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Index Lookup Question
I am working on an index function to pull the first two letters out of a part
number and put them into pivot table and return a result, Here is what my part numbers look like : PA01000P PA01100P Here is what my formula looks like : =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",TaxGroup,0)) Tax Group is my pivot table which looks like this : A B PA P1COMPBR PB P1COMPBR PC P1PRESTO My match function is working perfectly and returns the first to letters, but im loosing it in the index function. When I run the function help menu it tells me MATCH(LEFT('Inventory Master'!P11,2)&"*",TaxGroup,0) = #N/A I have my table sorted by ascending and it is in text format ??? Any help would sure be appreciated |
Index Lookup Question
On Aug 29, 1:50 pm, Noncentz303
wrote: I am working on an index function to pull the first two letters out of a part number and put them into pivot table and return a result, Here is what my part numbers look like : PA01000P PA01100P Here is what my formula looks like : =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",TaxGroup,0)) Tax Group is my pivot table which looks like this : A B PA P1COMPBR PB P1COMPBR PC P1PRESTO My match function is working perfectly and returns the first to letters, but im loosing it in the index function. When I run the function help menu it tells me MATCH(LEFT('Inventory Master'!P11,2)&"*",TaxGroup,0) = #N/A I have my table sorted by ascending and it is in text format ??? Any help would sure be appreciated Why not try Vlookup =Vllookup((LEFT('Inventory Master'!P11,2),taxgroup,2,false) assuming taxgroup is the range name for following A B PA P1COMPBR PB P1COMPBR PC P1PRESTO |
Index Lookup Question
The problem is that the lookup_array "TaxGroup" is a 2 dimensional array.
The lookup_array *must* be a 1 dimensional array (a single row or single column). Also, you haven't defined the column number in the INDEX function. Try this: =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",INDEX(TaxGroup,,1),0),2) -- Biff Microsoft Excel MVP "Noncentz303" wrote in message ... I am working on an index function to pull the first two letters out of a part number and put them into pivot table and return a result, Here is what my part numbers look like : PA01000P PA01100P Here is what my formula looks like : =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",TaxGroup,0)) Tax Group is my pivot table which looks like this : A B PA P1COMPBR PB P1COMPBR PC P1PRESTO My match function is working perfectly and returns the first to letters, but im loosing it in the index function. When I run the function help menu it tells me MATCH(LEFT('Inventory Master'!P11,2)&"*",TaxGroup,0) = #N/A I have my table sorted by ascending and it is in text format ??? Any help would sure be appreciated |
Index Lookup Question
2 answers within 5 minutes with 2 DANG good results .... Thanks all
"T. Valko" wrote: The problem is that the lookup_array "TaxGroup" is a 2 dimensional array. The lookup_array *must* be a 1 dimensional array (a single row or single column). Also, you haven't defined the column number in the INDEX function. Try this: =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",INDEX(TaxGroup,,1),0),2) -- Biff Microsoft Excel MVP "Noncentz303" wrote in message ... I am working on an index function to pull the first two letters out of a part number and put them into pivot table and return a result, Here is what my part numbers look like : PA01000P PA01100P Here is what my formula looks like : =INDEX(TaxGroup,MATCH(LEFT('Inventory Master'!P2,2)&"*",TaxGroup,0)) Tax Group is my pivot table which looks like this : A B PA P1COMPBR PB P1COMPBR PC P1PRESTO My match function is working perfectly and returns the first to letters, but im loosing it in the index function. When I run the function help menu it tells me MATCH(LEFT('Inventory Master'!P11,2)&"*",TaxGroup,0) = #N/A I have my table sorted by ascending and it is in text format ??? Any help would sure be appreciated |
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