should also read €śN/A€ť. What is happening B19 reads Uni-sex in C13 which is not a number and provides the incorrect answer. Is there a way to get B19s formula to read €śUni-sex€ť in C13 and provide the €śN/A€ť in addition to reading when 6 or more occur to read €śREQUIRED€ť? This is the Ambulatory stall which is required when a total of 6 fixtures or more occur in a separate sex restroom. The difference is Ambulatory is not an aggregate of fixtures for the separate sex restrooms as was the Uni-sex. |
Mercantile Plumbing calcs
C19 formula:
=IF(SUM(C13)<6,"N/A","REQUIRED") Since SUM treats texts as equal to zero, this still works. NOte that if you want more control, could change this to: =IF(OR(C13="Uni-sex",C13<6),"N/A","REQUIRED") First formula is 2 calculation steps faster. -- Best Regards, Luke M *Remember to click "yes" if this post helped you!* "Codeman" wrote: Those all worked thanks. However, two other Cells (B19 & D19) that are linked to results occurring in C13 & 15 changed. I did not think it would be affected but it did. =IF((C13)<6,"N/A","REQUIRED") is the formula in Cell B19 What changed is when C13 provides the answer €śUni-sex€ť B19 listed €śREQUIRED€ť. It should list €śN/A€ť. After testing some numbers in B5 it is related to the 50 or less. When the occupant load is 50 or less in B5 then B19 should also read €śN/A€ť. What is happening B19 reads Uni-sex in C13 which is not a number and provides the incorrect answer. Is there a way to get B19s formula to read €śUni-sex€ť in C13 and provide the €śN/A€ť in addition to reading when 6 or more occur to read €śREQUIRED€ť? This is the Ambulatory stall which is required when a total of 6 fixtures or more occur in a separate sex restroom. The difference is Ambulatory is not an aggregate of fixtures for the separate sex restrooms as was the Uni-sex. |
Mercantile Plumbing calcs
It is the Plumbing Codes
ratio of 1-WC plumbing fixture for every 500-people. Wow, you would neeed security on the door and bookings by appointment only. Cheers Martin "Codeman" wrote in message ... Cell B5 will contain the total Occupant load which is an input I have to provide because it will vary from job to job. Cell C9 is a value of 500 and will not change. It is the Plumbing Codes ratio of 1-WC plumbing fixture for every 500-people. Cell C13 is the answer from B5 divided by C9 where the numerical value is ROUNDEDUP to the next whole number but with some additional input as addressed below. This cell will be the plumbing fixture count or requirements. Here is the catch for C13 (Note: the same formula will be used in C15); I want C13 to provide several answers as follows: 1. When the total Occupant load in B5 is 50 or less C13 is to read €śUni-sex€ť 2. When the total Occupant load in B5 is 51 or more C13s numerical answer will be derived from (B5C9) x 50%. The answer would be the required number of fixtures to be provided for each sex. If 51 people are the occupant load, then by Code I will be required to have separate sex restrooms. I can divide the total fixture count by half between the sexes once the occupant load is 51 or more. I will have a cell for Men (C13) and Women (C15) with the same formulas. Do not forget that the numerical answer if it contains decimals is to be ROUNDED UP to the next whole number. (ex: 0.01 must be rounded up to 1) Now to another Cell B18; =IF((C13+C15)<6,"N/A","REQUIRED") is the current formula and it will have to be modified to provide three answers as follows. 1. If the occupant load in B5 is 50 or under then B18 should read €śALLOWED€ť and 2. if the occupant load in B5 is 51 or more then B18 should read €śN/A€ť and (See NOTE) 3. if C13+C15 totals 6 or more then B18 should read €śREQUIRED€ť. (See NOTE) NOTE: there maybe a conflict of #1 or #2 with #3 because #3 is totaling fixtures required for Men and Women and #1 or #2 is based on total occupant loads. As the occupant load increases over 51 each sex restroom will have an increase in fixtures base on half of the fixture count used for each sex. Since the numerical value is rounded up then a total occupant load of 2001 will push the aggregate total of Men and Women fixtures to 6 and will invoke the Uni-sex €śREQUIRED€ť. A total occupant load of 2000 will not require uni-sex. I am using this cell to flag when another type of Uni-sex restroom is required. If the total fixture count in Men (C13) + Women (C15) is 6 or more then the Code requires a Uni-sex (Family room) in addition to the separate sex restrooms. I do not need the quotation marks to read. This is different from the Assembly occupancies I receive help on earlier this week. |
Mercantile Plumbing calcs
Thank you Luke M.
Martin W, the 1:500 is for Mercantile Occupancies. Other Occupancies have much tighter ratios. Mercantile generally have large square footage from wich the occupant load is based. EX: Ground floor occupant load is 1 person per 60 sq ft of gross floor area. The Occupant load adds up and not everyone in a store is going to the restroom at one time as they would in an Assembly Occupancy during intermissions. Assembly Occupancy loads are base on net used floor area of fixed seating. |
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