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#1
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Round Len Function Help
Hi,
I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#2
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
I'm lost when you say that your formula of:
3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#3
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
Haha true, I see what you mean, but it returns the correct number I am
after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#5
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
Hi Sandy,
I dont know if thats what I am after, because I dont want it to always round to 3 sig figures. It changes and so should my formula, but hopefully automatically. I want it to look at Q16 and say "ok that cell has 0.010 in it and my answer in the other cell is 0.007, but it must at least be in line with the minimum division size in Q16, so Ill make it 0.010 by rounding it up." OR "ok that cell has 0.010 in it and my answer in the other cell is 0.012, but it must at least be in line with the minimum division size in Q16, so Ill make it 0.010 by rounding it down." Cheers, Aaron. Sandy Mann wrote: I haven't really been following this thread really but if you want the answer rounded depending on the number of decimal places in Q6 then should the formula not actually be: =ROUND(I36-I37,LEN(Q16)-3) -- HTH Sandy In Perth, the ancient capital of Scotland with @tiscali.co.uk wrote in message ups.com... Haha true, I see what you mean, but it returns the correct number I am after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#6
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
In that case does:
=ROUND(I36-I37,LEN(Q16)-2) do what you are looking for? -- HTH Sandy In Perth, the ancient capital of Scotland with @tiscali.co.uk wrote in message oups.com... Hi Sandy, I dont know if thats what I am after, because I dont want it to always round to 3 sig figures. It changes and so should my formula, but hopefully automatically. I want it to look at Q16 and say "ok that cell has 0.010 in it and my answer in the other cell is 0.007, but it must at least be in line with the minimum division size in Q16, so Ill make it 0.010 by rounding it up." OR "ok that cell has 0.010 in it and my answer in the other cell is 0.012, but it must at least be in line with the minimum division size in Q16, so Ill make it 0.010 by rounding it down." Cheers, Aaron. Sandy Mann wrote: I haven't really been following this thread really but if you want the answer rounded depending on the number of decimal places in Q6 then should the formula not actually be: =ROUND(I36-I37,LEN(Q16)-3) -- HTH Sandy In Perth, the ancient capital of Scotland with @tiscali.co.uk wrote in message ups.com... Haha true, I see what you mean, but it returns the correct number I am after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#7
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
Let's try again ! ! !
You *JUST* posted: <<<" If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 " What the heck is the difference between the 2 examples? They *both* have *6* decimal places! Is this a typo? How about you put a pseudo code into words, describing *exactly* what you want to happen. -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ups.com... Haha true, I see what you mean, but it returns the correct number I am after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#8
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
Is this just Aaron winding you all up ??
Pete RagDyer wrote: Let's try again ! ! ! You *JUST* posted: <<<" If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 " What the heck is the difference between the 2 examples? They *both* have *6* decimal places! Is this a typo? How about you put a pseudo code into words, describing *exactly* what you want to happen. -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ups.com... Haha true, I see what you mean, but it returns the correct number I am after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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#9
Posted to microsoft.public.excel.worksheet.functions
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Round Len Function Help
You know, I never look at the name of the OP, except what's in the Name
column. Maybe I should pay more attention. Thanks Pete!<g "Pete_UK" wrote in message oups.com... Is this just Aaron winding you all up ?? Pete RagDyer wrote: Let's try again ! ! ! You *JUST* posted: <<<" If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 " What the heck is the difference between the 2 examples? They *both* have *6* decimal places! Is this a typo? How about you put a pseudo code into words, describing *exactly* what you want to happen. -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ups.com... Haha true, I see what you mean, but it returns the correct number I am after, 0.010 from 0.007 I tested it by changing "len" to 2-LEN and sure enough the number returned changes to 0.000 and with 4-LEN I get no change, with the returned result as 0.007. 3-LEN returns the result 0.010. Try to copy and paste it into a ssheet to see what I mean. But essentially Q16 automatically changes based on what the ssheet is doing that day. It might be 0.000010 (the DP is important) but a calculated answer in another cell could come back as 0.000003 and I must have the answers automatically round to the figure in Q16. If I got 0.000003 I would expect it to just round to zero. If I got 0.000005 I would expect it to round to 0.000010 Any help appreciated greatly, Cheers, Aaron. RagDyer wrote: I'm lost when you say that your formula of: 3-LEN(INT(Q16)) really works ! ! ! 0.1 0.01 0.00001 in Q16 all equate to the same number ... 2 ... since the integer length is always 1. Care to re-phrase your question so that a not overly bright old man (been saying that a lot lately), might understand? -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- wrote in message ps.com... Hi, I have this formula which works well, but the 3-len part needs to be dependent on another cells content. Is it possible to have the formula automatically accommodate for this? Eg =ROUND(I36-I37,3-LEN(INT(Q16))) in cell Q16 is a number 0.010 as displayed, and the sum of i36-i37= 0.007 I need the formula to say ok the minimum division size is in multiples of Q16 (0.010) and change the 0.007 to either up or down depending on the calculation. This works currently, but the figure in Q16 can be 0.1 or 0.00001 etc, and the sum in i36-i37 could be anything also as it is a calculated error figure. I need the formula to be able to adapt automatically to the reference DP in Q16. Namely the "3-" part in the formula needs to accomodate for the Q16 number format changing. Is this achievable? Thanks in advance, Aaron. |
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