Copy actual URL from hyperlink cell
I have a spreadsheet with thousands of records. One column contains
hyperlinks either created manually using the Insert-Hyperlink action or via a =HYPERLINK() dynamic formula. I need to return the URL for the cyperlink column into another column so that I can use it for some other purpose. The new cells would simply contain text like http://website/folder/file.htm. I couldn't find a function that returned the URL, so I'm wondering if there is another way to get the info? A macro possibly? Thanks for your help IAN |
Copy actual URL from hyperlink cell
Ian
Not sure if I understand, but the code below will iterate a pre-selected range and if there is a hyperlink will place it's address 2 columns to the right (change as necessary) Sub MoveHyper() Dim myCell As Range Dim hyLink As Hyperlink For Each myCell In Selection If myCell.Hyperlinks.Count 0 Then Set hyLink = myCell.Hyperlinks(1) myCell.Offset(0, 2).Hyperlinks.Add myCell.Offset(0, 2), hyLink.Address Set hyLink = Nothing End If Next myCell End Sub -- HTH Nick Hodge Microsoft MVP - Excel Southampton, England DTHIS web: www.nickhodge.co.uk blog (non tech): www.nickhodge.co.uk/blog "IAN" wrote in message ups.com... I have a spreadsheet with thousands of records. One column contains hyperlinks either created manually using the Insert-Hyperlink action or via a =HYPERLINK() dynamic formula. I need to return the URL for the cyperlink column into another column so that I can use it for some other purpose. The new cells would simply contain text like http://website/folder/file.htm. I couldn't find a function that returned the URL, so I'm wondering if there is another way to get the info? A macro possibly? Thanks for your help IAN |
Copy actual URL from hyperlink cell
Hello Ian
You don't say whether you actually want the other column to show URL value as hyperlink? Anyway amend this code and try and see if it suits your needs: Sub PlaceUrls() Dim rg As Range For Each rg In Range("C1:C10") If rg.Hyperlinks.Count < 0 Then rg.Offset(0, 1).Value = rg.Hyperlinks(1).Address End If Next rg End Sub HTH Cordially Pascal "IAN" a écrit dans le message de news: ... I have a spreadsheet with thousands of records. One column contains hyperlinks either created manually using the Insert-Hyperlink action or via a =HYPERLINK() dynamic formula. I need to return the URL for the cyperlink column into another column so that I can use it for some other purpose. The new cells would simply contain text like http://website/folder/file.htm. I couldn't find a function that returned the URL, so I'm wondering if there is another way to get the info? A macro possibly? Thanks for your help IAN |
Copy actual URL from hyperlink cell
Here is a function to put in the other column. Will handle both Inserted
hyperlinks and SIMPLE hyperlink functions: Function hyp(r As Range) As String Dim s As String If r.HasFormula Then s = r.Formula MsgBox (s) s_array = Split(s, Chr(34)) hyp = s_array(1) Else hyp = r.Hyperlinks(1).Address End If End Function -- Gary''s Student - gsnu200749 "IAN" wrote: I have a spreadsheet with thousands of records. One column contains hyperlinks either created manually using the Insert-Hyperlink action or via a =HYPERLINK() dynamic formula. I need to return the URL for the cyperlink column into another column so that I can use it for some other purpose. The new cells would simply contain text like http://website/folder/file.htm. I couldn't find a function that returned the URL, so I'm wondering if there is another way to get the info? A macro possibly? Thanks for your help IAN |
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