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Sorry this is a long post but I've been working on this forever!
I have been trying to develop a function using Find/FindNext to search for text. The code below is just the start of the development. What it tries to do is look in a range in a single column and identify all occurrences of a particular text string. I started by writing a sub which works fine and identifies all the occurrences of the string in parameter A (code copied from Chip Pearson): (Parameter B will be use to compare to a 2nd column, C is the range to search) __________________________________________________ ____ Sub FactorX2(A As String, B As String, C As Range) Dim FoundCell As Range Dim LastCell As Range Dim FirstAddress As String With C Set LastCell = .Cells(.Cells.Count) End With Set FoundCell = C.Find(what:=A, after:=LastCell, LookAt:=xlWhole) If Not FoundCell Is Nothing Then FirstAddress = FoundCell.Address End If Do Until FoundCell Is Nothing Set FoundCell = C.FindNext(after:=FoundCell) Debug.Print FoundCell.Address If FoundCell.Address = FirstAddress Then Exit Do End If Loop End Sub __________________________________________________ _____ I then tried to convert this to a function: Function FactorX(A As String, B As String, C As Range) As Variant Dim FoundCell As Range Dim LastCell As Range Dim FirstAddress As String With C Set LastCell = .Cells(.Cells.Count) End With Set FoundCell = C.Find(what:=A, after:=LastCell, LookAt:=xlWhole) If Not FoundCell Is Nothing Then FirstAddress = FoundCell.Address End If Do Until FoundCell Is Nothing Set FoundCell = C.FindNext(after:=FoundCell) Debug.Print "£$ " & FoundCell.Address If FoundCell.Address = FirstAddress Then Exit Do End If Loop FactorX = 0 End Function __________________________________________________ ________ The function finds the first string occurrence, but the FindNext fails completely. Even if I place Debug.Print Statements before End Function, nothing is printed. It is as though the code exits as soon as it hits the FindNext. Can anyone please shed any light on this? |
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