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#1
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Hi,
I was wondering instead of If Range("F65") 0 Then Range so and so .printount I was wondering if there's any way I can get this line to apply strictly to numeric results, because currently code sees the text results also as greater than zero ( 0 ) ?? |
#2
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Dear Gerard
You can try this. Post back incase of any queries.. If Cint("0" & Range("F65")) 0 If this post helps click Yes --------------- Jacob Skaria |
#3
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Hi Jpcob,
I got a syntax error?? "Jacob Skaria" wrote in message ... Dear Gerard You can try this. Post back incase of any queries.. If Cint("0" & Range("F65")) 0 If this post helps click Yes --------------- Jacob Skaria |
#4
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This is the code I am working with
If Range ("F65") 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 Else The Problem is that when F65 = "NOT BALANCED !" I don't want it to print. Currently it does. When I replaced first line to this If CInt("0" & Range("F65")) 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 I got a Type Mismatched Error. The whole code is highlighted "Jacob Skaria" wrote in message ... Dear Gerard You can try this. Post back incase of any queries.. If Cint("0" & Range("F65")) 0 If this post helps click Yes --------------- Jacob Skaria |
#5
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Sorry Gerard. I didnt notice the text part..As the other post says you will
need to use IsNumeric function....Cheers "Gerard Sanchez" wrote: This is the code I am working with If Range ("F65") 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 Else The Problem is that when F65 = "NOT BALANCED !" I don't want it to print. Currently it does. When I replaced first line to this If CInt("0" & Range("F65")) 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 I got a Type Mismatched Error. The whole code is highlighted "Jacob Skaria" wrote in message ... Dear Gerard You can try this. Post back incase of any queries.. If Cint("0" & Range("F65")) 0 If this post helps click Yes --------------- Jacob Skaria |
#6
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![]() That's okay. Cheers! "Jacob Skaria" wrote in message ... Sorry Gerard. I didnt notice the text part..As the other post says you will need to use IsNumeric function....Cheers "Gerard Sanchez" wrote: This is the code I am working with If Range ("F65") 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 Else The Problem is that when F65 = "NOT BALANCED !" I don't want it to print. Currently it does. When I replaced first line to this If CInt("0" & Range("F65")) 0 And _ Range("G59") < "SELECT CUSTOMER" And _ Range("F64") < "SELECT USER" And _ WorksheetFunction.CountA(Range("C61"), _ Range("C62"), Range("F61"), Range("F62"), _ Range("I61"), Range("I62")) = 1 Then Range("A18:I69").PrintOut Copies:=1 I got a Type Mismatched Error. The whole code is highlighted "Jacob Skaria" wrote in message ... Dear Gerard You can try this. Post back incase of any queries.. If Cint("0" & Range("F65")) 0 If this post helps click Yes --------------- Jacob Skaria |
#7
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![]() If Isnumeric(Range("F65"))=true and Range("F65") 0 then blablablablalba "Gerard Sanchez" wrote: Hi, I was wondering instead of If Range("F65") 0 Then Range so and so .printount I was wondering if there's any way I can get this line to apply strictly to numeric results, because currently code sees the text results also as greater than zero ( 0 ) ?? |
#8
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This did the trick!
Thanks :) "filo666" wrote in message ... If Isnumeric(Range("F65"))=true and Range("F65") 0 then blablablablalba "Gerard Sanchez" wrote: Hi, I was wondering instead of If Range("F65") 0 Then Range so and so .printount I was wondering if there's any way I can get this line to apply strictly to numeric results, because currently code sees the text results also as greater than zero ( 0 ) ?? |
#9
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Gerard
Before using isnumeric see this thread. You could be surprised. http://tinyurl.com/9to4ka Gord Dibben MS Excel MVP On Mon, 16 Mar 2009 00:07:09 -0700, "Gerard Sanchez" wrote: This did the trick! Thanks :) "filo666" wrote in message ... If Isnumeric(Range("F65"))=true and Range("F65") 0 then blablablablalba "Gerard Sanchez" wrote: Hi, I was wondering instead of If Range("F65") 0 Then Range so and so .printount I was wondering if there's any way I can get this line to apply strictly to numeric results, because currently code sees the text results also as greater than zero ( 0 ) ?? |
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