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Array within a dictionary
Please could somebody help me why this code does not work as expected
in Excel 2003: Sub Test() Dim dic As Dictionary Set dic = New Dictionary dic("Hello") = Array("Zero", "Item1") Debug.Print dic("Hello")(0) Debug.Print dic("Hello")(1) dic("Hello")(1) = dic("Hello")(1) & ",Item2" Debug.Print dic("Hello")(1) End Sub Output: Zero Item1 Item1 Thanks Jon |
Array within a dictionary
this code:
Sub Test() Dim hello() hello = Array("Zero", "Item1") Debug.Print hello(0) Debug.Print hello(1) hello(1) = hello(1) & ",Item2" Debug.Print hello(1) End Sub will bring: Zero Item1 Item1,Item2 as the results On 20 Lis, 13:54, jrpfinch wrote: Please could somebody help me why this code does not work as expected in Excel 2003: Sub Test() Dim dic As Dictionary Set dic = New Dictionary dic("Hello") = Array("Zero", "Item1") Debug.Print dic("Hello")(0) Debug.Print dic("Hello")(1) dic("Hello")(1) = dic("Hello")(1) & ",Item2" Debug.Print dic("Hello")(1) End Sub Output: Zero Item1 Item1 Thanks Jon |
Array within a dictionary
I believe that in order to change an item in the array, the entire array
needs to be changed at the same time. If I understand the question correctly, here is one idea... Sub Demo() Dim Dic Dim M 'Matrix Array Set Dic = CreateObject("Scripting.Dictionary") ' Add Key, Item (Both Required) Dic.Add "Hello", Array("Zero", "Item1") Debug.Print Dic("Hello")(0) Debug.Print Dic("Hello")(1) 'Get Data to change M = Dic("Hello") 'New Data M(1) = M(1) & ", Item2" 'Change it Dic("Hello") = M Debug.Print Dic("Hello")(0) Debug.Print Dic("Hello")(1) End Sub = = = = = HTH Dana DeLouis jrpfinch wrote: Please could somebody help me why this code does not work as expected in Excel 2003: Sub Test() Dim dic As Dictionary Set dic = New Dictionary dic("Hello") = Array("Zero", "Item1") Debug.Print dic("Hello")(0) Debug.Print dic("Hello")(1) dic("Hello")(1) = dic("Hello")(1) & ",Item2" Debug.Print dic("Hello")(1) End Sub Output: Zero Item1 Item1 Thanks Jon |
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