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how many inbedded if statements can i have?
Here's my functional formula
=IF(OR(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,(SUM(O16:O18))=7),2,IF(AND(O13=2,O14=2 ,O15=2,(SUM(O16:O18))=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,(SUM(O16:O18))=9),"B tw Red & Grn","not an ans")))))) and it return the results I want, but I needed one more condition and it gives me the "formula contains errors" message. I just want to add the following that works on it's own.... IF((AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1)),1, so is there a limit to how many true statements you can have? Thanks |
how many inbedded if statements can i have?
Hi
You can have up to 7 levels of IF's in one formula - without branching them it leaves you with 8 different options. The condition you want to add will never occur, because the 1st condition in your current formula will be fired before. Generally, possible formulas will be (LE# - logical expression): =IF(LE1,Resp1,IF(LE2,resp2,IF(LE3,resp3,IF(LE4,res p4,IF(LE5,Resp5,IF(LE6,Resp6,IF(LE7,Resp7,Resp8))) )))) With branching (BC - branching condition): =IF(BC,IF(LE1,Resp1,IF(LE2,resp2,IF(LE3,resp3,IF(L E4,resp4,IF(LE5,Resp5,IF(LE6,Resp6,Resp7)))))),IF( LE8,Resp8,IF(LE9,resp9,IF(LE10,resp10,IF(LE11,resp 11,IF(LE12,Resp12,IF(LE13,Resp13,Resp14))))))) With numeric responses you can avoid 7-level limit using formula like: =(LE1)*Resp1+(LE2)*Resp2+... -- Arvi Laanemets ( My real mail address: arvi.laanemets<attarkon.ee ) "Brooke" wrote in message ... Here's my functional formula =IF(OR(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,(SUM(O16:O18))=7),2,IF(AND(O13=2,O14=2 ,O15=2,(SUM(O16:O18))=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,(SUM(O16:O18))=9),"B tw Red & Grn","not an ans")))))) and it return the results I want, but I needed one more condition and it gives me the "formula contains errors" message. I just want to add the following that works on it's own.... IF((AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1)),1, so is there a limit to how many true statements you can have? Thanks |
how many inbedded if statements can i have?
Will any of the cells in the range O16:O18 ever contain TEXT or will they
*always* contain a number or be *EMPTY* ? -- Biff Microsoft Excel MVP "Brooke" wrote in message ... Here's my functional formula =IF(OR(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,(SUM(O16:O18))=7),2,IF(AND(O13=2,O14=2 ,O15=2,(SUM(O16:O18))=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,(SUM(O16:O18))=9),"B tw Red & Grn","not an ans")))))) and it return the results I want, but I needed one more condition and it gives me the "formula contains errors" message. I just want to add the following that works on it's own.... IF((AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1)),1, so is there a limit to how many true statements you can have? Thanks |
how many inbedded if statements can i have?
The condition you want to add will never occur, because the 1st condition
in your current formula will be fired before. It will occur *if* you make it the first condition. You would want to test *all* cells for 1 first, then test *any* cells for 1. =IF(COUNTIF(O13:O18,1)=6,1,IF(COUNTIF(O13:O18,1)," Need to answer all statements"........ -- Biff Microsoft Excel MVP "Arvi Laanemets" wrote in message ... Hi You can have up to 7 levels of IF's in one formula - without branching them it leaves you with 8 different options. The condition you want to add will never occur, because the 1st condition in your current formula will be fired before. Generally, possible formulas will be (LE# - logical expression): =IF(LE1,Resp1,IF(LE2,resp2,IF(LE3,resp3,IF(LE4,res p4,IF(LE5,Resp5,IF(LE6,Resp6,IF(LE7,Resp7,Resp8))) )))) With branching (BC - branching condition): =IF(BC,IF(LE1,Resp1,IF(LE2,resp2,IF(LE3,resp3,IF(L E4,resp4,IF(LE5,Resp5,IF(LE6,Resp6,Resp7)))))),IF( LE8,Resp8,IF(LE9,resp9,IF(LE10,resp10,IF(LE11,resp 11,IF(LE12,Resp12,IF(LE13,Resp13,Resp14))))))) With numeric responses you can avoid 7-level limit using formula like: =(LE1)*Resp1+(LE2)*Resp2+... -- Arvi Laanemets ( My real mail address: arvi.laanemets<attarkon.ee ) "Brooke" wrote in message ... Here's my functional formula =IF(OR(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,(SUM(O16:O18))=7),2,IF(AND(O13=2,O14=2 ,O15=2,(SUM(O16:O18))=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,(SUM(O16:O18))=9),"B tw Red & Grn","not an ans")))))) and it return the results I want, but I needed one more condition and it gives me the "formula contains errors" message. I just want to add the following that works on it's own.... IF((AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1)),1, so is there a limit to how many true statements you can have? Thanks |
how many inbedded if statements can i have?
Try this *assuming O16:O18 will never contain TEXT* :
=IF(COUNTIF(O13:O18,1)=6,1,IF(COUNTIF(O13:O18,1)," Need to answer all statements",IF(COUNTIF(O13:O18,2)=6,2,IF(COUNTIF(O 13:O15,3),3,IF(AND(O13=2,O14=2,O15=2,O16+O17+O18=7 ),2,IF(AND(O13=2,O14=2,O15=2,OR(O16+O17+O18={8,9}) ),"Btw Red & Grn","not an ans")))))) -- Biff Microsoft Excel MVP "T. Valko" wrote in message ... Will any of the cells in the range O16:O18 ever contain TEXT or will they *always* contain a number or be *EMPTY* ? -- Biff Microsoft Excel MVP "Brooke" wrote in message ... Here's my functional formula =IF(OR(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,(SUM(O16:O18))=7),2,IF(AND(O13=2,O14=2 ,O15=2,(SUM(O16:O18))=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,(SUM(O16:O18))=9),"B tw Red & Grn","not an ans")))))) and it return the results I want, but I needed one more condition and it gives me the "formula contains errors" message. I just want to add the following that works on it's own.... IF((AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1)),1, so is there a limit to how many true statements you can have? Thanks |
Quote:
IF(AND(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),1,IF(O R(O13=1,O14=1,O15=1,O16=1,O17=1,O18=1),"Need to answer all statements",IF(AND(O13=2,O14=2,O15=2,O16=2,O17=2,O 18=2),2,IF(OR(O13=3,O14=3,O15=3),"3",IF(AND(O13=2, O14=2,O15=2,O16+O17+O18=7),2,IF(AND(O13=2,O14=2,O1 5=2,O16+O17+O18=8),"Btw Red & Grn",IF(AND(O13=2,O14=2,O15=2,O16+O17+O18=9),"B tw Red & Grn","not an ans"))))))) which incorporated your extra "if". regards Howard |
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