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I'm trying to adopt the Application.GetOpenFilename method, so I can let go of the dependency for comdlg32.ocx, which is not included in Vista. However, I haven't found a way to have GetOpenFilename start with a default filename. Starting in a given directory works (if I call it before calling GetOpenFilename), but I wonder if it's possible to have the dialog box open with a default filename in that directory? That is, when the dialog opens (in the given directory), the default file should be pre-selected. Is that possible?
Gustaf |
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