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Replace last three characters
Hiya! i was wondering if there was a way to replace just the last three
characters in a cell? example i have 123456000 i would like to have instead of the 000 a 959 so it would be 123456959? any ideas? -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...mming/200802/1 |
Replace last three characters
try the replace function. Use use the formula helper box for the context.
=Replace() "Phillips via OfficeKB.com" wrote: Hiya! i was wondering if there was a way to replace just the last three characters in a cell? example i have 123456000 i would like to have instead of the 000 a 959 so it would be 123456959? any ideas? -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...mming/200802/1 |
Replace last three characters
On Tue, 12 Feb 2008 16:24:05 GMT, "Phillips via OfficeKB.com" <u27679@uwe
wrote: Hiya! i was wondering if there was a way to replace just the last three characters in a cell? example i have 123456000 i would like to have instead of the 000 a 959 so it would be 123456959? any ideas? =REPLACE(A1,LEN(A1)-2,3,959) This returns a text string, so you may want to precede it with a double unary to convert it back to a number: =--REPLACE(A1,LEN(A1)-2,3,959) If the values are always numbers, you could use this: =INT(A1/1000)*1000+959 --ron |
Replace last three characters
thanks!!!
Ron Rosenfeld wrote: Hiya! i was wondering if there was a way to replace just the last three characters in a cell? example i have 123456000 i would like to have instead of the 000 a 959 so it would be 123456959? any ideas? =REPLACE(A1,LEN(A1)-2,3,959) This returns a text string, so you may want to precede it with a double unary to convert it back to a number: =--REPLACE(A1,LEN(A1)-2,3,959) If the values are always numbers, you could use this: =INT(A1/1000)*1000+959 --ron -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...mming/200802/1 |
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