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Dear all,
Suppose I want to input an extension number (e.g. 61151) in cell A1 then I want a full telephone number appears in B1. Our telephone prefix is 4255 so the full telephone number should be 4255 1151. My formula in B1 is: =IF(LEFT(A1)=6,"4255"&RIGHT(A1,4),"") Why I use LEFT(A1)=6 becuase I have another set of extension numbers start with 4. However, the result of the above formula returns a blank cell. Where is the mistake? Please kindly advise. Thanks & regards. |
#2
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If telephone numbers are text, try:
=IF(LEFT(A1)="6","4255"& RIGHT(A1,4),"") "Freshman" wrote: Dear all, Suppose I want to input an extension number (e.g. 61151) in cell A1 then I want a full telephone number appears in B1. Our telephone prefix is 4255 so the full telephone number should be 4255 1151. My formula in B1 is: =IF(LEFT(A1)=6,"4255"&RIGHT(A1,4),"") Why I use LEFT(A1)=6 becuase I have another set of extension numbers start with 4. However, the result of the above formula returns a blank cell. Where is the mistake? Please kindly advise. Thanks & regards. |
#3
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"Freshman" skrev i en meddelelse
... Dear all, Suppose I want to input an extension number (e.g. 61151) in cell A1 then I want a full telephone number appears in B1. Our telephone prefix is 4255 so the full telephone number should be 4255 1151. My formula in B1 is: =IF(LEFT(A1)=6,"4255"&RIGHT(A1,4),"") Why I use LEFT(A1)=6 becuase I have another set of extension numbers start with 4. However, the result of the above formula returns a blank cell. Where is the mistake? Please kindly advise. Thanks & regards. The function LEFT() always returns a string, so you can use =IF(VALUE(LEFT(A1))=6,"4255"&RIGHT(A1,4),"") or =IF(LEFT(A1)="6","4255"&RIGHT(A1,4),"") -- Best regards Leo Heuser Followup to newsgroup only please. |
#4
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![]() Hi Freshman, Your LEFT formula is missing the number of digits. So =IF(LEFT(A1)=6,"4255"&RIGHT(A1,4),"") Should be =IF(LEFT(A1,1)=6,"4255"&RIGHT(A1,4),"") HTH Martin |
#5
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Ignore this post, I forgot to engage brain before typing. ;-)
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