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mark kubicki

where am I?
 
is there a function that identifies what cell a formula is being used in?

ex; I have a formula: =LMI(xx) entered into cell B32 as part of the code
behind the formula, I need to know what cell the formula is being used in.

many thanks in advance,
mark



Dave Peterson

where am I?
 
Do you mean within the code for the LMI user defined function?

If yes, you can use application.caller

Option Explicit
Function LMI(xxx as yyyy) as uuuu
debug.print application.caller
...
end function

Mark Kubicki wrote:

is there a function that identifies what cell a formula is being used in?

ex; I have a formula: =LMI(xx) entered into cell B32 as part of the code
behind the formula, I need to know what cell the formula is being used in.

many thanks in advance,
mark


--

Dave Peterson

Rick Rothstein

where am I?
 
I'm assuming LMI is a UDF that you wrote and it is its code that you want to
have know which cell called it. You would use Application.Caller to return a
range object which references that cell.

--
Rick (MVP - Excel)


"Mark Kubicki" wrote in message
...
is there a function that identifies what cell a formula is being used in?

ex; I have a formula: =LMI(xx) entered into cell B32 as part of the code
behind the formula, I need to know what cell the formula is being used in.

many thanks in advance,
mark



Tim Zych

where am I?
 
Here's a sample UDF using the Caller property:

' UDF which returns the address info of the cell
' in which it resides
Function Addr() As String
' Addr = Application.Caller.Address
' Or more detail
With Application.Caller
Addr = .Parent.Parent.Name & ", " & _
.Parent.Name & ", " & .Address(0, 0)
End With
End Function


--
Regards,
Tim Zych
http://www.higherdata.com
Workbook Compare - Excel data comparison utility

"Mark Kubicki" wrote in message
...
is there a function that identifies what cell a formula is being used in?

ex; I have a formula: =LMI(xx) entered into cell B32 as part of the code
behind the formula, I need to know what cell the formula is being used in.

many thanks in advance,
mark





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