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last day of month in prior month
I am having trouble writing a function that returns the last day of the month
prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
Parse into year, month & the number 1 then take a day off - otherwise a 30
day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
=date does not work in VBA
tempdate =DATE(YEAR(A1),MONTH(A1),1)-1 produces a compilation error "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
Ah, I see. That was a function based method. This works for me:
Dim xdate As Date xdate = Now() MsgBox CDate("01/" & Month(xdate) & "/" & Year(xdate)) - 1 Swap month & date if you're American. "thomas donino" wrote: =date does not work in VBA tempdate =DATE(YEAR(A1),MONTH(A1),1)-1 produces a compilation error "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
Here is the current code which is not working
Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell Dim targMo As Integer Dim targYr As Integer Dim tempdate As Date targMo = Month(TargDate) - 1 targYr = Year(TargDate) tempdate = DateValue(TargDate) tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) LastDayInLastMo = tempdate End Function "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
Change thsi:
tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) to this tempdate = CDate(CStr(targMo) & "/01/" & CStr(targYr))-1 "thomas donino" wrote: Here is the current code which is not working Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell Dim targMo As Integer Dim targYr As Integer Dim tempdate As Date targMo = Month(TargDate) - 1 targYr = Year(TargDate) tempdate = DateValue(TargDate) tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) LastDayInLastMo = tempdate End Function "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
thank you
"Sam Wilson" wrote: Change thsi: tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) to this tempdate = CDate(CStr(targMo) & "/01/" & CStr(targYr))-1 "thomas donino" wrote: Here is the current code which is not working Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell Dim targMo As Integer Dim targYr As Integer Dim tempdate As Date targMo = Month(TargDate) - 1 targYr = Year(TargDate) tempdate = DateValue(TargDate) tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) LastDayInLastMo = tempdate End Function "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
Here is a simpler function for you to consider...
Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell LastDayInLastMo = DateSerial(Year(TargDate), Month(TargDate), 0) End Function -- Rick (MVP - Excel) "thomas donino" wrote in message ... thank you "Sam Wilson" wrote: Change thsi: tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) to this tempdate = CDate(CStr(targMo) & "/01/" & CStr(targYr))-1 "thomas donino" wrote: Here is the current code which is not working Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell Dim targMo As Integer Dim targYr As Integer Dim tempdate As Date targMo = Month(TargDate) - 1 targYr = Year(TargDate) tempdate = DateValue(TargDate) tempdate = CDate(CStr(targMo) & ", " & CStr(0) & ", " & CStr(targYr)) LastDayInLastMo = tempdate End Function "Sam Wilson" wrote: Parse into year, month & the number 1 then take a day off - otherwise a 30 day month after a 31 day month will cause you problems etc... =DATE(YEAR(A1),MONTH(A1),1)-1 "thomas donino" wrote: I am having trouble writing a function that returns the last day of the month prior to the month from the date in the cell. I am parsing the date apart into 3 variables, year,date,month subtracting 1 from month where i am having trouble is how to put it back together thank you |
last day of month in prior month
On Wed, 12 Aug 2009 11:09:39 -0400, "Rick Rothstein"
wrote: Here is a simpler function for you to consider... Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell LastDayInLastMo = DateSerial(Year(TargDate), Month(TargDate), 0) End Function -- Rick (MVP - Excel) Or, perhaps even simpler, using only one function and one arithmetic operation. ================== Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell LastDayInLastMo = TargDate - Day(TargDate) End Function =================== --ron |
last day of month in prior month
Here is a simpler function for you to consider...
Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell LastDayInLastMo = DateSerial(Year(TargDate), Month(TargDate), 0) End Function Or, perhaps even simpler, using only one function and one arithmetic operation. ================== Public Function LastDayInLastMo(TargDate As Date) As Date 'get the last day of the month prior to the date in the cell LastDayInLastMo = TargDate - Day(TargDate) End Function =================== Yep, that is definitely a better formula to use. -- Rick (MVP - Excel) |
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