Cell to be activated, which is a result of a vlookup formula
 

Hi,
could somebody please help me with some code for a macro?

I have following formula: =VLOOKUP($H6&"-"&I6,'Stock sheet'!$A:$F,6,FALSE)

After the result is displayed, I'd like the cursor to jump to that exact cell, which it found in 'Stock sheet'!$A:$F,6,False).
I tried Goto, but it doesn't work.

Thank you!

Regards,
Norbert

Cell to be activated, which is a result of a vlookup formula
 

Hi,
could somebody please help me with some code for a macro?

I have following formula: =VLOOKUP($H6&"-"&I6,'Stock sheet'!$A:$F,6,FALSE)

After the result is displayed, I'd like the cursor to jump to that exact
cell, which it found in 'Stock sheet'!$A:$F,6,False). I tried Goto, but it
doesn't work.

Thank you!

Regards,
Norbert

GoTo only requires the target address; - ",False" belongs to the VLOOKUP
function!

--
Garry

Free usenet access at http://www.eternal-september.org
Classic VB Users Regroup!
comp.lang.basic.visual.misc
microsoft.public.vb.general.discussion

Cell to be activated, which is a result of a vlookup formula
 

Hi Norbert,

Am Sun, 2 Feb 2020 08:31:29 -0800 (PST) schrieb Norbert:

I have following formula: =VLOOKUP($H6&"-"&I6,'Stock sheet'!$A:$F,6,FALSE)

After the result is displayed, I'd like the cursor to jump to that exact cell, which it found in 'Stock sheet'!$A:$F,6,False).
I tried Goto, but it doesn't work.

try:

Sub Test()
Dim c As Range
Dim myStr As String

With ActiveSheet
myStr = .Range("H6") & "-" & .Range("I6")
End With

With Sheets("Stock sheet")
Set c = .Range("A:A").Find(myStr)
Application.Goto .Range("F" & c.Row)
End With
End Sub


Regards
Claus B.
--
Windows10
Office 2016

Cell to be activated, which is a result of a vlookup formula
 

Hi Claus,
thanks for your reply!
I am trying to incorporate your code into my macro but it stops at line:
Application.Goto .Range("F" & c.Row)
with following message: Run-time error 91: Object variable or With block variable not set!


Herewith my macro and how I tried to make use of your code:

Sub FEED_STOCK_REQUIREMENTS()

Range("I6:L6").Select
Selection.ClearContents
Range("F6").Select
Selection.Copy
Range("I6").Select
Selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
Application.CutCopyMode = False
Selection.TextToColumns Destination:=Range("I6"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=False, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=True, OtherChar _
:="+", FieldInfo:=Array(Array(1, 1), Array(2, 1)), TrailingMinusNumbers:=True
Range("L6").Select
ActiveCell.FormulaR1C1 = "=RC[-5]/COUNTA(RC[-3]:RC[-1])"
Range("B6").Select

' Goto the cell which was found by the vlookup formula in
' Sheet("Input").Range(I8)

Dim c As Range
Dim myStr As String

With Sheets("Input")
myStr = .Range("H6") & "-" & .Range("I6")
End With

With Sheets("Stock sheet")
Set c = .Range("A:A").Find(myStr)
Application.Goto .Range("F" & c.Row)
End With
End Sub

Cell to be activated, which is a result of a vlookup formula
 

On Tuesday, 4 February 2020 07:54:47 UTC+2, Norbert wrote:
Hi Claus,
thanks for your reply!
I am trying to incorporate your code into my macro but it stops at line:
Application.Goto .Range("F" & c.Row)
with following message: Run-time error 91: Object variable or With block variable not set!


Herewith my macro and how I tried to make use of your code:

Sub FEED_STOCK_REQUIREMENTS()

Range("I6:L6").Select
Selection.ClearContents
Range("F6").Select
Selection.Copy
Range("I6").Select
Selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
Application.CutCopyMode = False
Selection.TextToColumns Destination:=Range("I6"), DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=False, Tab:=False, _
Semicolon:=False, Comma:=False, Space:=False, Other:=True, OtherChar _
:="+", FieldInfo:=Array(Array(1, 1), Array(2, 1)), TrailingMinusNumbers:=True
Range("L6").Select
ActiveCell.FormulaR1C1 = "=RC[-5]/COUNTA(RC[-3]:RC[-1])"
Range("B6").Select

' Goto the cell which was found by the vlookup formula in
' Sheet("Input").Range(I8)

Dim c As Range
Dim myStr As String

With Sheets("Input")
myStr = .Range("H6") & "-" & .Range("I6")
End With

With Sheets("Stock sheet")
Set c = .Range("A:A").Find(myStr)
Application.Goto .Range("F" & c.Row)
End With
End Sub

Hi Claus,

it works, the problem was that I actually had formulas in Range (A:A) on sheet "Stock sheet" and not values. The formulas created the string I was searching with the vlookup formula.
This is one of the formulas: =C5&"-"&D5

It would be great if it was working with the formulas, otherwise I have to come up with another idea.

Cell to be activated, which is a result of a vlookup formula
 

Error is because Find() failed to Set c

try...

With Sheets("Stock sheet")
Set c = .Range("A:A").Find(myStr)
If Not c Is Nothing Then Application.Goto .Range("F" & c.Row)
End With

--
Garry

Free usenet access at http://www.eternal-september.org
Classic VB Users Regroup!
comp.lang.basic.visual.misc
microsoft.public.vb.general.discussion