Can this be done with HIDE - UNHIDE ?
 

Hi All !

I have next macro , which move blocks of
data , in combinatoric order , from columns 11 to 20 ,
in columns 1 to 3 :

Sub moveblocksofdata ( )
Dim i1 As Integer
Dim i2 As Integer
Dim i3 As Integer

For i1 = 11 To 18
For i2 = i1 + 1 To 19
For i3 = i2 + 1 To 20
Range("A1:A203") = .Range(Cells("1", i1), _
Cells("203", i1)).Value
Range("B1:B203") = .Range(Cells("1", i2), _
Cells("203", i2)).Value
Range("C1:C203") = .Range(Cells("1", i3), _
Cells("203", i3)).Value
Next i3
Next i2
Next i1
End Sub

Can this be done in another way , useing hide - unhide method ?
I mean , let's be a block of data in a range ( from column 11
to column 20 ) ; can hide - unhide to do the exact result from
previous macro , so , all the time to be no more then 3 columns ?
In every step , must to be hide 7 columns .

I'd like very much and it's very usefull for me to get know if this
thing can be possible useing hide - unhide .

Thank you very much for your time and knowledge share !

Can this be done with HIDE - UNHIDE ?
 

i don't understand your code. Your target is the same, so it continuously
gets overwritten in the loop. also you seem to confuse rows with columns ...
wel you confused me anyway.

if you want to "move" a table, you could do it this way:
dim source as range
dim target as range
set source = range("A1:L203"
set target = sheet2.Range("G1") ' a cell anywhere else

with source
target.resize(.rows.count,.columns.count).Value = .Value
.ClearContents
end with






"ytayta555" wrote in message
...
Hi All !

I have next macro , which move blocks of
data , in combinatoric order , from columns 11 to 20 ,
in columns 1 to 3 :

Sub moveblocksofdata ( )
Dim i1 As Integer
Dim i2 As Integer
Dim i3 As Integer

For i1 = 11 To 18
For i2 = i1 + 1 To 19
For i3 = i2 + 1 To 20
Range("A1:A203") = .Range(Cells("1", i1), _
Cells("203", i1)).Value
Range("B1:B203") = .Range(Cells("1", i2), _
Cells("203", i2)).Value
Range("C1:C203") = .Range(Cells("1", i3), _
Cells("203", i3)).Value
Next i3
Next i2
Next i1
End Sub

Can this be done in another way , useing hide - unhide method ?
I mean , let's be a block of data in a range ( from column 11
to column 20 ) ; can hide - unhide to do the exact result from
previous macro , so , all the time to be no more then 3 columns ?
In every step , must to be hide 7 columns .

I'd like very much and it's very usefull for me to get know if this
thing can be possible useing hide - unhide .

Thank you very much for your time and knowledge share !

Can this be done with HIDE - UNHIDE ?
 

On 11 Iun, 17:41, "Patrick Molloy" wrote:
i don't understand your code.

Thanks for reply

Your target is the same, so it continuously gets overwritten in the loop.
This is what I really need

also you seem to confuse rows with columns ...
No , I'm not , if you put some data in Range K1:T203 ,
you will see the result of macro in range A1:C203 ;
I need this , to generate combinatoric situations

if you want to "move" a table, you could do it this way:
I need to move parts of table ( mean columns )"in combinatoric
order" .
I'd just want to get ideas and answers if it can be done in
other way , for eg. how I asked , useing Hide and Unhide

Many thanks again

Can this be done with HIDE - UNHIDE ?
 

I'd like to know what are you thinking
about this problem , you are shure more
experimented like me .

Can this be done with HIDE - UNHIDE ?
 

Hi,

The answer is yes, it can be done. I'm not sure why you'd want to... Your
existing code takes all combinations of three columns from K to T and shows
them sequentially as A to C. I assume your code will do something to each
combination as it is shown, but that you haven't written it yet.

This does the same thing, but by hiding:

Sub hideblocksofdata ( )
Dim i As Integer
Dim j As Integer
Dim k As Integer

For i = 11 To 18
For j = i + 1 To 19
For k = j + 1 To 20
range("K1:T1").entirecolumn.hidden = true
range("a1").offset(0,i).entirecolumn.hidden = false
range("a1").offset(0,j).entirecolumn.hidden = false
range("a1").offset(0,k).entirecolumn.hidden = false
Next i3
Next i2
Next i1

End Sub


"ytayta555" wrote:

Hi All !

I have next macro , which move blocks of
data , in combinatoric order , from columns 11 to 20 ,
in columns 1 to 3 :

Sub moveblocksofdata ( )
Dim i1 As Integer
Dim i2 As Integer
Dim i3 As Integer

For i1 = 11 To 18
For i2 = i1 + 1 To 19
For i3 = i2 + 1 To 20
Range("A1:A203") = .Range(Cells("1", i1), _
Cells("203", i1)).Value
Range("B1:B203") = .Range(Cells("1", i2), _
Cells("203", i2)).Value
Range("C1:C203") = .Range(Cells("1", i3), _
Cells("203", i3)).Value
Next i3
Next i2
Next i1
End Sub

Can this be done in another way , useing hide - unhide method ?
I mean , let's be a block of data in a range ( from column 11
to column 20 ) ; can hide - unhide to do the exact result from
previous macro , so , all the time to be no more then 3 columns ?
In every step , must to be hide 7 columns .

I'd like very much and it's very usefull for me to get know if this
thing can be possible useing hide - unhide .

Thank you very much for your time and knowledge share !