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#1
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Is there a way of doing this:
=COUNTIF(A1:A200;C2:C15) without having to =COUNTIF(A1:A200;C2)+COUNTIF(A1:A200;C3)+ ... ? with best regards P.S. For those using a non-english Excel -- such as I (me?) -- translations of functions in 9 languages: cherbe.free.fr/traduc_fonctions_xl97.html |
#2
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Try this:
=SUMPRODUCT(COUNTIF(A1:A200,C2:C15)) Biff "Bob" wrote in message ... Is there a way of doing this: =COUNTIF(A1:A200;C2:C15) without having to =COUNTIF(A1:A200;C2)+COUNTIF(A1:A200;C3)+ ... ? with best regards P.S. For those using a non-english Excel -- such as I (me?) -- translations of functions in 9 languages: cherbe.free.fr/traduc_fonctions_xl97.html |
#3
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Thank you, but no, that didn't work; I get the wrong result "0". Although I'm
not quite sure what Excel is counting... What I want to count is strings (if that is complicating everything), i.e 'how many' of this, that and the other in A1:A200; "this, that and the other" is specifyed in C2:C15. This ought to be possible, one might think... Bob |
#4
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I retract my answer!!! It does work, human error...
Thank you very much Biff!! Bob "Bob" skrev: Thank you, but no, that didn't work; I get the wrong result "0". Although I'm not quite sure what Excel is counting... What I want to count is strings (if that is complicating everything), i.e 'how many' of this, that and the other in A1:A200; "this, that and the other" is specifyed in C2:C15. This ought to be possible, one might think... Bob |
#5
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I was concerned after reading your first reply but I feel better now!
You're welcome. Thanks for the feedback! Biff "Bob" wrote in message ... I retract my answer!!! It does work, human error... Thank you very much Biff!! Bob "Bob" skrev: Thank you, but no, that didn't work; I get the wrong result "0". Although I'm not quite sure what Excel is counting... What I want to count is strings (if that is complicating everything), i.e 'how many' of this, that and the other in A1:A200; "this, that and the other" is specifyed in C2:C15. This ought to be possible, one might think... Bob |
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