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#1
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count unique with mulitple criteria
I have a list of data.
Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#2
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count unique with mulitple criteria
one way
=SUMPRODUCT((B2:B22="job1")*1)-MIN(SUMPRODUCT((B2:B22="job1")*(A2:A22="unfilled") ),1) -- Don Guillett SalesAid Software "ellebelle" wrote in message ... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#3
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count unique with mulitple criteria
Don,
This doesn't work with mutliples of Name/Job combinations. Bernie MS Excel MVP "Don Guillett" wrote in message ... one way =SUMPRODUCT((B2:B22="job1")*1)-MIN(SUMPRODUCT((B2:B22="job1")*(A2:A22="unfilled") ),1) -- Don Guillett SalesAid Software "ellebelle" wrote in message ... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#5
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count unique with mulitple criteria
Don,
" i do not want to count Alex twice" Bernie I thought the question was for a total of all jobs but only counting unfilled once. So, where does is fail?? |
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#6
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count unique with mulitple criteria
Ahhhhhhhhhhhhhhhh, I read it the other way.
-- Don Guillett SalesAid Software "Bernie Deitrick" <deitbe @ consumer dot org wrote in message ... Don, " i do not want to count Alex twice" Bernie I thought the question was for a total of all jobs but only counting unfilled once. So, where does is fail?? |
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#7
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count unique with mulitple criteria
Try this
=SUMPRODUCT((A1:A7="Unfilled")*(B1:B7="JOB1"))+SUM PRODUCT((A1:A7<"Unfilled")*(B1:B7="JOB1")*(1/COUNTIF(A1:A7,A1:A7))) "ellebelle" wrote: I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#8
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count unique with mulitple criteria
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#9
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count unique with mulitple criteria
Ellen,
Using extra columns of helper formulas will work, given your criteria.... With your list in A2:B100 In C2, copied down to C100 =A2&B2 In D2, copied down to D100 =IF(AND(B2="Job1",COUNTIF($C$2:C2,C2)=1),C2,IF(AND (A2="Unfilled",B2="Job1"),C2,"NO")) Then here's your desired result: =COUNTA(D2:D100)-COUNTIF(D2:D100,"NO") You can hide columns C and D or move them off to the right, if you want, to make the view less cluttered.... HTH, Bernie MS Excel MVP "ellebelle" wrote in message ... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#10
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count unique with mulitple criteria
Very expensive, but maybe...
Assuming that that A2:B8 contains the data, let D2 and D3 contain JOB1 and JOB2. Then try... E2, copied down: =SUM(IF(FREQUENCY(IF(B$2:B$8=D2,MATCH(A$2:A$8,A$2: A$8,0)+IF(A$2:A$8="Unfi lled",ROW(A$2:A$8)/10^5)),IF(B$2:B$8=D2,MATCH(A$2:A$8,A$2:A$8,0)+IF(A $2:A $8="Unfilled",ROW(A$2:A$8)/10^5))),1)) Note that the formula needs to be confirmed with CONTROL+SHIFT+ENTER, not just ENTER. Hope this helps! In article , ellebelle wrote: I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen |
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#11
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count unique with mulitple criteria
"ellebelle" skrev i en meddelelse
... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. Any help appreciated, Ellen Hi Ellen One way with a helper column: Assuming data in A2:B100, and job to search for in E1. In C2 enter A2&B2 Copy C2 down to C3:C100 In some cell: =SUMPRODUCT((COUNTIF(OFFSET(C2:C100,,,ROW(C2:C100)-ROW(C2)+1), C2:C100)=1)*(B2:B100=E1))+MAX(COUNTIF(C2:C100,"Unf illed"&E1)-1,0) -- Best regards Leo Heuser Followup to newsgroup only please. |
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#12
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count unique with mulitple criteria
ellebelle wrote...
