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I have a street database that contains 9 columns. Not all of them will be
used on each record. Here's my problem. I have a column named ST_NAME and a column named OID that have all my information in them. It's set up like this: ST_NAME OID STREET_2 STREET_3 STREET_4 Leigh cv 22 Mays ln 22 Stoneridge 22 Russell 54 Makala 54 Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. |
#2
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On Oct 16, 7:16 am, Jennifer Andrews <Jennifer
wrote: Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. I am not sure I understand the assumptions you can make and the result that you want, but I wonder if the following helps. Assume ST_NAME, OID, STREET_2, STREET_3 and STREET_4 are columns A, B, C, D and E, and assume "Leigh cv" is in row 2. Insert the following formulas and copy them down their columns: C2: if(and(B1<B2,B2=B3), A3, "") D2: if(and(B1<B2,B2=B4), A4, "") E2: if(and(B1<B2,B2=B5), A5, "") Thus, in the first row with a new OID, STREET_2, STREET_3 and STREET_4 will contain up to the next 3 adjacent street names with the same OID. Those columns will remain blank in the non-first rows with the same OID. ----- complete original posting ----- On Oct 16, 7:16 am, Jennifer Andrews <Jennifer wrote: I have a street database that contains 9 columns. Not all of them will be used on each record. Here's my problem. I have a column named ST_NAME and a column named OID that have all my information in them. It's set up like this: ST_NAME OID STREET_2 STREET_3 STREET_4 Leigh cv 22 Mays ln 22 Stoneridge 22 Russell 54 Makala 54 Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. |
#3
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Don't know about functions, but it is simple with a macro
Public Sub ProcessData() Dim i As Long Dim iLastRow As Long With ActiveSheet iLastRow = .Cells(.Rows.Count, "A").End(xlUp).Row For i = iLastRow To 2 Step -1 If .Cells(i, "B").Value = .Cells(i - 1, "B").Value Then .Cells(i, "C").Resize(, 2).Copy .Cells(i, "D") .Cells(i, "A").Copy .Cells(i, "C") .Cells(i, "C").Resize(, 3).Copy .Cells(i - 1, "C") .Rows(i).Delete End If Next i End With End Sub -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jennifer Andrews" <Jennifer wrote in message ... I have a street database that contains 9 columns. Not all of them will be used on each record. Here's my problem. I have a column named ST_NAME and a column named OID that have all my information in them. It's set up like this: ST_NAME OID STREET_2 STREET_3 STREET_4 Leigh cv 22 Mays ln 22 Stoneridge 22 Russell 54 Makala 54 Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. |
#4
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Vacation?<bg
-- Regards, RD ----------------------------------------------------------------------------------------------- Please keep all correspondence within the Group, so all may benefit ! ----------------------------------------------------------------------------------------------- "Bob Phillips" wrote in message ... Don't know about functions, but it is simple with a macro Public Sub ProcessData() Dim i As Long Dim iLastRow As Long With ActiveSheet iLastRow = .Cells(.Rows.Count, "A").End(xlUp).Row For i = iLastRow To 2 Step -1 If .Cells(i, "B").Value = .Cells(i - 1, "B").Value Then .Cells(i, "C").Resize(, 2).Copy .Cells(i, "D") .Cells(i, "A").Copy .Cells(i, "C") .Cells(i, "C").Resize(, 3).Copy .Cells(i - 1, "C") .Rows(i).Delete End If Next i End With End Sub -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jennifer Andrews" <Jennifer wrote in message ... I have a street database that contains 9 columns. Not all of them will be used on each record. Here's my problem. I have a column named ST_NAME and a column named OID that have all my information in them. It's set up like this: ST_NAME OID STREET_2 STREET_3 STREET_4 Leigh cv 22 Mays ln 22 Stoneridge 22 Russell 54 Makala 54 Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. |
#5
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And one solution with formulas, for the fun...
Assume ST_NAME, OID in row 1, A1:B1, streets start on A2, OID's on B2. Place all the OID's successively. E.g. 22 in F2, 54 in F3. Start in G2 with this *array* formula: =IF(COUNTIF($B$2:$B$6,$F2)=COLUMNS($G$1:G1),INDEX ($A$2:$A $6,SMALL(IF($B$2:$B$6=$F2,ROW($A$2:$A$6)-ROW($A$2)+1),COLUMNS($G $1:G1))),"") As an array formula it must be committed with Shift+Ctrl+Enter. Now, copy down and across to suit. HTH Kostis Vezerides On Oct 16, 5:16 pm, Jennifer Andrews <Jennifer wrote: I have a street database that contains 9 columns. Not all of them will be used on each record. Here's my problem. I have a column named ST_NAME and a column named OID that have all my information in them. It's set up like this: ST_NAME OID STREET_2 STREET_3 STREET_4 Leigh cv 22 Mays ln 22 Stoneridge 22 Russell 54 Makala 54 Where the OID are all the same, each of those streets need to be placed in a seperate street column, instead of all being under ST_NAME. Leigh cv, Mays Ln, and Stoneridge should occupy ST_NAME, STREET_2, and STREET_3 all in the same row. I'm not sure how to set up functions for this. |
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