![]() |
GROWTH too aggressive, TREND too conservative - what to do?
I am working on projecting some data that is non-linear. the TREND function
gives me a line that is too conservative in its estimates, but GROWTH gives me an exponential line that is way too aggressive. Is there another function I can use? Can I combine these functions meaningfully? Is there a way to tweak GROWTH to be less aggressive? Any other ideas? |
GROWTH too aggressive, TREND too conservative - what to do?
Brett L. <Brett wrote...
I am working on projecting some data that is non-linear. the TREND function gives me a line that is too conservative in its estimates, but GROWTH gives me an exponential line that is way too aggressive. Idle curiosity: which gives the higher R-squared value? Is there another function I can use? Assuming you have one y series and one x series, there are other functional forms you could try. General ones, Polynomials: y = a + b x + c x^2 + d x^3 + . . . =LINEST(y,x^{1,2,3,...}) Hoerl curves: y = a x^b exp(c x) =LINEST(LN(y),LN(x)*{1,0}+x*{0,1}) There's also logistic regression. =LINEST(LN(y/(1-y)),x) Can I combine these functions meaningfully? You could always average the two, but that'd be pure ad hoc without a shred of theoretical support. Even so, it may serve your needs adequately. Is there a way to tweak GROWTH to be less aggressive? Not without transformingadjusting either x or y series. |
GROWTH too aggressive, TREND too conservative - what to do?
"Harlan Grove" wrote:
.... Assuming you have one y series and one x series, there are other functional forms you could try. General ones, Polynomials: y = a + b x + c x^2 + d x^3 + . . . =LINEST(y,x^{1,2,3,...}) .... which can be projected by TREND as =TREND(y,known_x^{1,2,3,...},new_x^{1,2,3,...}) Jerry |
All times are GMT +1. The time now is 02:27 PM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com