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#1
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I need a function that would count how many are odd/even numbers in a row or
column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#2
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For even numbers
=SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) for odd =SUMPRODUCT(--(MOD(A1:J1,2)=1),--(ISNUMBER(A1:J1))) -- Regards, Peo Sjoblom "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#3
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![]() Thanks Peo, i just tried your suggestion and did not work. Do I have to key in _ _ between brackets? Thanks heaps -- RodJ "Peo Sjoblom" wrote: For even numbers =SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) for odd =SUMPRODUCT(--(MOD(A1:J1,2)=1),--(ISNUMBER(A1:J1))) -- Regards, Peo Sjoblom "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#4
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Thanks so much...it did work after i used --.
Wonderful . i really appreciate this....wow...what a great community... -- RodJ "Peo Sjoblom" wrote: For even numbers =SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) for odd =SUMPRODUCT(--(MOD(A1:J1,2)=1),--(ISNUMBER(A1:J1))) -- Regards, Peo Sjoblom "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#5
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=SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1)))
the "--ISNUMBER (A1:J1)" in your formula won't do any good. If one of the cell contain text value, your formula still returns #VALUE! error. The *array* formula below ignore any text value =SUM(IF(ISNUMBER(A1:J1),IF(MOD(A1:J1,2)=1,1))) *ctrl+shift+enter*, not just enter "Peo Sjoblom" wrote: For even numbers =SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) for odd =SUMPRODUCT(--(MOD(A1:J1,2)=1),--(ISNUMBER(A1:J1))) -- Regards, Peo Sjoblom "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#6
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It will not count blank cells, that was the reason not to avoid text, or
else they will be counted as even (0) -- Regards, Peo Sjoblom "Teethless mama" wrote in message ... =SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) the "--ISNUMBER (A1:J1)" in your formula won't do any good. If one of the cell contain text value, your formula still returns #VALUE! error. The *array* formula below ignore any text value =SUM(IF(ISNUMBER(A1:J1),IF(MOD(A1:J1,2)=1,1))) *ctrl+shift+enter*, not just enter "Peo Sjoblom" wrote: For even numbers =SUMPRODUCT(--(MOD(A1:J1,2)=0),--(ISNUMBER(A1:J1))) for odd =SUMPRODUCT(--(MOD(A1:J1,2)=1),--(ISNUMBER(A1:J1))) -- Regards, Peo Sjoblom "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
#7
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Hi,
Try this array formula (Ctrl+Shift+Enter) =COUNT(IF((MOD(A1:E1,2)<0),A1:E1)) -- Regards, Ashsih Mathur Microsoft Excel MVP www.ashishmathur.com "RodJ" wrote in message ... I need a function that would count how many are odd/even numbers in a row or column. eg: 1,3,6,22,35 = this row has 3 odd and 2 even numbers. Is there a function that can count this for me. Thanks RodJ |
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