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Default Index Match for 2 columns and one Row


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(

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JMB JMB is offline
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Default Index Match for 2 columns and one Row

Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 = adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE), try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(


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Posts: 12
Default Index Match for 2 columns and one Row

I still get #N/A
=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))

What seems the problem here? :(*

JMB wrote:
Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 = adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE), try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(



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Posts: 1,688
Default Index Match for 2 columns and one Row

You probably don't want a MATCH TYPE of 0 (exact match only).

Try changing it to 1. Requires that your table be sorted in ascending order
(which at least your sample is).

Biff

wrote in message
oups.com...
I still get #N/A
=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))

What seems the problem here? :(*

JMB wrote:
Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 =
adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE),
try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(





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Posts: 1,688
Default Index Match for 2 columns and one Row

Hmmm......

=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))


Because you're concatenating 2 numeric values:

LoanAmount&FICOScore
LoanAmountMatrix&FICOScoreMatrix

An approximate match (match type of either 1 or -1) probably won't work
either.

Biff

"Biff" wrote in message
...
You probably don't want a MATCH TYPE of 0 (exact match only).

Try changing it to 1. Requires that your table be sorted in ascending
order (which at least your sample is).

Biff

wrote in message
oups.com...
I still get #N/A
=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))

What seems the problem here? :(*

JMB wrote:
Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 =
adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE),
try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(









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Posts: 12
Default Index Match for 2 columns and one Row

Ok let me try to do it this way
I am looking for the value when Loan amount is $670,000 with 640 FICO
and LTV 76 and that should give me 3.000

A B C D E F G H I
1 LTV 0 70.01 75.01 80.01 85.01 90.01
2 Loan Size FICO
3 $650,000.01 620 659 1.000 2.000 3.000 N/A N/A N/A
4 $650,000.01 660 0.000 0.000 0.000 0.000 0.000 N/A
5 $1,000,000.01 740 4.000 5.000 N/A N/A N/A N/A
6 $1,000,000.01 680 739 6.000 7.000 N/A N/A N/A N/A
7 $1,500,000.01 680 8.000 N/A N/A N/A N/A N/A

Biff wrote:
Hmmm......

=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))


Because you're concatenating 2 numeric values:

LoanAmount&FICOScore
LoanAmountMatrix&FICOScoreMatrix

An approximate match (match type of either 1 or -1) probably won't work
either.

Biff

"Biff" wrote in message
...
You probably don't want a MATCH TYPE of 0 (exact match only).

Try changing it to 1. Requires that your table be sorted in ascending
order (which at least your sample is).

Biff

wrote in message
oups.com...
I still get #N/A
=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))

What seems the problem here? :(*

JMB wrote:
Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 =
adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE),
try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(






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JMB JMB is offline
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Posts: 2,062
Default Index Match for 2 columns and one Row

If the issue is not approximate match versus exact match as Biff suggested,
you'll need to post details about your named ranges, what you're trying to
look up and what results are expected.


" wrote:

I still get #N/A
=INDEX(Matrix,MATCH(LoanAmount&FICOScore,LoanAmoun tMatrix&FICOScoreMatrix,0),MATCH(LTVMatrix,Values! E149:J149,0))

What seems the problem here? :(*

JMB wrote:
Assuming your table is in A1:E6, G1 = Loan amount, H1 = FICO score, I1 = adj
value you want to find (70%, 70.01, or 75.01), try

=INDEX(A1:E6,MATCH(G1&H1,A1:A6&B1:B6,0),MATCH(I1,A 1:E1,0))
entered with Cntrl+Shift+Enter or you'll get #VALUE!

or, if your table is a named range (referring to A1:E6 - I used TABLE), try:
=INDEX(TABLE,MATCH(G1&H1,INDEX(TABLE,0,1)&INDEX(TA BLE,0,2),0),MATCH(I1,INDEX(TABLE,1,0),0))
also entered with Cntrl+Shift+Enter


" wrote:


How can I match Loan amount with FICO and get the adj value for it?

A B C D
E
1Loan FICO 70% 70.01 75.01
2 $650,000.01 620 0.123 0.250 0.850
3 $650,000.01 660 (0.123) (0.250) (0.375)
4 $1,000,000.01 740 0.123 0.250 0.375
5 $1,000,000.01 680 0.123 0.250 0.375
6 $1,500,000.01 680 0.123 0.250 0.375

Please help I tried everything possible :(




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