I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I'll assume this is a 2-column range with defined name TBL. I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. No ancillary cells needed. If the job code sought were entered in a cell named JOB, try the following array formula. =COUNT(1/(INDEX(TBL,0,2)=JOB)/(IF(INDEX(TBL,0,1)="Unfilled",ROW(TBL), MATCH(INDEX(TBL,0,1),INDEX(TBL,0,1),0)-1+MIN(ROW(TBL))=ROW(TBL)))) |
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#13
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count unique with mulitple criteria
In article om,
"Harlan Grove" wrote: ellebelle wrote... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I'll assume this is a 2-column range with defined name TBL. I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. No ancillary cells needed. If the job code sought were entered in a cell named JOB, try the following array formula. =COUNT(1/(INDEX(TBL,0,2)=JOB)/(IF(INDEX(TBL,0,1)="Unfilled",ROW(TBL), MATCH(INDEX(TBL,0,1),INDEX(TBL,0,1),0)-1+MIN(ROW(TBL))=ROW(TBL)))) If the data can contain the following... Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB2 <--- Alex JOB1 <--- ....I believe the unique count should be 4. If this is correct, the above formula will fail and return 3. Similar to the above formula, mine can be shortened to... =COUNT(1/FREQUENCY(IF(B$2:B$8=D2,IF(A$2:A$8="Unfilled",ROW( A$2:A$8)-ROW(A $2)+1,MATCH(A$2:A$8,A$2:A$8,0))),ROW(A$2:A$8)-ROW(A$2)+1)) ....confirmed with CONTROL+SHIFT+ENTER. Hope this helps! |
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#14
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count unique with mulitple criteria
Great job Domenic !
I learned a new trick from your formula... Thanks ! -- Festina Lente "Domenic" wrote: In article om, "Harlan Grove" wrote: ellebelle wrote... I have a list of data. Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB1 Alex JOB1 I'll assume this is a 2-column range with defined name TBL. I want to count the unique person that works on a job, however "unfilled" always denotes a new person and therefore I do not want it to be unique. eg. searching for "JOB 1" should give me 4 because i do not want to count Alex twice but I do want to count Unfilled twice. No ancillary cells needed. If the job code sought were entered in a cell named JOB, try the following array formula. =COUNT(1/(INDEX(TBL,0,2)=JOB)/(IF(INDEX(TBL,0,1)="Unfilled",ROW(TBL), MATCH(INDEX(TBL,0,1),INDEX(TBL,0,1),0)-1+MIN(ROW(TBL))=ROW(TBL)))) If the data can contain the following... Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB2 <--- Alex JOB1 <--- ....I believe the unique count should be 4. If this is correct, the above formula will fail and return 3. Similar to the above formula, mine can be shortened to... =COUNT(1/FREQUENCY(IF(B$2:B$8=D2,IF(A$2:A$8="Unfilled",ROW( A$2:A$8)-ROW(A $2)+1,MATCH(A$2:A$8,A$2:A$8,0))),ROW(A$2:A$8)-ROW(A$2)+1)) ....confirmed with CONTROL+SHIFT+ENTER. Hope this helps! |
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#15
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count unique with mulitple criteria
Domenic wrote...
.... If the data can contain the following... Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB2 <--- Alex JOB1 <--- ...I believe the unique count should be 4. If this is correct, the above formula will fail and return 3. Similar to the above formula, mine can be shortened to... =COUNT(1/FREQUENCY(IF(B$2:B$8=D2,IF(A$2:A$8="Unfilled",ROW( A$2:A$8) -ROW(A$2)+1,MATCH(A$2:A$8,A$2:A$8,0))),ROW(A$2:A$8)-ROW(A$2)+1)) .... Or mine could be corrected to =COUNT(1/(INDEX(TBL,0,2)=JOB)/IF(INDEX(TBL,0,1)="Unfilled",1,MATCH(INDEX(TBL,0,1 ), IF(INDEX(TBL,0,2)=JOB,INDEX(TBL,0,1)),0)-1+MIN(ROW(TBL))=ROW(TBL))) If I were to hardcode the ranges, it reduces to =COUNT(1/($B2:$B8=D2)/IF($A2:$A8="Unfilled",1,MATCH($A2:$A8, IF($B2:$B8=D2,$A2:$A8),0)-1+MIN(ROW($A2:$A8))=ROW($A2))) |
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#16
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count unique with mulitple criteria
Nice !
