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Predicting a Number From a Time Series
I have a time series like this:
..85% 5.42% 7.90% 8.28% 3.83% 3.47% 6.03% 4.19% 6.71% 8.74% 6.03% 7.71% 8.75% 7.01% 2.87% 5.23% 4.89% 6.33% 6.50% 6.22% Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Thank you in advance. |
Predicting a Number From a Time Series
Excel predicts th enext value is .0658.
How did I do this? Select the range and on the bottom right hand corner of the range outline, you can click and drag to extend the series. Whether Excel's prediction is accurate, I haven't a clue. As for predicting standard deviation, well that would be a function of the next value in the series, right? Dave -- Brevity is the soul of wit. "carl" wrote: I have a time series like this: .85% 5.42% 7.90% 8.28% 3.83% 3.47% 6.03% 4.19% 6.71% 8.74% 6.03% 7.71% 8.75% 7.01% 2.87% 5.23% 4.89% 6.33% 6.50% 6.22% Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Thank you in advance. |
Predicting a Number From a Time Series
Carl --
If you set up your data like this: A B 1 1 .85% 2 2 5.42% 3 3 7.90% etc. 21 21 6.22% 22 22 =FORECAST(A21,B1:B20,A1:A20) you'll get the 6.58% in the previous answer. You can also use different forecasting formulas for non-linear trends. HTH "carl" wrote: I have a time series like this: .85% 5.42% 7.90% 8.28% 3.83% 3.47% 6.03% 4.19% 6.71% 8.74% 6.03% 7.71% 8.75% 7.01% 2.87% 5.23% 4.89% 6.33% 6.50% 6.22% Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Thank you in advance. |
Predicting a Number From a Time Series
Carl --
Sorry, didn't see the part about the standard deviation. You can use either =STDEV(B1:B21), or =STDEVP(B1:B21) Read the help to see which one you want to use. "carl" wrote: I have a time series like this: .85% 5.42% 7.90% 8.28% 3.83% 3.47% 6.03% 4.19% 6.71% 8.74% 6.03% 7.71% 8.75% 7.01% 2.87% 5.23% 4.89% 6.33% 6.50% 6.22% Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Thank you in advance. |
Predicting a Number From a Time Series
carl wrote:
I have a time series like this: [.... Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Hopefully one of the statistics experts will comment. But looking at some of the responses so far, I want to offer some caveats for your consideration. First, when trying to extrapolate data, it is wise to start by graphing the data and looking at its behavior subjectively, not by blindly manipulating the data numerically as if one approach fits all. (It doesn't.) It is also wise to factor in any information that you might know about the nature of the data; for example, if the data represents month-to-month sales variation, you might know that in that industry, there is a cyclical or seasonal tendency to the data. Use the Chart Wizard to graph this data and create a linear trendline. I mention a linear trendline only because that is what the FORECAST() function does. I see an oscillating pattern around the trendline. One interpretation might be that there is sharp dampening effect over time which converges to the trendline. If that is your interpretation based on your knowledge of the nature of the data (e.g. an exponential decay), you might reasonably assume that the linear trendline does indeed predict the extrapolation of the dampened data, and FORECAST() is the proper tool to use. On the other hand, the oscillating behavior might convince you that the linear trendline is inadequate for extrapolating the data because there really is no dampening effect, but merely a random (or cyclical) pattern of the data, perhaps centered around the linear trendline; then again, perhaps the linear trendline is an illusion. Again, that would depend on your knowledge of the intrinsic nature of the data. Second, be careful with how you might use the std dev of this data. If you are using it simply as a measure of the deviation of the data around the mean, that might be okay. It is a common statistic for that purpose, albeit not the only one and not always the most appropriate one to use. But you might have heard things like 68% of the predicted data will lie within 1 std dev of the mean. That is valid if the data is "normally distributed". But that does not seem to be true in this case, unless once again you have knowledge of the intrinsic nature of the data that suggests that it should be normally distributed -- in which case, you might conclude this sampling simply does not accurately represent the behavior of the population. Finally, there is the matter of how the std dev (and the average) is computed. First, you need to decide if you want to treat this data truly as a "time series" or as a collection of periodic data. For example, the population every 10 years is a collection of periodic data. You might compute the arithmetic average and perhaps the arithmetic std dev (STDEV). But the rate of growth of the population every 10 years is a "time series". You might compute the geometric average and perhaps the geometric std dev. If you want to consider this data to be a "time series", the geometric mean computes the average percentage change per period. The geometric mean can be computed by GEOMEAN(1+A1:A20)-1, entered as an array formula (ctrl-shift-Enter). Similarly, I believe the geometric std dev should be used. That is computed by EXP(STDEV(LN(1+A1:A20)))-1, entered as an array formula. FYI, the geometric mean could also be computed using the array formula EXP(AVERAGE(LN(1+A1:A20)))-1. This is probably not the cookie-cutter solution that you were hoping for. But I hope it gives you some things to think about before crunching the numbers. ----- complete previous posting ---- carl wrote: I have a time series like this: .85% 5.42% 7.90% 8.28% 3.83% 3.47% 6.03% 4.19% 6.71% 8.74% 6.03% 7.71% 8.75% 7.01% 2.87% 5.23% 4.89% 6.33% 6.50% 6.22% Is there a a good way to predict what the next number is the time series will be and what the standard deviation is ? Thank you in advance. |
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