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"MAX" wrote:
I am writing this code (below) and a window appears with Compile error and Syntax error. I suspect that your error is due to an explicit line break without the necessary continuation character. But it is difficult to say for sure since it is difficult to discern which line breaks in your posting are due to text wrapping in the message v. what you actually entered in the VBA enter. In summary, VBA statements must be a "single" line. Long lines can be continued by putting an underscore (_) at the end, but only after a space; ergo, only where a space is valid in the statement. The following should work "for sure", keeping lines short enough to avoid line wrapping in the message (I hope): Range("A105").Value = _ IIf(Range("F102") = Range("G102"), Range("A99"), _ IIf(Range("F102") Range("G102"), Range("E102"), _ Range("H102"))) ----- original message ----- "MAX" wrote: Hello I am writing this code (below) and a window appears with Compile error and Syntax error. I am having also this part of the code highlighted. Range("A105").Value = IIf(Range("F102") = Range("G102"), Range("A99"), IIf(Range("F102") Range("G102"), Range("E102"), This is the code: Option Explicit Dim nextSecond Sub startFlashing() flashCell End Sub Sub stopFlashing() On Error Resume Next Application.OnTime nextSecond, "flashCell", , False End Sub Sub flashCell() nextSecond = Now + TimeValue("00:00:01") Application.OnTime nextSecond, "flashCell" If Range("A105").Interior.ColorIndex =4 Then Range("A105").Interior.ColorIndex = 6 Range("A105").Value = IIf(Range("F102") = Range("G102"), Range("A99"), IIf(Range("F102") Range("G102"), Range("E102"), Range("H102"))) ElseIf Range("A105").Interior.ColorIndex = 6 Then Range("A105").Interior.ColorIndex = 4 Range("A105").Value = "WORLD CHAMPIONS 2010" End If End Sub I appriciate even a small help. Thanks in advance. |
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