update links - source file open
 

Is there a way in VBA to detect if the source file for a specific link is open?

update links - source file open
 

'/================================================/
' Function Purpose: Returns TRUE if workbook is open
' Returns FALSE if workbook is NOT open
' syntax of strWkbkName is FULL Name
' example: "D:\Temp\Hello.xls"
' strWkbkName must be a string
'
'/================================================/
Public Function WorkbookIsOpen(strWkbkName As String) As Boolean
Dim blnResult As Boolean
Dim iWorkbooks As Double, x As Double

On Error GoTo err_Function

blnResult = False

'count number of open workbooks
iWorkbooks = Application.Workbooks.Count
If iWorkbooks < 1 Then
GoTo exit_Function
End If

For x = 1 To iWorkbooks
If Application.Workbooks(x).FullName = strWkbkName Then
blnResult = True
End If
Next x

WorkbookIsOpen = blnResult

exit_Function:
On Error Resume Next
Exit Function

err_Function:
Debug.Print "Error: " & Err.Number & " - (" & _
Err.Description & _
") - Function: WorkbookIsOpen - " & _
"Module: Mod_Functions_WorkbookIsOpen - " & Now()
GoTo exit_Function

End Function
'/================================================/

--
Hope this helps.
If it does, please click the Yes button.
Thanks in advance for your feedback.
Gary Brown



"KB" wrote:

Is there a way in VBA to detect if the source file for a specific link is open?