Isn't the last term of your "hardcoded" one wrong ? A probable typo error, I think it should be ROW($A2:$A8) instead of ROW($A2)... -- Festina Lente "Harlan Grove" wrote: Domenic wrote... .... If the data can contain the following... Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB2 <--- Alex JOB1 <--- ...I believe the unique count should be 4. If this is correct, the above formula will fail and return 3. Similar to the above formula, mine can be shortened to... =COUNT(1/FREQUENCY(IF(B$2:B$8=D2,IF(A$2:A$8="Unfilled",ROW( A$2:A$8) -ROW(A$2)+1,MATCH(A$2:A$8,A$2:A$8,0))),ROW(A$2:A$8)-ROW(A$2)+1)) .... Or mine could be corrected to =COUNT(1/(INDEX(TBL,0,2)=JOB)/IF(INDEX(TBL,0,1)="Unfilled",1,MATCH(INDEX(TBL,0,1 ), IF(INDEX(TBL,0,2)=JOB,INDEX(TBL,0,1)),0)-1+MIN(ROW(TBL))=ROW(TBL))) If I were to hardcode the ranges, it reduces to =COUNT(1/($B2:$B8=D2)/IF($A2:$A8="Unfilled",1,MATCH($A2:$A8, IF($B2:$B8=D2,$A2:$A8),0)-1+MIN(ROW($A2:$A8))=ROW($A2))) |
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#17
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count unique with mulitple criteria
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#18
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count unique with mulitple criteria
PapaDos wrote...
.... Isn't the last term of your "hardcoded" one wrong ? A probable typo error, I think it should be ROW($A2:$A8) instead of ROW($A2)... .... Not a typo, a mistake. It should be =COUNT(1/($B2:$B8=D2)/IF($A2:$A8="Unfilled",1,MATCH($A2:$A8, IF($B2:$B8=D2,$A2:$A8),0)-1+ROW($A2)=ROW($A2:$A8))) |
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#19
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count unique with mulitple criteria
Many thanks to everyone that has offered up solutions on this.
I've used the +COUNT(1/frequency.... formula and it does what I need. Great stuff "Harlan Grove" wrote: Domenic wrote... .... If the data can contain the following... Mike JOB1 Karen JOB2 Unfilled JOB1 Unfilled JOB2 Unfilled JOB1 Alex JOB2 <--- Alex JOB1 <--- ...I believe the unique count should be 4. If this is correct, the above formula will fail and return 3. Similar to the above formula, mine can be shortened to... =COUNT(1/FREQUENCY(IF(B$2:B$8=D2,IF(A$2:A$8="Unfilled",ROW( A$2:A$8) -ROW(A$2)+1,MATCH(A$2:A$8,A$2:A$8,0))),ROW(A$2:A$8)-ROW(A$2)+1)) .... Or mine could be corrected to =COUNT(1/(INDEX(TBL,0,2)=JOB)/IF(INDEX(TBL,0,1)="Unfilled",1,MATCH(INDEX(TBL,0,1 ), IF(INDEX(TBL,0,2)=JOB,INDEX(TBL,0,1)),0)-1+MIN(ROW(TBL))=ROW(TBL))) If I were to hardcode the ranges, it reduces to =COUNT(1/($B2:$B8=D2)/IF($A2:$A8="Unfilled",1,MATCH($A2:$A8, IF($B2:$B8=D2,$A2:$A8),0)-1+MIN(ROW($A2:$A8))=ROW($A2))) |
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