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![]() For some reason I can't figure this one out. What's the most elegant way to sum up a list of numbers according to a binary truth table? To start with, here's an example of the raw data: C B A Combo Numbers N N N None 42 N N Y A only 23 N Y N B only 16 N Y Y A & B 26 Y N N C only 20 Y N Y A & C 11 Y Y N B & C 10 Y Y Y All 51 But now I want to add up all the rows in which, e.g. B has any part, like so: C B A Combo Numbers N N Y A any 23+26+11+51=111 N Y N B any 16+26+10+51=103 N Y Y A & B 26+51=77 Y N N C any 20+11+10+51=92 Y N Y A & C 11+51=62 Y Y N B & C 10+51=61 Y Y Y All 51 I thought this would be easy, but I can't get my head around it. I'm willing to change Y/N to binary TRUE/FALSE or 1/0 if it will make an elegant function, but what function will best read the list above to make the list below? -- Del Cotter NB Personal replies to this post will send email to , which goes to a spam folder-- please send your email to del3 instead. |
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