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Export range to new file (using classes)
Hi, I need to write a macro which will export entire rows of data to a new file (one row per person copied directly from the master, one file to be sent to each employer), I could write a loop that basically says:
Code:
For rownum from LastRow to 9 The more I look into classes the more confused I get. |
Export range to new file (using classes)
Hi, I need to write a macro which will export entire rows of data to
a new file (one row per person copied directly from the master, one file to be sent to each employer), I could write a loop that basically says: Code: -------------------- For rownum from LastRow to 9 If Range("A:" & rownum).value = "Employer1" Then Copy stuff over Next rownum -------------------- But could I use classes to do this quicker and easier? I cannot get my head around how to use them, I have all the employee data in a sheet indexed by unique IDs so I would tell the class module that all the instances of the class are in the sheet? The more I look into classes the more confused I get. Why not simply 'dump' the sheet into an array and write each row of that array to a file? This would certainly be way easier than implimenting a 'class' since you can use the standard VB file I/O functions with minimal coding!!! -- Garry Free usenet access at http://www.eternal-september.org Classic VB Users Regroup! comp.lang.basic.visual.misc microsoft.public.vb.general.discussion |
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