![]() |
INDEX function need to have col reference to be formula
This works quite nicely:
=INDEX('Price List'!$E:$J,MATCH($E20,'Price List'!$B:$B,0)+ROW()-ROW(),6) But the last cell reference of a value in column "6" in the above formula needs to be a calculated cell within this formula. In this case: F3*(1+I3) Reason being: It seems that the value in column 6 in the range is not present when the ODBC completes its job from which the data is extracted. I'm hoping that this calculation can occur in the cell where the above formula is located. So to summarize, can I replace the "6" in the above INDEX function with the result of calculating F3*(1+I3) ? TIA for any ideas. Pierre |
INDEX function need to have col reference to be formula
Hi!
The short answer to your question is yes. Did you try it? Don't know why you're using this: +ROW()-ROW() It's superfluous. Biff "Pierre" wrote in message ups.com... This works quite nicely: =INDEX('Price List'!$E:$J,MATCH($E20,'Price List'!$B:$B,0)+ROW()-ROW(),6) But the last cell reference of a value in column "6" in the above formula needs to be a calculated cell within this formula. In this case: F3*(1+I3) Reason being: It seems that the value in column 6 in the range is not present when the ODBC completes its job from which the data is extracted. I'm hoping that this calculation can occur in the cell where the above formula is located. So to summarize, can I replace the "6" in the above INDEX function with the result of calculating F3*(1+I3) ? TIA for any ideas. Pierre |
INDEX function need to have col reference to be formula
Biff wrote: Hi! The short answer to your question is yes. Did you try it? Don't know why you're using this: +ROW()-ROW() It's superfluous. Biff Biff, thanks for the sanity check. ;-) The formula works well as =INDEX('Price List'!$E:$J,MATCH($E20,'Price List'!$B:$B,0),6) The next row is =INDEX('Price List'!$E:$J,MATCH($E20,'Price List'!$B:$B,0)+1,6) =INDEX('Price List'!$E:$J,MATCH($E20,'Price List'!$B:$B,0)+2,6) etc. however, we still need to multiply the value in column F by the value in coulmn I at the row located by the INDEX/MATCH. This would appear where a column 6 would be if it existed. Attempts at nomenclature have fizzled in this heat. Thanks for your interest. Pierre |
All times are GMT +1. The time now is 09:22 AM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com