array values not matching
I am trying to use an array to change a column number, based on the
array values. However, the variable (colnum) remains starts at 0, then 1, etc. instead of 2,6,8,10,12: Dim c As Range Dim colnumarr As Variant Dim colnum As Integer colnumarr = Array(2, 6, 8, 10, 12) For colnum = LBound(colnumarr) To UBound (colnumarr) For Each c In Range(tlcapscell, blcapscell).Offset(0, colnum) c.Value = UCase(c.Value) Next Next Thanks... |
array values not matching
You have probably figured it out by now. The LBound and UBound of your array
run from 0 To to the index count - 1. In your case 0 To 5. To get the values of each index number in the arrary you can use colnumarr(0) for a value of 2, colnumarr(1) for a value of 4, etc. "Steve" wrote: I am trying to use an array to change a column number, based on the array values. However, the variable (colnum) remains starts at 0, then 1, etc. instead of 2,6,8,10,12: Dim c As Range Dim colnumarr As Variant Dim colnum As Integer colnumarr = Array(2, 6, 8, 10, 12) For colnum = LBound(colnumarr) To UBound (colnumarr) For Each c In Range(tlcapscell, blcapscell).Offset(0, colnum) c.Value = UCase(c.Value) Next Next Thanks... |
array values not matching
For Each c In Range(tlcapscell,blcapscell).Offset(0, colnumarr(colnum))
Steve wrote: I am trying to use an array to change a column number, based on the array values. However, the variable (colnum) remains starts at 0, then 1, etc. instead of 2,6,8,10,12: Dim c As Range Dim colnumarr As Variant Dim colnum As Integer colnumarr = Array(2, 6, 8, 10, 12) For colnum = LBound(colnumarr) To UBound (colnumarr) For Each c In Range(tlcapscell, blcapscell).Offset(0, colnum) c.Value = UCase(c.Value) Next Next Thanks... -- Dave Peterson |
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