column count
just curious:
is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
You can use .column with cells
These formats also work a = Range("A3:A7").Count Returns 5 b = Range(Cells(1, 1), Cells(3, 3)).Count Returns 9 "Gary Keramidas" wrote: just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
? columns("K").Resize(,60).count
60 ? Range(columns(11),columns(11+59)).count 60 -- Regards, Tom Ogilvy "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
got it, thanks
-- Gary "Joel" wrote in message ... You can use .column with cells These formats also work a = Range("A3:A7").Count Returns 5 b = Range(Cells(1, 1), Cells(3, 3)).Count Returns 9 "Gary Keramidas" wrote: just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
thanks, to, i knew there was a way, just couldn't remember to use range.
-- Gary "Tom Ogilvy" wrote in message ... ? columns("K").Resize(,60).count 60 ? Range(columns(11),columns(11+59)).count 60 -- Regards, Tom Ogilvy "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
Gary,
Maybe I'm missing something, but if you already have the column numbers, why can't you just subtract one from the other to get number of columns? E.g., Function NumCols(Col1 As Long, Col2 As Long) NumCols = Abs(Col1 - Col2) + 1 End Function -- Cordially, Chip Pearson Microsoft MVP - Excel Pearson Software Consulting, LLC www.cpearson.com (email address is on the web site) "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
column count
yes, chip, i thought of that a little bit ago. thanks for pointing that out, too. -- Gary "Chip Pearson" wrote in message ... Gary, Maybe I'm missing something, but if you already have the column numbers, why can't you just subtract one from the other to get number of columns? E.g., Function NumCols(Col1 As Long, Col2 As Long) NumCols = Abs(Col1 - Col2) + 1 End Function -- Cordially, Chip Pearson Microsoft MVP - Excel Pearson Software Consulting, LLC www.cpearson.com (email address is on the web site) "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... just curious: is there a way to get the number of columns using column numbers instead of letters? columns("K:BR").count returns 60 but i'd like to use the column numbers instead. -- Gary |
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