![]() |
countif again sorry
Sorry, Im not thinking my questions through proply and missing bits of.
Ok if I have in range a1:a13 the letters H or S, doesnt matter on order or how many of each. Then in b1:b13 I have numbers 1 through to 13. Is it possible to count how many in b1:b13 are greater that 3 if a1:a13 = S. For instance a1 = h b1 = 5 a2 =s b2 = 1 a3 = s b3 = 4 a4 = h b4 = 10 etc therefore only 1 meets my criteria. Id like ti use a worksheet function if possible. Regards Robert |
countif again sorry
i'm no sumproduct expert like bob p, but i'll take a stab
give this a try =SUMPRODUCT(-(A1:A4="s"),-(B1:B43),B1:B4) -- Gary "RobcPettit" wrote in message ps.com... Sorry, Im not thinking my questions through proply and missing bits of. Ok if I have in range a1:a13 the letters H or S, doesnt matter on order or how many of each. Then in b1:b13 I have numbers 1 through to 13. Is it possible to count how many in b1:b13 are greater that 3 if a1:a13 = S. For instance a1 = h b1 = 5 a2 =s b2 = 1 a3 = s b3 = 4 a4 = h b4 = 10 etc therefore only 1 meets my criteria. Id like ti use a worksheet function if possible. Regards Robert |
countif again sorry
Thankyou for your reply. I added your formula and when i deleted the
last part b1:b4 it worked perfect. Regards Robert Gary Keramidas wrote: i'm no sumproduct expert like bob p, but i'll take a stab give this a try =SUMPRODUCT(-(A1:A4="s"),-(B1:B43),B1:B4) -- Gary "RobcPettit" wrote in message ps.com... Sorry, Im not thinking my questions through proply and missing bits of. Ok if I have in range a1:a13 the letters H or S, doesnt matter on order or how many of each. Then in b1:b13 I have numbers 1 through to 13. Is it possible to count how many in b1:b13 are greater that 3 if a1:a13 = S. For instance a1 = h b1 = 5 a2 =s b2 = 1 a3 = s b3 = 4 a4 = h b4 = 10 etc therefore only 1 meets my criteria. Id like ti use a worksheet function if possible. Regards Robert |
All times are GMT +1. The time now is 07:04 AM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com