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Simple line error msg
Hi everyone,
one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you, |
Simple line error msg
If the path and file exists then the code line is correct. Are you
assigning this to a object? If so use Set wbkNew = Workbooks.Open ("G:\ReportFiles\ReportTemplate.xls") -- Regards, Nigel "James8309" wrote in message ... Hi everyone, one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you, |
Simple line error msg
On Jul 1, 3:55*pm, "Nigel" wrote:
If the path and file exists then the code line is correct. *Are you assigning this to a object? If so use Set wbkNew = *Workbooks.Open ("G:\ReportFiles\ReportTemplate.xls") -- Regards, Nigel "James8309" wrote in message ... Hi everyone, one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you,- Hide quoted text - - Show quoted text - Directory is there, file is there, It even opens up when I execute the macro but after opening the file, it returns the same error. Even if I use your code it creates an error. When I click debug to see where the error occured, it is the same line. Is this because of the excel file that I am trying to open ? I am only doing this because I have a seperate macro that need to be done in :="G:\ReportFiles\ReportTemplate.xls" Is there anyway I can run the macro from other workbook in the current workbook? if I do "Application.Run "ReportTemplate.xls'!Macro_B" will it work? |
Simple line error msg
Did you create any subroutines/functions called Open?
Did you name any of your modules Open? James8309 wrote: Hi everyone, one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you, -- Dave Peterson |
Simple line error msg
On Jul 1, 9:53*pm, Dave Peterson wrote:
Did you create any subroutines/functions called Open? Did you name any of your modules Open? James8309 wrote: Hi everyone, one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you, -- Dave Peterson Nope :( |
Simple line error msg
Sorry, I don't have another guess.
Does the code work in a brand new workbook's project? I bet it does, so there's something bad going on in that original workbook. James8309 wrote: On Jul 1, 9:53 pm, Dave Peterson wrote: Did you create any subroutines/functions called Open? Did you name any of your modules Open? James8309 wrote: Hi everyone, one of my line in my VBA code is ; Workbooks.Open Filename:="G:\ReportFiles\ReportTemplate.xls" and I do not understand why this line creates "Invalid Procedure call or argument" Please help thank you, -- Dave Peterson Nope :( -- Dave Peterson |
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