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Indirect function result in #REF
Hi,
I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules |
Indirect function result in #REF
Try it as: =INDIRECT("A3")
-- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "Julie L" wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules |
Indirect function result in #REF
=Indirect() expects something that looks like a range address/range name in that
cell. So if A3 contained X99, then =indirect(a3) would return the value contained in X99. Julie L wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules -- Dave Peterson |
Indirect function result in #REF
Thank you Dave, I now understand what created the problem. Reference in
indirect should refer to an address, therefore, if a3 contains 3, the result would be too volatile since excel is trying to pick up all information from row 3. Thanks for the info! Jules "Dave Peterson" wrote: =Indirect() expects something that looks like a range address/range name in that cell. So if A3 contained X99, then =indirect(a3) would return the value contained in X99. Julie L wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules -- Dave Peterson |
Indirect function result in #REF
And "3" isn't a valid range address, either.
But if you had '3:3 (make sure it's text and not a time!) in A1, then you could use: =sum(indirect(a1)) to add up all the values in row 3. Julie L wrote: Thank you Dave, I now understand what created the problem. Reference in indirect should refer to an address, therefore, if a3 contains 3, the result would be too volatile since excel is trying to pick up all information from row 3. Thanks for the info! Jules "Dave Peterson" wrote: =Indirect() expects something that looks like a range address/range name in that cell. So if A3 contained X99, then =indirect(a3) would return the value contained in X99. Julie L wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules -- Dave Peterson -- Dave Peterson |
Indirect function result in #REF
Thanks for the insightful explanation!
Jules "Dave Peterson" wrote: And "3" isn't a valid range address, either. But if you had '3:3 (make sure it's text and not a time!) in A1, then you could use: =sum(indirect(a1)) to add up all the values in row 3. Julie L wrote: Thank you Dave, I now understand what created the problem. Reference in indirect should refer to an address, therefore, if a3 contains 3, the result would be too volatile since excel is trying to pick up all information from row 3. Thanks for the info! Jules "Dave Peterson" wrote: =Indirect() expects something that looks like a range address/range name in that cell. So if A3 contained X99, then =indirect(a3) would return the value contained in X99. Julie L wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules -- Dave Peterson -- Dave Peterson |
Indirect function result in #REF
Thanks for the information Max!
"Max" wrote: Try it as: =INDIRECT("A3") -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "Julie L" wrote: Hi, I tried to use the indirect function (i.e. indirect(A3)) where A3 contains a number (say 3), but the result came back as #REF. Any idea what caused the problem. Thanks, Jules |
Indirect function result in #REF
welcome, Julie. Thanks for the liner
-- Max Singapore http://savefile.com/projects/236895 xdemechanik --- "Julie L" wrote in message ... Thanks for the information Max! |
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