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#1
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I would like a function to return a value that fits its range
For example:
0-$500 = 20% 501-$1000 = 15% 1001-$5000 = 12.5% Thank you! |
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#2
Posted to microsoft.public.excel.worksheet.functions
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I would like a function to return a value that fits its range
One way:
=LOOKUP(A1,{0,501,1001},{0.20,0.15,0.125}) with cell formatted as % or look at VLOOKUP function "rpbsr" wrote: For example: 0-$500 = 20% 501-$1000 = 15% 1001-$5000 = 12.5% Thank you! |
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#3
Posted to microsoft.public.excel.worksheet.functions
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I would like a function to return a value that fits its range
=IF(B1<=500, 0.2,IF(B1<=1000,0.15,IF(B1<=5000,0.125,0))) and format as
percentage. I've assumed that anything over the maximum in a range goes into the next range (eg.$500.01) and that anything over 5000 results in 0. -- Ian -- "rpbsr" wrote in message ... For example: 0-$500 = 20% 501-$1000 = 15% 1001-$5000 = 12.5% Thank you! |
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#4
Posted to microsoft.public.excel.worksheet.functions
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I would like a function to return a value that fits its range
That's perfect Ian. Thanks.
"Ian" wrote: =IF(B1<=500, 0.2,IF(B1<=1000,0.15,IF(B1<=5000,0.125,0))) and format as percentage. I've assumed that anything over the maximum in a range goes into the next range (eg.$500.01) and that anything over 5000 results in 0. -- Ian -- "rpbsr" wrote in message ... For example: 0-$500 = 20% 501-$1000 = 15% 1001-$5000 = 12.5% Thank you! |
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#5
Posted to microsoft.public.excel.worksheet.functions
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I would like a function to return a value that fits its range
Glad it worked.
Thanks for the feedback. -- Ian -- "rpbsr" wrote in message ... That's perfect Ian. Thanks. "Ian" wrote: =IF(B1<=500, 0.2,IF(B1<=1000,0.15,IF(B1<=5000,0.125,0))) and format as percentage. I've assumed that anything over the maximum in a range goes into the next range (eg.$500.01) and that anything over 5000 results in 0. -- Ian -- "rpbsr" wrote in message ... For example: 0-$500 = 20% 501-$1000 = 15% 1001-$5000 = 12.5% Thank you! |
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