#DIV/0! error
I am using the formula
=(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
You could do it this way:
=IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,"",SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales)/ SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) i.e. if the denominator is zero then return a blank, otherwise do the calculation. You can change the "" in the middle to 0 if you wish. Another way would be to use: =IF(ISERROR(your_formula),"",your_formula) though this would trap all errors. Hope this helps. Pete On Dec 7, 3:08 pm, Curtis wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
Hi Curtis,
Change your formula as =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,0,=(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)) Basically I am checking if the later formula is resulting in zero before using it in the division. HTH, -- Pranav Vaidya VBA Developer PN, MH-India If you think my answer is useful, please rate this post as an ANSWER!! "Curtis" wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
Thanks
Is there a way to exclude cells with the #DIV/0! error when using the sum function example =SUM(C41:H41) "Pete_UK" wrote: You could do it this way: =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,"",SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales)/ SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) i.e. if the denominator is zero then return a blank, otherwise do the calculation. You can change the "" in the middle to 0 if you wish. Another way would be to use: =IF(ISERROR(your_formula),"",your_formula) though this would trap all errors. Hope this helps. Pete On Dec 7, 3:08 pm, Curtis wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
if you use 0 instead of "" in the IF(), the automatically there will be no
cells with #DIV/0. HTH, -- Pranav Vaidya VBA Developer PN, MH-India If you think my answer is useful, please rate this post as an ANSWER!! "Curtis" wrote: Thanks Is there a way to exclude cells with the #DIV/0! error when using the sum function example =SUM(C41:H41) "Pete_UK" wrote: You could do it this way: =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,"",SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales)/ SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) i.e. if the denominator is zero then return a blank, otherwise do the calculation. You can change the "" in the middle to 0 if you wish. Another way would be to use: =IF(ISERROR(your_formula),"",your_formula) though this would trap all errors. Hope this helps. Pete On Dec 7, 3:08 pm, Curtis wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
=SUMIF(C41:H41,"<"&99^99)
-- Regards, Peo Sjoblom "Curtis" wrote in message ... Thanks Is there a way to exclude cells with the #DIV/0! error when using the sum function example =SUM(C41:H41) "Pete_UK" wrote: You could do it this way: =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,"",SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales)/ SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) i.e. if the denominator is zero then return a blank, otherwise do the calculation. You can change the "" in the middle to 0 if you wish. Another way would be to use: =IF(ISERROR(your_formula),"",your_formula) though this would trap all errors. Hope this helps. Pete On Dec 7, 3:08 pm, Curtis wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
Thanks
"Pranav Vaidya" wrote: Hi Curtis, Change your formula as =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,0,=(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)) Basically I am checking if the later formula is resulting in zero before using it in the division. HTH, -- Pranav Vaidya VBA Developer PN, MH-India If you think my answer is useful, please rate this post as an ANSWER!! "Curtis" wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks |
#DIV/0! error
If you use the formula I gave you to return either "" or 0, then this
will not have any effect on the SUM formula, so they will be ignored. Pete On Dec 7, 3:30 pm, Curtis wrote: Thanks Is there a way to exclude cells with the #DIV/0! error when using the sum function example =SUM(C41:H41) "Pete_UK" wrote: You could do it this way: =IF(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO)=0,"",SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales)/ SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) i.e. if the denominator is zero then return a blank, otherwise do the calculation. You can change the "" in the middle to 0 if you wish. Another way would be to use: =IF(ISERROR(your_formula),"",your_formula) though this would trap all errors. Hope this helps. Pete On Dec 7, 3:08 pm, Curtis wrote: I am using the formula =(SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!sales))/SUMIF('Tech Ops Data Base 2007.xls'!TechallDate,C$36&$A37,'Tech Ops Data Base 2007.xls'!salesWO) However in some causes I am receiving the following error #DIV/0!. Is there anything I can do to the above formula to remove that error thanks- Hide quoted text - - Show quoted text - |
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