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Define variable from cell to open a file
Try this...
Dim strFileName as String strFileName = Range("B1").Value Workbooks.Open Filename:="V:\FTP Data\" & strFileName Note - Don't declare a variable FileName as that is a reserved word(ish). -- HTH... Jim Thomlinson "Amir" wrote: I have it calling B1 "Amir" wrote: I am trying to open a file that has a date in its name. EX Data-20070816.csv I have the user input the date in one cell (a1) and have a string formula in another cell (b1). I keep getting an error when I try to define the variable. Windows("Data Comparison.xls").Activate Application.Run "BLPLinkReset" Sheets("Sheet1").Select Dim Filename As String Set Filename = Range("B1").Select Workbooks.Open Filename:="V:\FTP Data\(Filename)" |
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