dynamically change IF formula in macro, possible?
 

I'm trying to calculate percentages that a column of values are of a
single cell value, e.g.
column a contains values 10 through 100
column b will contain the percentage that a is of a cell C6
I'm trying to populate the cell formulas in column B with an =IF(...
formula, is that possible, I tried this

for n = 1 to 10
Cells(n, 2).Formula = "=IF(C6, Cells(n, 1).Value / cells(6,3).value &
, 0)"
next

But that won't work, I've tried a few other things, I want the sheet to
update when different values are entered into C6, with the percentages
if C6 is not empty, and with 0's if c6 is empty.

Does anyone have any suggestions?

TIA,
Mike

dynamically change IF formula in macro, possible?
 

You won't be able to use a .value in the value of a cell I don't think. Here is a snippet of code that I used recently where I put an if statement in a cell.

Sheet5.Cells(row_tag + 1, col_tag + 1).Value = "=IF('Introduction'!B7<"""",'Introduction'!B7 , ""N/A"")"
Sheet5.Cells(row_tag + 3, col_tag + 1).Value = "=IF('LoTo Procedure #" & page_number & "'!C" & cell_data & "<"""",'LoTo Procedure #" & page_number & "'!C" & cell_data & ", ""N/A"")"
Sheet5.Cells(row_tag + 5, col_tag + 1).Value = "=IF('LoTo Procedure #" & page_number & "'!B" & cell_data & "<"""",'LoTo Procedure #" & page_number & "'!B" & cell_data & ", ""N/A"")"
Sheet5.Cells(row_tag + 21, col_tag + 1).Value = "=IF('LoTo Procedure #" & page_number & "'!D" & cell_data & "<"""",'LoTo Procedure #" & page_number & "'!D" & cell_data & ", ""N/A"")"
Sheet5.Cells(row_tag + 25, col_tag + 1).Value = "=IF('LoTo Procedure #" & page_number & "'!F" & cell_data & "<"""",'LoTo Procedure #" & page_number & "'!F" & cell_data & ", ""N/A"")"

dynamically change IF formula in macro, possible?
 

Perhaps...

In B10:
=IF($C$6,$A10/$C$6,0)

...and copy down!

--
Garry

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