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Insert cells at end of selection
Thanks,
The only problem I am finding is that it is inserting the new row, 2 rows above the last row with data, not one "Rick Rothstein" wrote: This should do what you want, just assign the number of rows of cells in Columns A through R to insert to the NumberOfBlankRows variable (I used 4 for my example code)... Sub InsertBlankCellsColumnsAtoR() Dim LastRow As Long, NumberOfBlankRows NumberOfBlankRows = 4 LastRow = Range("A3:R1000").Find(What:="*", SearchOrder:=xlColumns, _ SearchDirection:=xlPrevious, LookIn:=xlValues).Row Intersect(Range("A:R"), Rows(LastRow)).Resize(NumberOfBlankRows).Insert End Sub -- Rick (MVP - Excel) "Kirsty" wrote in message ... Hi, I have a macro that I want to change to go look in a range of cells A3:R1000 and find the last row with data. I then want to step back and insert cells above this row. Eg, i have data in row 140, so I want to insert cells to get a blank lot of cells in row 140 from columns A to R. Is this possible? Kirsty . |
Insert cells at end of selection
Sorry, have been having computer issues, but I have fixed the problem.
"Kirsty" wrote: Thanks, The only problem I am finding is that it is inserting the new row, 2 rows above the last row with data, not one "Rick Rothstein" wrote: This should do what you want, just assign the number of rows of cells in Columns A through R to insert to the NumberOfBlankRows variable (I used 4 for my example code)... Sub InsertBlankCellsColumnsAtoR() Dim LastRow As Long, NumberOfBlankRows NumberOfBlankRows = 4 LastRow = Range("A3:R1000").Find(What:="*", SearchOrder:=xlColumns, _ SearchDirection:=xlPrevious, LookIn:=xlValues).Row Intersect(Range("A:R"), Rows(LastRow)).Resize(NumberOfBlankRows).Insert End Sub -- Rick (MVP - Excel) "Kirsty" wrote in message ... Hi, I have a macro that I want to change to go look in a range of cells A3:R1000 and find the last row with data. I then want to step back and insert cells above this row. Eg, i have data in row 140, so I want to insert cells to get a blank lot of cells in row 140 from columns A to R. Is this possible? Kirsty . |
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