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How to match bits to a certain value
I don't think this is very hard, but I'm not sure how to approach it.
Basically I have an 8 bit binary code that represents a decimal value between 0 and 255, and each of the 8 bits represents a different color. By either using the decimal or binary number, I need to output the corresponding color. Say the 8 bits are equivalent to ROYGBIVP (8 colors). ie bit 7=Red, bit 6= Orange, bit 5=yellow, etc., down to bit 0=purple. So, if I have 00001011 (decimal 8+2+1=11), then I would output BVP or, if I have 11010000 (decimal 128+64+16= 128), then I would output ROG It doesn't matter if you use the binary (to match bit by bit) or decimal (using remainder function, even, odd, ,<, etc., or anything else I don't know about). Thanks. |
How to match bits to a certain value
What are you looking for here? Do you want this to be part of some VB code
or do you have the data in worksheet cells and need a formula? So, any solution is better than NO solution, right? How about an IF formula? Binary *TEXT* string in A1. A1 = 00001011 =IF(MID(A2,1,1)="1","R","")&IF(MID(A2,2,1)="1","O" ,"")&IF(MID(A2,3,1)="1","Y","")&IF(MID(A2,4,1)="1" ,"G","")&IF(MID(A2,5,1)="1","B","")&IF(MID(A2,6,1) ="1","I","")&IF(MID(A2,7,1)="1","V","")&IF(MID(A2, 8,1)="1","P","") Returns: BVP Biff "matt" wrote in message ... I don't think this is very hard, but I'm not sure how to approach it. Basically I have an 8 bit binary code that represents a decimal value between 0 and 255, and each of the 8 bits represents a different color. By either using the decimal or binary number, I need to output the corresponding color. Say the 8 bits are equivalent to ROYGBIVP (8 colors). ie bit 7=Red, bit 6= Orange, bit 5=yellow, etc., down to bit 0=purple. So, if I have 00001011 (decimal 8+2+1=11), then I would output BVP or, if I have 11010000 (decimal 128+64+16= 128), then I would output ROG It doesn't matter if you use the binary (to match bit by bit) or decimal (using remainder function, even, odd, ,<, etc., or anything else I don't know about). Thanks. |
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